Rudolf:

I'm new to comp.lang.c and have a question regarding a function that
I'm testing: void * memcpy_rom ( void *s1, const void *s2, size_t n)
/*
=A0 Description
=A0 =A0 Copy n bytes of memory from s2 to s1.
=A0 =A0 =A0 Destination: =A0 s1
=A0 =A0 =A0 Source: =A0 =A0 =A0 =A0 s2
=A0 =A0 =A0 size in bytes: n
*/

I'd suggest you use descriptive names, like dest and src.

My testing program that I am using allows me to set up the values to
the input parameters, which I do.
The input parameters that I for s2 is: abcde
The input parameter that I enter for s1 is: xxx
The input parameter that I enter for n is: 4

According to me what it should do is to simply copy 4 bytes, thus
"abcd" from s2 to s1. s1 should now have an expected value of abcd and
the function should return a pointer to s1.

This is not what happens.
It gives me a error and tells me that it expects s1 to be "bcde"

Question: Is there something about this function I'm not aware of?

You didn't post the code.

The standard library has a function called "memcpy" that does exactly
what you're trying to do. It could be implemented as so:

#include <stddef.h> =A0 =A0/* size_t */

void *memcpy(void *const dest,void const *const src,size_t len)
{
=A0 =A0 char unsigned *pdest =3D dest, *psrc =3D src;

=A0 =A0 while (len--) *pdest++ =3D *psrc++;

=A0 =A0 return dest;

}

char const hello[] =3D "Hello";

int main(void)
{
=A0 =A0 char buf[12];

=A0 =A0 memcpy(buf,hello,sizeof hello);

=A0 =A0 return 0;

}

--
Tom=E1s =D3 h=C9ilidhe

Rudolf:

I'm new to comp.lang.c and have a question regarding a function that
I'm testing: void * memcpy_rom ( void *s1, const void *s2, size_t n)
/*
Description
Copy n bytes of memory from s2 to s1.
Destination: s1
Source: s2
size in bytes: n
*/

I'd suggest you use descriptive names, like dest and src.