| Topic: |
Science > Physics |
| User: |
"Gagan" |
| Date: |
29 Jan 2005 12:14:11 PM |
| Object: |
A ques on mechanics |
A ball of mass 1 kg is attached to an inextensible string.the ball is
released from the position shown. find the impulse imparted by the
string to the ball after the string becomes taut.
__________
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| O
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|_____| from this pt the height of mass is one m
Where there is a capital O the mass is attached.
This is the best idea of a fig i can give you.
Now when the string will become taut it will have a velocity of square
root of 40(g = 10).
But What next to do is what i cant understand.
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| User: "Fool Name " |
|
| Title: Re: A ques on mechanics |
29 Jan 2005 01:14:05 PM |
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On 29 Jan 2005 10:14:11 -0800, (Gagan) wrote:
A ball of mass 1 kg is attached to an inextensible string.the ball is
released from the position shown. find the impulse imparted by the
string to the ball after the string becomes taut.
__________
|
|
|
| O
| |
|_____| from this pt the height of mass is one m
Where there is a capital O the mass is attached.
This is the best idea of a fig i can give you.
Now when the string will become taut it will have a velocity of square
root of 40(g = 10).
But What next to do is what i cant understand.
I can only guess :-)
The ball will fall 2 meters.
v = SQRT(2*g*h) = SQRT( 2 * 10 * 2) = SQRT(40)
Hey, I got that right!
The impulse of a body is the product of his mass and his velocity.
The unit of an impule is (one) [kg * m / sec ] = (1) Newtonsecond [Ns]
So, how many Nsec do we get?
The "impulse" is, what Mother Nature wants to
always keep constant.
w.
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| User: "John C. Polasek" |
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| Title: Re: A ques on mechanics |
29 Jan 2005 01:01:10 PM |
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On 29 Jan 2005 10:14:11 -0800, (Gagan) wrote:
A ball of mass 1 kg is attached to an inextensible string.the ball is
released from the position shown. find the impulse imparted by the
string to the ball after the string becomes taut.
__________
|
|
|
| O
| |
|_____| from this pt the height of mass is one m
Where there is a capital O the mass is attached.
This is the best idea of a fig i can give you.
Now when the string will become taut it will have a velocity of square
root of 40(g = 10).
But What next to do is what i cant understand.
Maybe you don't know what an impulse is. It's
I = FT = MV
in kg m/s or Newton seconds.
John Polasek
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