AC=Alternating DC, Dimwit.



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Topic: Science > Physics
User: "brian a m stuckless"
Date: 16 Feb 2006 02:02:41 AM
Object: AC=Alternating DC, Dimwit.
$$ Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
```Brian.
PD wrote: > >
wrote: > > PD wrote:

For example, electrons carry charge and electromagnetic
radiation does not; both carry energy and momentum. Thus,
we know that electromagnetic radiation is not carried by
electrons because no *charge* is carried away from the
source, though momentum and energy most certainly are.

$$ Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
```Brian.

PD > >

1. How is it determined that no charge is carried away?


Lots of ways. An ammeter would measure the charge carried away
as a DC (not AC) current.

$$ AC current is an Alternating DC current, Dimwit. ```Brian.

-=- There is no DC current measured in a radio antenna.


2. An electron traveling in a wire generates an EM wave
perpendicular to its direction....does a photon alos generate
an EM wave perpendicular to its direction???


No. Remember: light (EM radiation) has both particle and wave
aspects.

$$ Technically, "light" AND "heat" ARE "..the same thing", idiot.

EM radiation, photons, they are all labels for *the same thing*.

So when you make a statement like "does a photon also generate an EM
wave," you're asking whether light generates light. The answer to that
is no.

(I think I read it has a magnetic
field (EM)perpendicular to its direction....which is strange
since the photon itself is an EM wave)

Re: Questions about radiation and em waves
Re: Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
Re: AC=Alternating DC, Dimwit.
.


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