On Mar 14, 8:04 am, Richard Herring <junk@[127.0.0.1]> wrote:

In message <1173740454.743859.276...@v33g2000cwv.googlegroups.com>,
"rayoha...@yahoo.com.ar" <juanp...@gmail.com> writes

On Mar 12, 10:42 am, "Douglas Eagleson" <eaglesondoug...@yahoo.com>
wrote:

[...]

Hey, MY answer is rignt. A graph is a topology.

And the six Long lines defined in topology are dividable into 12 rays
each defining a geometric line. A ray is the half long line defined by
the ray starting at the center of the circle set.

An intersection as the number was used, but it fails to account for
size!
A size of geometric infinity relative to topologic infinity.

sorry ... may be you are right ... but I don't understand you ...

Don't worry. *Nobody* understands Eagleson.

http://groups.google.com/groups?as_uauthors=douglas+eagleson

you are talking about a curved space ?? maybe you may post a link to a
picture
using some filesharing service ...

http://llef.tripod.com/FirstLinear.jpg

--
Richard Herring

It is another topic, but th epicture of the generalized first order
differential equations device is a fairly importent topic.

What I wrote is a requirment for the reader to infer the definiton of
a certain symbol based on the meaning of index. What does the index do
in the General Equation?

And to clarify, the the odd symbol matrix allows usage in a profouund
fashion.

N- means number
A- means rate
C- means total number

So it can solve for these three items!!! It is a very versitile
equattion where used like the matrix says.

The top row indicate the transform to cause the symbol to apply. And
the symbol inference is the relation of triangle line symbol on th
eleft to the symbol on the top row.

It should only take a minute to infer. It is another IQ test.

On Mar 14, 9:28 am, "Douglas Eagleson" <eaglesondoug...@yahoo.com>
wrote:

On Mar 12, 7:00 pm, "rayoha...@yahoo.com.ar" <juanp...@gmail.com>
wrote:

On Mar 12, 10:42 am, "Douglas Eagleson" <eaglesondoug...@yahoo.com>
wrote:

On Mar 12, 8:35 am, "rayoha...@yahoo.com.ar" <juanp...@gmail.com>
wrote:

On Mar 10, 2:18 am, "Jim Black" <trams...@yahoo.com> wrote:

On Mar 9, 5:34 pm, "rayoha...@yahoo.com.ar" <juanp...@gmail.com>
wrote:

you must to find a graph where 25 points are set in such a wa=

forms
(only) 12 stright lines each one with 5 points ...

a hint : for example a 5 x 5 square doesnt work, because alto=

are 5 horizontal lines of 5
points, plus 5 vertical lines with 5 points, and plus 2 diago=

lines with 5 points, that is
a total of 12 lines of 5 points, there are also lines of 4 po=

etc ... so t doesn=B4t work ...

wich is the solution graph ??

If I read you correctly, your conditions are:

1. The graph consists of 25 points and 12 straight lines.
2. Each line in the graph passes through exactly 5 of the point=

the graph.
3. For every pair of points in the graph, there is a line in th=

that passes through both of them.

Let N be the number of pairs (P,l) of points and lines in the g=

such that the point P is on the line l.

To illustrate what I mean, I will calculate N for the 2 x 2 squ=

depicted below:

Q a R
o-------o
|\ /|
| \e f/ |
| \ / |
b | X | c
| / \ |
| / \ |
|/ \|
o-------o
S d T

[You may need to copy the diagram above to a text editor and ch=

the font to a fixed-width font such as Courier to read it.]

Above, Q, R, S, and T are points. The lines are a, b, c, d, e,=

I make a chart showing which lines intersect which points:

a b c d e f
Q X X X
R X X X
S X X X
T X X X

If we count up the number of X's in the table, we find N =3D 12.

Now, back to the original problem.

The problem specifies that there are 12 lines, each line of whi=

through 5 points. That implies N =3D 60.

Select one of the points. Call it A. Each line passing throug=

contains 4 points other than A. Note that every point other th=

must be connected to A by some line. Also, it is impossible fo=

lines through A to share a point other than A, because that wou=

them the same line. Since there are 24 points other than A, th=

must be 6 lines through A.

Since the above is valid for any point chosen, each point has 6=

passing through it. This implies N =3D 150.

This contradiction shows that your problem has no solution, unl=

made a mistake or misunderstood you.

I have set the Followup-To header to request that replies be se=

sci.math.

--
Jim E. Black

Jim ... your answer seems to be right ... thanks very much for yo=

help ...

best regards

juan- Hide quoted text -

- Show quoted text -

Hey, MY answer is rignt. A graph is a topology.

And the six Long lines defined in topology are dividable into 12 ra=

each defining a geometric line. A ray is the half long line defined=

the ray starting at the center of the circle set.

An intersection as the number was used, but it fails to account for
size!
A size of geometric infinity relative to topologic infinity.

sorry ... may be you are right ... but I don't understand you ...

you are talking about a curved space ?? maybe you may post a link to a
picture
using some filesharing service ...

best regards

juan- Hide quoted text -

- Show quoted text -

Try going to teh first set of art images at my art website

the first image, in set 1, is a graph.

http://www.angelfire.com/md3/dougeagleson

It has one point, five circles, 12 rays. A set of points in any
arraingment make a graph. A basic idea is to make the set the most
dimensionless, i.e. the fewest triangles? I is hard like that, I
think.

Graphs stink, and a basic topology is the correct interpretation.- Hide=

- Show quoted text -

I was trying to remember why I heard that a ray in tolopoogy causes a
full line in geometric space.

A space as the cause is the toplogic space. And the cause to a line
must be all one dimensional effect. A point is locatable, but a
second point has no reference in relation. A cause to the origin as
location itself is undedfinable in topology. Ergo, two origins are
made for the two attmepts.

So it is some implication of the cause to distance. That is as far as
i can defend.
It is weird topology.

A homeomorphism appears to make the function equate geometric shapes.
A pair of points has a homeomorphisim. What is it? That is a real
interesting question. BUt points you to the topic that makes topology
very difficult because geometric analogy fails. Intuition fails.- Hide qu=

- Show quoted text -