| Topic: |
Science > Physics |
| User: |
"rookie7799" |
| Date: |
11 Feb 2005 01:35:08 AM |
| Object: |
calculating forces |
hello everyone,
i have one box inside another box
I was wondering, if I place those on some vehicle is possible to
calculate the force at which box B that is inside pushes on the other
box A, obviously in oposite direction
thanks
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| User: "CWatters" |
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| Title: Re: calculating forces |
11 Feb 2005 03:16:06 AM |
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"rookie7799" <pavelbaranov@gmail-dot-com.no-spam.invalid> wrote in message
news:420c602c$1_2@127.0.0.1...
hello everyone,
i have one box inside another box
I was wondering, if I place those on some vehicle is possible to
calculate the force at which box B that is inside pushes on the other
box A, obviously in oposite direction
No horizontal force unless the vehicle is accelerating then it's just f=ma.
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| User: "Maarten van Reeuwijk" |
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| Title: Re: calculating forces |
23 Feb 2005 02:31:24 AM |
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rookie7799 wrote:
hello everyone,
i have one box inside another box
I was wondering, if I place those on some vehicle is possible to
calculate the force at which box B that is inside pushes on the other
box A, obviously in oposite direction.
When the car accelerates, and the boxes don't slide, the whole system can be
regarded as a rigid body with acceleration a. The force corresponding to
this is Ft = mt * a (mt is total mass). When we look at the interface
between box A and B, the total force that is needed to prevent sliding must
be FB = mB * a (mB is mass of box B) or if you wish FB = mB / mt * Ft. The
action force from box A onto box B produces its acceleration, and the
equally large reaction force of B onto A produces a shear stress inside box
A. You are right that this (reaction force) is in the opposite direction as
the acceleration.
HTH Maarten
thanks
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Maarten van Reeuwijk Thermal and Fluids Sciences
Phd student dept. of Multiscale Physics
www.ws.tn.tudelft.nl Delft University of Technology
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