I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document. The main
argument against this invention is that it is too difficult to get

object into the tube. This is wrong. It is actually fairly simple
and it requires very little energy. In my original post I explained
how to get the object into the tube in the last paragraph. However,
in this posting it is in the sixth paragraph.

There should be a wall (which I will call the "front door") separating
the compartment and the tube. The compartment will also have a "back
door". This is how it would work: First, the ball is put into the
compartment through the back door. Then, the back door is closed and
water is allowed to fill up the compartment. When it is full of
water, the front door opens. Giving the ball a little nudge should
allow the ball to enter the tube. When the ball has exited the
compartment, the front door will close and some of the water in the
compartment will be drained.

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document.

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document.

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document. The main
argument against this invention is that it is too difficult to get the
object into the tube. This is wrong. It is actually fairly simple
and it requires very little energy. In my original post I explained
how to get the object into the tube in the last paragraph. However,
in this posting it is in the sixth paragraph.

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document. The main
argument against this invention is that it is too difficult to get the
object into the tube. This is wrong. It is actually fairly simple
and it requires very little energy. In my original post I explained
how to get the object into the tube in the last paragraph. However,
in this posting it is in the sixth paragraph.

-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
=-=-=-3) The Gravitational-density Dynamo-=-=-=-=-=-=-=-=
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-

Here is the general idea of the Gravitational-density Dynamo:

First, an object (the object could be a liquid) on the ground is
inserted into a tall tube which contains a fluid which is more dense
than the object. Also, the object should be insoluble in the fluid.
(When I first conceived this idea I figured the object would be a log
of wood, and the fluid would be water.) Due to the density
difference, the submerged object is displaced upwards. When the
object reaches the top, it is removed from the tube and is dropped.
Due to the force of gravity, it will fall. The energy of the falling
object will somehow be harnessed to create electricity. Once the
object has reached the ground, it must be reinserted back into the
tube to repeat the process. (Notice that the tube should be as tall
as possible so as to maximize the amount of energy of the object when
it falls.)

In the following paragraphs I will lay out the plans of a way to use
the Gravitational-density Dynamo to create cheap and clean
electricity.

_______________
ramps--> / _ _ _ __ |
/ / / / / / / / |
|*| |*| |*| |*| |
|*| |*| |*| |*| |
tubes--> |*| |*| |*| |*| ----------*---------- <--turbine
|*| |*| |*| |*| |
|*| |*| |*| |*| |
\ \_\ \_\ \_\ \__ |
ramps--> \_______________ |


When I first conceived this idea I thought the object would be a log
of wood. However, logs of wood are unwieldy. So instead we will use
balls of wood. (I'm not sure how exactly to make a ball of wood, but
I'm sure with glue, etc., it can be done.) Since the density of wood
is 680 kg/m^3, a ball of wood that has a mass of 200kg would have a
volume of 300 000 cm^3 and a diameter of 80cm.

Now, this power plant I am designing here will occupy 1kmē of land.
In this space we will have 350 000 tall tubes. Each tube will be 300m
high and will occupy 1mē of ground area. Within each tube will be
water.

The idea is each wooden ball will be inserted into the bottom of a
tube. When the ball surfaces at the top of the tube it will be to the
turbine. When the ball is on the turbine, it will cause the turbine
to rotate. (In the diagram, the turbine would be rotating
anti-clockwise.) When the ball has reached the floor it will be
directed back to the bottom of a tube so that it may re-enter the
cycle.

Now, it is not as difficult as it seems to get the balls to-and-from
the turbine. To get the balls to the turbine is easy; all one needs
to do is give the ball a nudge so that it moves from the top of the
tube to the inclined ramp. Once it is on the ramp, it will simply
roll to the turbine, which of course does not require us to input
energy. One way to get a ball to enter the bottom of a tube is to
have a "compartment" which is attached to the bottom of the tube.
There should be a wall (which I will call the "front door") separating
the compartment and the tube. The compartment will also have a "back
door". This is how it would work: First, the ball is put into the
compartment through the back door. Then, the back door is closed and
water is allowed to fill up the compartment. When it is full of
water, the front door opens. Giving the ball a little nudge should
allow the ball to enter the tube. When the ball has exited the
compartment, the front door will close and some of the water in the
compartment will be drained. Then the back door will open to repeat
the cycle. (This way of getting the ball to enter a tube is similar
to how astronauts go for a space walk; they first enter a compartment
which is then depressurized, and then they are allowed to step out
into space.)

Now, a ball of wood at the top of a tube will have a gravitational
potential energy of 600 000J (GPE = 200kg * 10m/sē * 300m). Assuming
that the ball travels at 1 m/s while it is in the tube rising and the
same speed when it is on the turbine descending, and that it takes
100s in total for the ball to get to-and-from the turbine, we can say
that the ball will take 700s to complete a cycle. Thus, each ball
will give a power just under 1000 Watts (P = 600 000J/700s).

Now, obviously we can have more that one ball in a tube. It's
reasonable to assume that we have 100 balls per tube. This figure
allows a space of 6m between balls, which I figure is sufficient.

Thus, since each ball gives a power of 1000 Watts and we can fill a
tube with 100 balls, we can say that each tube produces 100 000 Watts
(P = 1000W/ball * 100 balls).

Now, since there are 350 000 tubes in the entire power plant and each
tube produces 100 000 Watts of energy, we can produce 35 giga-watts of
electricity (P = 350 000 tubes * 100 000 Watts/tube).

The tubes take up a bit more than a-third of the ground space. The
other two-thirds of the space will be occupied by the turbine, ramps,
etc.

-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-
-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-

by Raheman Velji
rahemanvelji@yahoo.ca

March 13, 2005

you can also view this paper (and updated versions) at...
...http://www.angelfire.com/un/rv

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document.[snip crap]

I am reposting my idea of the gravitational-density dynamo because
most of you did not bother to read the entire document.