| Topic: |
Science > Physics |
| User: |
"thomas fiischer" |
| Date: |
12 Jan 2005 02:54:37 PM |
| Object: |
crossing of sound beams in water |
Hey,
there is a new kind of loudspeacker avaibable, called "Parametric
Loudspeakers".
If you need further information about this technology you go to
american technology corporation and download the whitepaper there is a
lot of information.
In this paper the point out, that the first devices are developed for
underwater communication and sonars.
This means that this effect is in water much more easier to realize
than in air.
Now to my question.
If I have to ultrasound beams with a frequency of 1 MHz and 1,010 MHz
and have the same amplitude and which are crossing in a single point
how big will be the amplitude of the resulting 10kHZ oscillating.
Maybe someone can say me how I can caculate this or even estimate ?
Thomi
.
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| User: "Old Man" |
|
| Title: Re: crossing of sound beams in water |
12 Jan 2005 10:51:47 PM |
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"thomas fiischer" <heino.blatt@gmx.de> wrote in message
news:1cfe2867.0501121254.5e12b6de@posting.google.com...
Hey,
there is a new kind of loudspeacker avaibable, called "Parametric
Loudspeakers".
If you need further information about this technology you go to
american technology corporation and download the whitepaper there is a
lot of information.
In this paper the point out, that the first devices are developed for
underwater communication and sonars.
This means that this effect is in water much more easier to realize
than in air.
Now to my question.
If I have to ultrasound beams with a frequency of 1 MHz and 1,010 MHz
and have the same amplitude and which are crossing in a single point
how big will be the amplitude of the resulting 10kHZ oscillating.
Maybe someone can say me how I can caculate this or even estimate ?
Thomi
You need to exceed Hook's Law for the Medium.
As for a spring, a large amplitude yields non-linearity
between stress and stain. Only one of the sound
waves needs to be of large amplitude.
[Old man]
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| User: "Paul Cardinale" |
|
| Title: Re: crossing of sound beams in water |
12 Jan 2005 06:00:05 PM |
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thomas fiischer wrote:
Hey,
there is a new kind of loudspeacker avaibable, called "Parametric
Loudspeakers".
If you need further information about this technology you go to
american technology corporation and download the whitepaper there is
a
lot of information.
In this paper the point out, that the first devices are developed for
underwater communication and sonars.
This means that this effect is in water much more easier to realize
than in air.
Now to my question.
If I have to ultrasound beams with a frequency of 1 MHz and 1,010 MHz
and have the same amplitude and which are crossing in a single point
how big will be the amplitude of the resulting 10kHZ oscillating.
Maybe someone can say me how I can caculate this or even estimate ?
Thomi
If the medium is linear, the amplitude will be zero. If the medium is
non-linear, the amplitude depends upon the nature of the non-linearity.
Paul Cardinale
.
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