| Topic: |
Science > Physics |
| User: |
"dedanoe" |
| Date: |
19 Aug 2006 07:07:14 AM |
| Object: |
dedanoe's leverian astrophysics |
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow. something trully fishy is going on with these three. i think
that the light follows some curved surface like shown below:
view this one with fixed font:
-----------------
/--<--- --->--\
// \ / \\
|| |X| ||
|V |X| VV Day
Earth S u n Moon -------
^| |X| || Night
|| ^X^ ||
\\ / \ //
\--->-- --<---/
-----------------
the outter circle shows the earth's and the moon's trajectory around
their common center which not necessarily has to be at the center of
the sun (the sun may be undernit or above the earth-moon "plane"):
view this one with fixed font:
S u n
/ \
/ \
/ | \
/ | \
/---->-+------\
// | \\
Moon ----*---Earth
\ /
--------<----
i try to tell you that the earth-moon axis can be normal with the axis
defined with the sun's center and the earth-moon's barycenter. this
means that earth and moon originate from same equilibrium point and
together they are sub-system=sub-lever in the hierarchy of all that
comes from the sun. this also means that the sun is at the same time
the SUPER STAR and the BLACK HOLE in this community. finnally, we see
the moon fully bright, fully dark and partially of them two because of
the same reasons that we have day and night here on earth. they, as a
sub-lever, spin together around their barycenter and their barycenter
spins together with other barycenters or planets around our
black-hole-sun. the black-hole-sun is like an north-south-pole magnet
and when the sun-part seases then the black-hole-part activates and
vice-versa. our black-hole-sun is now partially emissive and absorbtive
but it's heading towards it's sunniest (most emissive) culmination that
is the center of the stellar group 'Hercules'. that is the 11th degree
of CAPRICORN astrologic longitude.
take a look on the updated dedanoe's page:
http://dedanoe.tripod.com/maximum-worp.html
Dobri Karagorgov -- Dedanoe
schizo-paranoid-lever-sex-pert
http://dedanoe.tripod.com
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| User: "Old Man" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 03:09:03 PM |
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"dedanoe" <dedanoe@yahoo.com> wrote in message
news:1155989234.515533.36750@p79g2000cwp.googlegroups.com...
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow. something trully fishy is going on with these three.
Not fishy at all. The plane of the Moon's orbit is tilted WRT
the plane of the ecliptic. At midnight, the moon is usually
above or below the plane of the ecliptic. If the Moon is on
the plane of the ecliptic, there's an eclipse.
[Old Man]
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| User: "Ben Newsam" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 04:41:52 PM |
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On Sat, 19 Aug 2006 15:09:03 -0500, "Old Man" <nomail@nomail.net>
wrote:
"dedanoe" <dedanoe@yahoo.com> wrote in message
news:1155989234.515533.36750@p79g2000cwp.googlegroups.com...
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow. something trully fishy is going on with these three.
Not fishy at all. The plane of the Moon's orbit is tilted WRT
the plane of the ecliptic. At midnight, the moon is usually
above or below the plane of the ecliptic. If the Moon is on
the plane of the ecliptic, there's an eclipse.
Don't tell Lester.
--
Posted via a free Usenet account from http://www.teranews.com
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| User: "Mike" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 04:32:19 PM |
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dedanoe wrote:
ever wondered how the moon,
[snip]
No, nobody wonders about anything having to do with the moon. Possibly
dead-noe is a member of the hollow moon conspiracy cult.
Mike
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| User: "Paul Cardinale" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 12:21:40 PM |
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dedanoe wrote:
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow.
When you see a 'full' moon, the angle between vector1 & vector2 is very
small, but not 0 (i.e. they are not colinear). So the Moon is very
slightly less than full; but it's so close that we can't tell just by
looking that it's not quite full.
Paul Cardinale
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| User: "Ben Newsam" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 01:32:30 PM |
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On 19 Aug 2006 10:21:40 -0700, "Paul Cardinale"
<pcardinale@volcanomail.com> wrote:
dedanoe wrote:
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow.
When you see a 'full' moon, the angle between vector1 & vector2 is very
small, but not 0 (i.e. they are not colinear). So the Moon is very
slightly less than full; but it's so close that we can't tell just by
looking that it's not quite full.
Yes. It should also be remembered that although the moon at its
fullest (assuming it is not so "full" as to be eclipsed) is directly
above somewhere where the time is midnight, that same moon may be seen
at the same time from pretty well everywhere where it is night time.
--
Posted via a free Usenet account from http://www.teranews.com
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| User: "dedanoe" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 01:05:58 PM |
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isn't that insignificant in this case?
isn't the earth's shadow significantly larger?
Paul Cardinale =D0=BD=D0=B0=D0=BF=D0=B8=D1=88=D0=B0:
dedanoe wrote:
ever wondered how the moon, the sun and the earth are constellated so
that you can see the full disk of the moon bright from the earth at
midnight. it seems quite possible as it obviously happens but it's not
that simple. take the vector from the center of the sun towards the
center of the moon as vector1 and the vector from the center of the
earth towards the center of the moon as vector2. to see the moon's disk
fully bright from earth at midnight, the vector1 has to be collinear
with vector2. when it's so then they all three have to be alined -- the
earth between the sun and the moon but then moon falls into earths
shadow.
When you see a 'full' moon, the angle between vector1 & vector2 is very
small, but not 0 (i.e. they are not colinear). So the Moon is very
slightly less than full; but it's so close that we can't tell just by
looking that it's not quite full.
=20
Paul Cardinale
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| User: "Paul Cardinale" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 07:17:01 PM |
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dedanoe wrote:
isn't that insignificant in this case?
isn't the earth's shadow significantly larger?
In the vast majority of full moons, the Moon never passes into the
shadow of the Earth; when it does, that's called a Lunar Eclipse. The
reason that they are uncommon is that the plane of the Moon's orbit
around the Earth is tilted with respect the the plane of the Earth's
orbit around the Sun. Thus it's not very often that all three are in
alignement.
Paul Cardinale
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| User: "Mike" |
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| Title: Re: dedanoe's leverian astrophysics |
20 Aug 2006 10:02:07 AM |
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Paul Cardinale wrote:
The
reason that they are uncommon is that the plane of the Moon's orbit
around the Earth is tilted with respect the the plane of the Earth's
orbit around the Sun.
Indeed. But dead-noe hasn't kept up with progress in astronomy and
orbital mechanics. He still studies levers and epicycles. Maybe the US
should consider donating a whole University to poor FYROM to get them
up to orbital speed, literally.
Mike
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| User: "Aluminium Holocene Holodeck Zoroaster" |
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| Title: Re: dedanoe's leverian astrophysics |
19 Aug 2006 01:10:24 PM |
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that's why lunar eclipses are more common
than solar eclipses (not counting "sunset,"
as Bucky do .-)
also, the penumbra is much larger than the umbra.
isn't the earth's shadow significantly larger?
thus:
<a-hem> I'm not a mathematician;
I'm not a physicist; and so on. anyway,
there are two primary issues: a)
has in fact all of the "knwon matter" been accounted for,
species-wise; b)
the awful prevalence of Einsteinmania in Universe, such that,
now, Universe is not just going away from us, because
of the nascent assertion that the doppler shift is due
to velocity, but it is now running away from us,
faster & faster & faster, thus relagating all *programmes
d'espace* to the ash-heap of science-history; eh?
thus:
what an incentive to attack; at least,
it's clearly labeled as a conjecture. the question is,
is it "ill-pozed?"
http://bfi.org/clinton_equal_central_angle_conjecture
thus:
Chum -- you could attract sharks with mathematicians!
thus:
to be featured in the next movie, "Harry Potter and
the 'Public' Charter Schools: Faith-based Initiatives
in the New Millennium CCE: Come the Rapture,
No Child Left Behind!:"
http://rand.org/news/press.06/08.07.html
--it takes some to jitterbug!
http://members.tripod.com/~american_almanac
http://www.21stcenturysciencetech.com/2006_articles/Amplitude.W05.pdf
http://www.rwgrayprojects.com/synergetics/plates/figs/plate01.html
http://larouchepub.com/other/2006/3322_ethanol_no_science.html
http://www.wlym.com/pdf/iclc/howthenation.pdf
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