Science > Physics > Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997
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Science > Physics |
| User: |
"OsherD" |
| Date: |
08 Jan 2006 09:33:29 PM |
| Object: |
Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
From Osher Doctorow
P. L. Sachdev of Indian Institute of Science, India, in A Compendium on
Nonlinear Ordinary Differential Equations, Wiley: N.Y. 1997, has
several (df/dx)(dg/dx) types with f = g, which is to say (dy/dx)^2 with
a coefficient, for example:
1) y" + f(x, y)(y' )^2 + g(x, y)y' + h(x, y) = 0
The volume includes the Riccati and Painleve PI-PIV equations among
numerous others.
Osher Doctorow
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| User: "Alternaria Alternata" |
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| Title: Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
09 Jan 2006 12:26:17 PM |
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"OsherD" <> wrote in message
news:1136777609.001770.61180@g43g2000cwa.googlegroups.com...
From Osher Doctorow
P. L. Sachdev of Indian Institute of Science, India, in A Compendium on
Nonlinear Ordinary Differential Equations, Wiley: N.Y. 1997, has
several (df/dx)(dg/dx) types with f = g, which is to say (dy/dx)^2 with
a coefficient, for example:
1) y" + f(x, y)(y' )^2 + g(x, y)y' + h(x, y) = 0
That is a degenerate case, f = g
1. it would not be (dy/dx)^2 but (df/dx)(df/dx) or (df/dx) ^ 2
1. Under that logic one could write if f = g = h, then
(df/dx)(dg/dx)(dh/dx) exists or
(dy/dx)^3 Clearly, this is garf.
2. If y = f * g, then (dy/dx) = f * (dg/dx) + g * (df/dx) which is not
what you have.
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| User: "OsherD" |
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| Title: Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
09 Jan 2006 01:27:54 PM |
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From Osher Doctorow
Alternaria Alternata, who has never begun a thread on sci.physics to my
knowledge and whom I haven't seen post to any other threads except one
equally Mediocre claim on a later thread of mine, claims in regard to f
= g in (df/dx)(dg/dx) that:
That is a degenerate case, f = g
He/she/it also claims:
Under that logic one could write if f = g = h, then
(df/dx)(dg/dx)(dh/dx) exists or
(dy/dx)^3 Clearly, this is garf.
To whom, AA (Alcoholics Anonymous?), is f = g "degenerate"? Surely not
to physicists, for whom K.E. = (1/2)mv^2 is very important (v = dx/dt,
etc.). As for the "garf" (a term that seems more at home in
MoveOn.Org and George Soros' vocabulary than here), if f = g = h, then
certainly (df/dx)(dg/dx)(dh/dx) = (df/dx)^3. Have you tried
"sci.physics.kindergarten for spoiled brats?" Do give them a try or,
if they haven't established a website yet (possibly because they're too
busy pushing Jobs over Self-Defense or Self-Defense over Jobs but not
both), establish it yourself - you certainly have the right words for
kindergarten.
Osher Doctorow.
Osher Doctorow
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| User: "Fusarium Graminearum" |
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| Title: Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
09 Jan 2006 01:50:27 PM |
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"OsherD" <> wrote in message
news:1136834874.430649.136940@g14g2000cwa.googlegroups.com...
From Osher Doctorow
Alternaria Alternata, who has never begun a thread on sci.physics to my
knowledge and whom I haven't seen post to any
Poor Thing!
other threads except one
equally Mediocre claim on a later thread of mine, claims in regard to f
= g in (df/dx)(dg/dx) that:
That is a degenerate case, f = g
He/she/it also claims:
Under that logic one could write if f = g = h, then
(df/dx)(dg/dx)(dh/dx) exists or
(dy/dx)^3 Clearly, this is garf.
To whom, AA (Alcoholics Anonymous?), is f = g "degenerate"? Surely not
to physicists, for whom K.E. = (1/2)mv^2
What has K.E. to do with your f = g in (df/dx)(dg/dx) ?
Nothing.
More poo from the garfmaster.
Never heard of "degenerate cases" have you?
It is a term used in math.
is very important (v = dx/dt,
etc.). As for the "garf" (a term that seems more at home in
MoveOn.Org and George Soros' vocabulary than here), if f = g = h, then
certainly (df/dx)(dg/dx)(dh/dx) = (df/dx)^3. Have you tried
"sci.physics.kindergarten for spoiled brats?"
Can't answer the question, can you?
You refer to insults because *you don't know math*.
This is a problem that you can cure with therapy and a good High School
Education.
Do give them a try or,
if they haven't established a website yet (possibly because they're too
busy pushing Jobs over Self-Defense or Self-Defense over Jobs but not
both), establish it yourself.
Your drifting again, over to something about "Jobs over Self-Defense"
whatever that means.
So, what has K.E. to do with your f = g in (df/dx)(dg/dx) anyway?
Osher Doctorow.
Osher Doctorow
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| User: "OsherD" |
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| Title: Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
09 Jan 2006 02:28:12 PM |
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From Osher Doctorow
Fusarium Graminearum, presumably a second nickname of Alternaria
Alternata, typed:
Never heard of "degenerate cases" have you?
It is a term used in math.
This multiple personality Fusarium Graminearum is now hearing things
that weren't stated or typed, like "never heard of 'degenerate cases'
have you," and then proceeding to sow seeds of doubt by "It is a term
used in math," as though explaining what he heard from his own mind in
order to show himself to be superior to himself or herself (my guess is
both).
As for never hearing "Jobs versus Self-Defense," I suppose that Middle
School children and insane assylum inmates haven't heard it. Try
"sci.loonie" or start it up yourself.
Osher Doctorow
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| User: "Fusarium Graminearum" |
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| Title: Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 8: Sachdev 1997 |
09 Jan 2006 03:02:24 PM |
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"OsherD" <> wrote in message
news:1136838492.822371.15610@g44g2000cwa.googlegroups.com...
From Osher Doctorow
Fusarium Graminearum, presumably a second nickname of Alternaria
Alternata, typed:
Never heard of "degenerate cases" have you?
It is a term used in math.
This multiple personality Fusarium Graminearum is now hearing things
that weren't stated or typed, like "never heard of 'degenerate cases'
have you," and then proceeding to sow seeds of doubt by "It is a term
used in math," as though explaining what he heard from his own mind in
order to show himself to be superior to himself or herself (my guess is
both).
Instead of being passive, you could answer the question directly,
I'll put it here,
"Never heard of "degenerate cases" have you?"
But I can see from your response that you do not know about it, verifying my
position on your cretinability.
As for never hearing "Jobs versus Self-Defense," I suppose that Middle
School children and insane assylum inmates haven't heard it.
You must know, posting from a middle school insane assylum.
Try
"sci.loonie" or start it up yourself.
You post there too?
Osher Doctorow
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