| Topic: |
Science > Physics |
| User: |
"Pentcho Valev" |
| Date: |
17 Oct 2006 01:05:48 AM |
| Object: |
EINSTEIN'S HYPNOTISTS PROVE 5=4 |
One of Einstein's crucial discoveries is the fact that, if the quantity
1/gamma = (1-v^2/c^2)^(1/2)
is replaced by its Taylor approximation 1-v^2/2c^2, Einstein's lies
about gravitational time dilation can be camouflaged to some extent. If
Einstein had not made this discovery, that is, if the original quantity
(1-v^2/c^2)^(1/2) had remained unchanged, the malignancy called
relativity theory would not have killed theoretical science (perhaps).
Einstein's hypnotists do know about the crucial discovery and always
replace (1-v^2/c^2)^(1/2) with 1-v^2/2c^2. Consider Problem 3 "Circular
motion", (a) and (b), on p. 15, solution on p. 19, in
http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
In other words, Einstein's theory can only be true if 5=4.
Pentcho Valev
.
|
|
| User: "Surfer" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
18 Oct 2006 12:10:39 AM |
|
|
On 16 Oct 2006 23:05:48 -0700, "Pentcho Valev" <pvalev@yahoo.com>
wrote:
Consider Problem 3 "Circular
motion", (a) and (b), on p. 15, solution on p. 19, in
http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
In other words, Einstein's theory can only be true if 5=4.
Is this inconsistency due to a genuine problem with SR or GR, or is it
due to a misapplication of the two theories?
For example, since they are different theories, is it appropriate to
simultaneously apply them?
What if t_A and t_B were calculated using GR alone?
.
|
|
|
| User: "Sorcerer" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
18 Oct 2006 06:21:47 AM |
|
|
"Surfer" <surfer@no.spam.net> wrote in message
news:p0dbj2196mtktt5738snul30gpshvv5i93@4ax.com...
| On 16 Oct 2006 23:05:48 -0700, "Pentcho Valev" <pvalev@yahoo.com>
| wrote:
|
| >Consider Problem 3 "Circular
| >motion", (a) and (b), on p. 15, solution on p. 19, in
| >
| >http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
| >
| >>From the solution on p. 19 we have
| >
| >(a) t_B = t_A (1-v^2/c^2)^(1/2)
| >
| >(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
| >
| >Accordingly
| >
| >t_A = t_A (1-v^4/c^4)
| >
| >In other words, Einstein's theory can only be true if 5=4.
| >
|
|
| Is this inconsistency due to a genuine problem with SR or GR, or is it
| due to a misapplication of the two theories?
It is due to division-by-zero.
http://www.androcles01.pwp.blueyonder.co.uk/DominoEffect.GIF
http://www.androcles01.pwp.blueyonder.co.uk/2equals1.xls
|
| For example, since they are different theories, is it appropriate to
| simultaneously apply them?
Hahaha!
| What if t_A and t_B were calculated using GR alone?
What if you calculated them instead of expecting someone else to do it for
you?
What if pigs could fly?
What if...
.
|
|
|
|
| User: "Surfer" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
18 Oct 2006 08:33:12 AM |
|
|
On Wed, 18 Oct 2006 14:40:39 +0930, Surfer <surfer@no.spam.net> wrote:
On 16 Oct 2006 23:05:48 -0700, "Pentcho Valev" <pvalev@yahoo.com>
wrote:
Consider Problem 3 "Circular
motion", (a) and (b), on p. 15, solution on p. 19, in
http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
In other words, Einstein's theory can only be true if 5=4.
Is this inconsistency due to a genuine problem with SR or GR, or is it
due to a misapplication of the two theories?
For example, since they are different theories, is it appropriate to
simultaneously apply them?
What if t_A and t_B were calculated using GR alone?
I found the answer here in Example 3
http://en.wikipedia.org/wiki/Proper_time
When the calculations are done this way, an inconsistency does not
occur.
.
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|
|
| User: "" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
18 Oct 2006 09:39:38 AM |
|
|
Pentcho Valev wrote:
One of Einstein's crucial discoveries is the fact that, if the quantity
1/gamma = (1-v^2/c^2)^(1/2)
But, that's not what Einstein discovered,
He discovered that if you only do the
expansion in two dimension, x and t,
you can tell quantum retards to
pack it up, you Euler wannabee
retards.
is replaced by its Taylor approximation 1-v^2/2c^2, Einstein's lies
about gravitational time dilation can be camouflaged to some extent. If
Einstein had not made this discovery, that is, if the original quantity
(1-v^2/c^2)^(1/2) had remained unchanged, the malignancy called
relativity theory would not have killed theoretical science (perhaps).
Einstein's hypnotists do know about the crucial discovery and always
replace (1-v^2/c^2)^(1/2) with 1-v^2/2c^2. Consider Problem 3 "Circular
motion", (a) and (b), on p. 15, solution on p. 19, in
http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
In other words, Einstein's theory can only be true if 5=4.
Pentcho Valev
.
|
|
|
|
| User: "" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
17 Oct 2006 11:30:39 AM |
|
|
Yes. That book is plagued with such inconsistencies.
The exact solution according to a) is tb=ta*sqrt(1-b2)
The exact solution according to b) is tb=ta*1/[ sqrt(1-b2) * (1+b2) ]
Conclusion: a) and b) have different results.
Oh, but if we chop here, approximate there and assume a few other
little things then these results can be made the same!
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
.
|
|
|
| User: "" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
17 Oct 2006 06:15:27 PM |
|
|
wrote:
Yes. That book is plagued with such inconsistencies.
The exact solution according to a) is tb=ta*sqrt(1-b2)
The exact solution according to b) is tb=ta*1/[ sqrt(1-b2) * (1+b2) ]
Conclusion: a) and b) have different results.
Oh, but if we chop here, approximate there and assume a few other
little things then these results can be made the same!
From the solution on p. 19 we have
(a) t_B = t_A (1-v^2/c^2)^(1/2)
(b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
Accordingly
t_A = t_A (1-v^4/c^4)
xxein: Ah, yes. Physics.
.
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|
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|
| User: "Sorcerer" |
|
| Title: Re: EINSTEIN'S HYPNOTISTS PROVE 5=4 |
17 Oct 2006 04:52:12 AM |
|
|
You are a day late and a dollar shy, I've already invented
the relativistic computer.
http://www.androcles01.pwp.blueyonder.co.uk/2equals1.xls
Androcles
"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1161065148.114222.51600@i3g2000cwc.googlegroups.com...
| One of Einstein's crucial discoveries is the fact that, if the quantity
|
| 1/gamma = (1-v^2/c^2)^(1/2)
|
| is replaced by its Taylor approximation 1-v^2/2c^2, Einstein's lies
| about gravitational time dilation can be camouflaged to some extent. If
| Einstein had not made this discovery, that is, if the original quantity
| (1-v^2/c^2)^(1/2) had remained unchanged, the malignancy called
| relativity theory would not have killed theoretical science (perhaps).
|
| Einstein's hypnotists do know about the crucial discovery and always
| replace (1-v^2/c^2)^(1/2) with 1-v^2/2c^2. Consider Problem 3 "Circular
| motion", (a) and (b), on p. 15, solution on p. 19, in
|
| http://www.courses.fas.harvard.edu/~phys16/Textbook/ch13.pdf
|
| >From the solution on p. 19 we have
|
| (a) t_B = t_A (1-v^2/c^2)^(1/2)
|
| (b) t_A = t_B (1-v^2/c^2)^(1/2) (1+v^2/c^2)
|
| Accordingly
|
| t_A = t_A (1-v^4/c^4)
|
| In other words, Einstein's theory can only be true if 5=4.
|
| Pentcho Valev
|
.
|
|
|
|
|
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