| Topic: |
Science > Physics |
| User: |
"OsherD" |
| Date: |
22 Nov 2005 09:41:25 PM |
| Object: |
Energy In The Knowledge Equation |
From Osher Doctorow
COPYRIGHT NOTICE
Energy In The Knowledge Equation
Copyright By Owner Osher Doctorow Ph.D.
First Published 2005
The Knowledge Equation, now including Probability P, is:
1) K^(a+b+c)V^a V^(a+b) PI = L^a T^b M^c F^(a+b) P^d
Let's now put in energy E, at the risk of redundancy:
2) K^(a+b+c)V^a V^(a+b) E^g PI = L^a T^b M^c F^(a+b) P^d
where a, b, c, d, g are variable or constant exponents, PI is usually a
dimensionless constant (but PI can be generalized to a dimensional
constant or even variable).
With proper selection of exponents we can obtain E = mc^2 (c = V), E =
hv for v frequency or E = k/T = kT^(-1) for T period (dimensionally
time), k constant, the various operator expressions for E and kinetic
energy, etc. Notice that in E = hv, h would be (PI)^(-1) and the
dimensions of E are still ML^2 T^(-2) with PI this time dimensional
constant. h is well known to have dimensions ML^2 T^(-1).
Notice that we do not technically require variable M in (2) to get E =
hv, so that although in the photoelectric effect and other scenarios
Einstein and others put E = (1/2)mv^2 = hv2 - hv1 for kinetic energy E,
it would be formally possible from (2) to have a massless energy E =
hv.
Osher Doctorow
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| User: "OsherD" |
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| Title: Re: Energy In The Knowledge Equation |
23 Nov 2005 12:04:54 AM |
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From Osher Doctorow
This reminds me of the fact that we can obtain Hooke's Law:
1) F = kx
by zeroing out all exponents of the Knowledge Equation except 1 on F
and -1 on L, obtaining:
2) PI = FL^(-1)
with L = x and PI = k (constant). Since mass (M) was zeroed out, we
could argue that a spring force is massless in a sense even though a
mass attached to the spring is doing the stretching by being given a
push or pull. In fact, the elastic potential energy P.E. is:
3) P.E. = (1/2)kx^2
which can also be gotten from the Knowledge Equation by zeroing out
everything except E and L (this time L^(-2) and E^1 and PI = 2/k). So
mass was zeroed out for both force and energy.
Similar remarks apply to various other equations of elasticity at least
holding the type of material constant (e.g., iron vs steel vs lead vs
copper).
Osher Doctorow
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