F=-Gmm/r^2 + (1/4*pi*e)qq/r^2 See, that wasn't so tough.



 Science > Physics > F=-Gmm/r^2 + (1/4*pi*e)qq/r^2 See, that wasn't so tough.

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Topic: Science > Physics
User: "doodeedoo"
Date: 05 Sep 2003 08:39:38 PM
Object: F=-Gmm/r^2 + (1/4*pi*e)qq/r^2 See, that wasn't so tough.
I don't see why you guys didn't figure this out already. Sheesh.
.

User: "Uncle Al"

Title: Re: F=-Gmm/r^2 + (1/4*pi*e)qq/r^2 See, that wasn't so tough. 06 Sep 2003 01:08:00 PM
doodeedoo wrote:


I don't see why you guys didn't figure this out already. Sheesh.

Unless the addend is uniformly zero it massively conflicts with all
real world measurements Cavendish balances to Adelberger's recent
quadupole pendulum to the world's most remarkable beam balance,
Science 288(5468) 944 (2000)
Phys. Rev. Lett. 89 161102 (2002)
including all electrostatic measurements. Your proposal is trivally
demonstrated to be *****.
Of course, it would be poor etiquette to merely state the obvious and
let it go at that. Uncle Al cares! here, let him rub your stooopid
face in it: Given any two irrational numbers 'x' and 'y' it is always
possible to find integers j, k, m, n such that |(j)(x^m) - (k)(y^n)| <
epsilon, where "epsilon" is arbitrarily small. One should not be
impressed by such a relationship since one could find an arbitrarily
large number of relationships as good or better by picking any other
irrational number, like the Napierian base 'e', Euler's constant
gamma, the Golden Ratio, any irrational square root, etc.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
"Quis custodiet ipsos custodes?" The Net!
.


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