"Gieniu" <warendag@telus.net> wrote in message
news:743di.28720$vT6.6565@edtnps90...

"The Ghost In The Machine" <ewill@sirius.tg00suus7038.net> wrote in
message news:fh0vj4-7fv.ln1@sirius.tg00suus7038.net...

In sci.physics, Gieniu
<warendag@telus.net>
wrote
on Mon, 04 Jun 2007 20:18:38 GMT
<ys_8i.9$vT6.3@edtnps90>:

"The Ghost In The Machine" <ewill@sirius.tg00suus7038.net> wrote in
message
news:bp3cj4-t5c.ln1@sirius.tg00suus7038.net...

In sci.physics, Gieniu
<warendag@telus.net>
wrote
on Sun, 03 Jun 2007 06:08:45 GMT
<NVs8i.67391$V75.42901@edtnps89>:

Hi
The pumping it is moving of liquid from the lower level ho, to .
higher level h1.
Because this action is in the gravitational field,
therefore is prformed the work W=mg( h1 - h0),
and this work the motopump performs.
The straight tube is plunged deep into ideal liquid,
This tube is open on the both its ends.
On the top of tube is instaled the motopump
and the lower end of tube is open.
By action of the hydrostatic preasure, the liquid

flows into

the tube and into the motopump.
Maximal velocity v of pumped liquid is
v = sqrt ( gH)
Velociti of liquid out of pump is also same
but here there are two different action,
1/ keeping velocity of liquid as constant,
2/ hydrostatic preasure.which creates of
velocity of water equal v=sqrt(gh).
These two action are self-supporting

In order to receive energy E = m vv/2 =mgH/2
WE must give energy E1=mg(h1-h0);
it does the motopump

This work is performed for EVER velocity

of pumping ideal liquid ,on the condition that
this velocity is constant, it is not variable.
.
Sincerely E.W.

The bottom of the tube does not is empty ,when the water
flows into it.

--
#191,

Hi
This tube is not empty ,it is full of the
water(ideal liquid) when motopump is working.
Sincerely E.W.

Then I have no idea where your motopump is. If it's at
the top, then it can move fluid around but that's about it.

If it's at the bottom, it's under tremendous but balanced
pressure from both sides of the tube bottom and can move
fluid around but that's about it.

--
#191,

*****************************************
Hi
The motopump is intalled on the top of the tube.
The lower end of the tube is open
The liquid fiows into the tube across the lower end f

of it into the motopump with the speed of v = sqrt (gH)

Sincerely E.W.

"Gieniu" <warendag@telus.net> wrote in message
news:743di.28720$vT6.6565@edtnps90...

"The Ghost In The Machine" <ewill@sirius.tg00suus7038.net> wrote in
message news:fh0vj4-7fv.ln1@sirius.tg00suus7038.net...

In sci.physics, Gieniu
<warendag@telus.net>
wrote
on Mon, 04 Jun 2007 20:18:38 GMT
<ys_8i.9$vT6.3@edtnps90>:

"The Ghost In The Machine" <ewill@sirius.tg00suus7038.net> wrote in
message
news:bp3cj4-t5c.ln1@sirius.tg00suus7038.net...

In sci.physics, Gieniu
<warendag@telus.net>
wrote
on Sun, 03 Jun 2007 06:08:45 GMT
<NVs8i.67391$V75.42901@edtnps89>:

Hi
The pumping it is moving of liquid from the lower level ho, to .
higher level h1.
Because this action is in the gravitational field,
therefore is prformed the work W=mg( h1 - h0),
and this work the motopump performs.
The straight tube is plunged deep into ideal liquid,
This tube is open on the both its ends.
On the top of tube is instaled the motopump
and the lower end of tube is open.
By action of the hydrostatic preasure, the liquid

flows into

the tube and into the motopump.
Maximal velocity v of pumped liquid is
v = sqrt ( gH)
Velociti of liquid out of pump is also same
but here there are two different action,
1/ keeping velocity of liquid as constant,
2/ hydrostatic preasure.which creates of
velocity of water equal v=sqrt(gh).
These two action are self-supporting

In order to receive energy E = m vv/2 =mgH/2
WE must give energy E1=mg(h1-h0);
it does the motopump

This work is performed for EVER velocity

of pumping ideal liquid ,on the condition that
this velocity is constant, it is not variable.
.
Sincerely E.W.

The bottom of the tube does not is empty ,when the water
flows into it.

--
#191,

Hi
This tube is not empty ,it is full of the
water(ideal liquid) when motopump is working.
Sincerely E.W.

Then I have no idea where your motopump is. If it's at
the top, then it can move fluid around but that's about it.

If it's at the bottom, it's under tremendous but balanced
pressure from both sides of the tube bottom and can move
fluid around but that's about it.

--
#191,

*****************************************
Hi
The motopump is intalled on top of the tube.
The lower end of the tube is open
The liquid fiows into the tube ,across the lower end fows out
of it into the motopump with the speed of v = sqrt (gH)

Sincerely E.W.