Hall effect sensors can easily measure the earths field (i have one on my
desk now). The effect of motion of the sensor is to increase or decrease the
velocity of the charge carries relative to their drift velocity. Its this
ratio which will determine the sensitivity.
"Igor" <thoovler@excite.com> wrote in message
news:1175552524.821257.251040@p15g2000hsd.googlegroups.com...
On Apr 2, 8:39 am, "WhoGoes" <nowh...@hotmail.com> wrote:
I'm reasonably familiar with the theory of the Hall effect but can
anyone
help with an explanation of their behaviour.
If a semiconductor Hall effect device is placed in the earths magnetic
field. then the charge carries are influenced by the magnetic field and
an
electric field is set up according to the right hand rule etc etc. All
straightforward. However if the Hall effect device is now moved in so
that
it has a velocity which adds (or subtracts) to the velocity of the
charge
carriers, is the Hall voltage affected by this mechanical velocity ie
B*q*(velectric+vmechanical).
I've tried this with a couple of Hall effect devices but cannot see any
change in the Hall voltage. Is my understanding incorrect or are the
voltages too small to measure ??
All assistance greatfully appreciated
Cheers
Ian
Ian(underscore)Whiteho...@hotmail.com
Probably too small to measure. The Earth's magnetic field is not very
strong.
.
