| Topic: |
Science > Physics |
| User: |
"gsax" |
| Date: |
14 Jul 2005 02:38:58 AM |
| Object: |
hawking radiation |
Hi
I was reading "Brief Hisotry of Time", where Hawking mentions how a
black hole can radiate..& loose mass (evaporate)......
This is acccomplished by a set of virtual particle-antiparticle pair
forming near it's event horizon... & then the anti-particle falls into
the black hole & the article is left out as radiation...
Now the antiparticle falling in causes the mass of black hole to
decrease, just as if it has been radiating a particle..
My question is:
Why is it that it id the anti-particle that falls in , there should be
an equal probability of the particle to fall in too?..but this would
mean that the mass of the black hole would neither increase nor
decrease in the long run?
PLease let me know where I am wrong ..?
thanks
Gsax
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| User: "" |
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| Title: Re: hawking radiation |
14 Jul 2005 04:01:46 AM |
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gsax wrote:
I was reading "Brief Hisotry of Time", where Hawking mentions
how a black hole can radiate..& loose mass (evaporate)......
This is acccomplished by a set of virtual particle-antiparticle
pair forming near it's event horizon... & then the anti-particle
falls into the black hole & the article is left out as radiation
Now the antiparticle falling in causes the mass of black hole to
decrease, just as if it has been radiating a particle..
My question is:
Why is it that the anti-particle that falls in? there should be
an equal probability of the particle to fall in too?
He's talking about particle and anti-particle in general terms,
as one might refer to a number x and its negative, -x, whether
or not x itself is negative (in which case -x would be positive).
What reduces the black hole mass is the energy conveyed away by
the particles that escape, and presumably these may be either
conventional ones in the sense you mean, or anti-particles.
The energy is the same for both.
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| User: "gsax" |
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| Title: Re: hawking radiation |
18 Jul 2005 06:44:03 AM |
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wrote:
He's talking about particle and anti-particle in general terms,
as one might refer to a number x and its negative, -x, whether
or not x itself is negative (in which case -x would be positive).
What reduces the black hole mass is the energy conveyed away by
the particles that escape, and presumably these may be either
conventional ones in the sense you mean, or anti-particles.
The energy is the same for both.
thanks for your reply,..
I see that the energy for both is same, but I was under the impression
that the antiparticle falls into the black hole & annihilates the mass
inside it..
thanks
Gsax
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| User: "" |
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| Title: Re: hawking radiation |
18 Jul 2005 07:11:25 AM |
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gsax wrote:
john_ramsden@sagitta-ps.com wrote:
He's talking about particle and anti-particle in general terms,
as one might refer to a number x and its negative, -x, whether
or not x itself is negative (in which case -x would be positive).
What reduces the black hole mass is the energy conveyed away by
the particles that escape, and presumably these may be either
conventional ones in the sense you mean, or anti-particles.
The energy is the same for both.
thanks for your reply,..
I see that the energy for both is same, but I was under the
impression that the antiparticle falls into the black hole
& annihilates the mass inside it..
Ah no, because in annihilating its matter counterpart the pair
would release an equivalent amount of energy, which would remain
trapped within the hole.
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