My mistake on Time Dilation?



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Topic: Science > Physics
User: ""
Date: 11 Feb 2005 10:07:14 AM
Object: My mistake on Time Dilation?
Sorry,
One can get lost when it comes to perspectives and observation, the end
fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks would
have been re-modified????
Both there is still one STRANGE question...Both "believe" the other has
AGED LESS...In a way could this mean time is but a mirage?
1. I had 2 pairs a twins on Earth.
2. One pair left Earth at 1/3c so say after 1 month, they were say 1
year younger than the Earth pair.
3. Then one brother of each pair flies at 2/3c to each immigrate on the
opposit's platform.
4. Now they remain this way at 1/3c for 10 years (making the period in
#1 more of an irrelevant factor since this period is much longer).
So from the laws of symmetry (and Inertial Reference Frames) both new
non-twin-brother pairs must be younger?
.

User: "Uncle Al"

Title: Re: My mistake on Time Dilation? 11 Feb 2005 12:25:43 PM
wrote:


Sorry,

One can get lost when it comes to perspectives and observation, the end
fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks would
have been re-modified????

[snip]
Absolutely not. The triplets experiment has no clock acceleration at
all. Only inertial velocity is required. The clock that passes
through the most space records the least time on local compairison.
http://sheol.org/throopw/sr-twin-01.html
The clock that goes forward and then backwards travels more undeniable
from any reference frame. The same is true for somebody in a circular
orbit hwerein the non-inertial reference frame ages more slowly.
The ratio by which the two have aged at the end when they are back
together again is the same in all reference frames:
ratio = sqrt(t^2 - x^2 - y^2 - z^2)/t (with units of c=1)
Acceleration breaks the symmetry of who ages faster. To accomplish
that, the acceleration can occur before the clocks (or the twins)
exist. Only reference frames matter.
Inertial frames with relative *velocities* pursue different paths
through spacetime in Special Relativity. No clock anomaly is apparent
in any of them until clocks are compared (by all being local when you
do it, initial calibration then experiment). Acceleration is
irrelevant in SR to the running of the clocks (as opposed to
Equivalence Principle acceleration in GR). Acceleration is necessary
at some arbitrary time not associated with the experiment itself for
breaking the symmetry of clock observation. Acceleration defines
which reference frame takes what path through spacetime - even if it
occurs when the clocks are *off* (or not even constructed yet, or
destroyed) - so the situation is NOT symmetric. There is a difference
between the reference frame and any clocks in it.
1) Acceleration is an absolute measurement and it does not require a
clock to make the measurement (e.g, simultaneous displacement of three
independent orthogonally cantilevered masses). There is no doubt who
was accelerated even if a clock was not running/existing during
aceleration. Any past accelerated reference frame has a different
mixture of space and time from an unaccelerated frame.
2) Past acceleration is irrelevant to the running of present clocks,
but not to the mixture of space and time in the reference frame that
said clocks measure. This is an important subtlety and the key to the
whole thing. You cannot synchronize clocks except by having them
local. That's what Relativity demands. If they are local at the
start, you can tell who was naughty thereafter without needing a clock
to do the acceleration measurement. Accelerometers are not clocks.
EXAMPLE: We have three identical clocks that are off (a state of not
running, or of not even having been fabricated) and zeroed. Each
clock has/will have a very short toggle jiggger switch sticking out.
We load them (or their parts, or ore and a smelter and a machine shop)
in individual spaceships and set up the experiment.
CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Touch the jigger
and the "off" state becomes "on" or the "on" state becomes "off."
Clock 1 is "off." Or we can build it from parts just before we need
it, and in the "off" state, zeroed.
CLOCK 2: In a spaceship traveling at 0.999c relative to our inertial
frame of reference. Clock 2 is "off." It was built after all
acceleration ceased, and set to zero. It skims past Clock 1 (our
clock), the jiggers touch, both Clocks 1 and 2 are now "on" and
locally synchronized by touching. Elapsed time accumulates in each
one. The situation is NOT symmetric! We know who accelerated to set
up the experiment even if there wasn't a clock present when it
happened.
CLOCK 3: In a spaceship traveling at 0.999c relative to our inertial
frame of reference, but 180 degrees counter in direction to Clock 2.
Clock 3 is zeroed and "off." It was built after all acceleration
ceased, and set to zero.
Some arbitrary time after Clocks 1 and 2 synchronize and turn "on" by
touching, Clocks 2 and 3 brush past each other, touching jiggers.
Clock 2 is now "off," Clock 3 is now "on." Write down the elapsed
time in now "off" Clock 2, then smash the clock with a sledgehammer.
Or melt it down, or toss it over the side. The spaceship with Clock 3
is returning back over the path taken by the spaceship with Clock 2.
CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Clock 3 rushes
past, jiggers touch. Clocks 3 and 1 are now off. All clocks are
off. No clock has accelerated while "on" or even while existing.
Write down elapsed times, smash each clock with a sledgehammer. Or
melt them down, or toss them.
BOTTOM LINE: Get all three slips of paper together... Accelerate as
you need. Or send all the results to all three folks by radio and
never decelerate. All clocks have been smashed, melted, tossed.
Their elapsed times were written down. The numbers on the papers
won't change when you accelerate or broadcast the data.
Acceleration is arguably General Relativity, as we did setting up the
experiment. It is irrelevant to the clocks. No clock is running or
even exists during acceleration. Numbers written on slips of paper
are unaffected by Special or General Relativity. One could as easily
build the clocks from their component parts after setting up the
experiment. No clock exists during acceleration up or down. The
*reference frame* has accelerated in the past, and that changes its
mix of space and time relative to an unaccelerated frame. The clocks
are passive observers in a presently unaccelerated setting.
Finally.... compare elapsed times. Elapsed time #2=#3 (straight line
motion for both traveling clocks, no acceleration!), but elapsed time
#2+#3 does not equal #1, the local stationary reference frame
summation. The sum of #2+#3 elasped time is only about 4.5% that than
of #1's accumulated elapsed time. You have the Twin Paradox (or,
Triplets) without any running clock having been accelerated - or
having even existed during acceleration up or down.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf
.
User: "Androcles Androcles@ MyPlace.org"

Title: Re: My mistake on Time Dilation? 11 Feb 2005 06:23:20 PM
"Uncle Al" <UncleAl0@hate.spam.net> wrote in message
news:420CF8A7.2CC8B01F@hate.spam.net...

guskz@hotmail.com wrote:


Sorry,

One can get lost when it comes to perspectives and observation, the
end
fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks would
have been re-modified????

[snip]

Absolutely not. The triplets experiment has no clock acceleration at
all. Only inertial velocity is required. The clock that passes
through the most space records the least time on local compairison.

http://sheol.org/throopw/sr-twin-01.html

The clock that goes forward and then backwards travels more undeniable
from any reference frame. The same is true for somebody in a circular
orbit hwerein the non-inertial reference frame ages more slowly.

The ratio by which the two have aged at the end when they are back
together again is the same in all reference frames:

ratio = sqrt(t^2 - x^2 - y^2 - z^2)/t (with units of c=1)

Acceleration breaks the symmetry of who ages faster. To accomplish
that, the acceleration can occur before the clocks (or the twins)
exist. Only reference frames matter.

Inertial frames with relative *velocities* pursue different paths
through spacetime in Special Relativity. No clock anomaly is apparent
in any of them until clocks are compared (by all being local when you
do it, initial calibration then experiment). Acceleration is
irrelevant in SR to the running of the clocks (as opposed to
Equivalence Principle acceleration in GR). Acceleration is necessary
at some arbitrary time not associated with the experiment itself for
breaking the symmetry of clock observation. Acceleration defines
which reference frame takes what path through spacetime - even if it
occurs when the clocks are *off* (or not even constructed yet, or
destroyed) - so the situation is NOT symmetric. There is a difference
between the reference frame and any clocks in it.

1) Acceleration is an absolute measurement and it does not require a
clock to make the measurement (e.g, simultaneous displacement of three
independent orthogonally cantilevered masses). There is no doubt who
was accelerated even if a clock was not running/existing during
aceleration. Any past accelerated reference frame has a different
mixture of space and time from an unaccelerated frame.

2) Past acceleration is irrelevant to the running of present clocks,
but not to the mixture of space and time in the reference frame that
said clocks measure. This is an important subtlety and the key to the
whole thing. You cannot synchronize clocks except by having them
local. That's what Relativity demands. If they are local at the
start, you can tell who was naughty thereafter without needing a clock
to do the acceleration measurement. Accelerometers are not clocks.

EXAMPLE: We have three identical clocks that are off (a state of not
running, or of not even having been fabricated) and zeroed. Each
clock has/will have a very short toggle jiggger switch sticking out.
We load them (or their parts, or ore and a smelter and a machine shop)
in individual spaceships and set up the experiment.

CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Touch the jigger
and the "off" state becomes "on" or the "on" state becomes "off."
Clock 1 is "off." Or we can build it from parts just before we need
it, and in the "off" state, zeroed.

CLOCK 2: In a spaceship traveling at 0.999c relative to our inertial
frame of reference. Clock 2 is "off." It was built after all
acceleration ceased, and set to zero. It skims past Clock 1 (our
clock), the jiggers touch, both Clocks 1 and 2 are now "on" and
locally synchronized by touching. Elapsed time accumulates in each
one. The situation is NOT symmetric! We know who accelerated to set
up the experiment even if there wasn't a clock present when it
happened.

CLOCK 3: In a spaceship traveling at 0.999c relative to our inertial
frame of reference, but 180 degrees counter in direction to Clock 2.
Clock 3 is zeroed and "off." It was built after all acceleration
ceased, and set to zero.

Some arbitrary time after Clocks 1 and 2 synchronize and turn "on" by
touching, Clocks 2 and 3 brush past each other, touching jiggers.
Clock 2 is now "off," Clock 3 is now "on." Write down the elapsed
time in now "off" Clock 2, then smash the clock with a sledgehammer.
Or melt it down, or toss it over the side. The spaceship with Clock 3
is returning back over the path taken by the spaceship with Clock 2.

CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Clock 3 rushes
past, jiggers touch. Clocks 3 and 1 are now off. All clocks are
off. No clock has accelerated while "on" or even while existing.
Write down elapsed times, smash each clock with a sledgehammer. Or
melt them down, or toss them.

BOTTOM LINE: Get all three slips of paper together... Accelerate as
you need. Or send all the results to all three folks by radio and
never decelerate. All clocks have been smashed, melted, tossed.
Their elapsed times were written down. The numbers on the papers
won't change when you accelerate or broadcast the data.

Acceleration is arguably General Relativity, as we did setting up the
experiment. It is irrelevant to the clocks. No clock is running or
even exists during acceleration. Numbers written on slips of paper
are unaffected by Special or General Relativity. One could as easily
build the clocks from their component parts after setting up the
experiment. No clock exists during acceleration up or down. The
*reference frame* has accelerated in the past, and that changes its
mix of space and time relative to an unaccelerated frame. The clocks
are passive observers in a presently unaccelerated setting.

Finally.... compare elapsed times. Elapsed time #2=#3 (straight line
motion for both traveling clocks, no acceleration!), but elapsed time
#2+#3 does not equal #1, the local stationary reference frame
summation. The sum of #2+#3 elasped time is only about 4.5% that than
of #1's accumulated elapsed time. You have the Twin Paradox (or,
Triplets) without any running clock having been accelerated - or
having even existed during acceleration up or down.

ROFL!
Do the math, wangless Alice.
½[tau(0,0,0,t)+tau(0,0,0,t+x'/(c-v)+x'/something not there)]
= tau(x',0,0,t+x'/(c-v))
Fucking blind as a bat.... what a maroon.
Androcles

--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf

.

User: ""

Title: Re: My mistake on Time Dilation? 12 Feb 2005 12:56:10 PM
Uncle Al wrote:

guskz@hotmail.com wrote:


Sorry,

One can get lost when it comes to perspectives and observation, the

end

fact they MUST ACCELERATE (for their distance increases

considerably

with time) to compare each others values and by then the clocks

would

have been re-modified????

[snip]

Absolutely not. The triplets experiment has no clock acceleration at
all. Only inertial velocity is required. The clock that passes
through the most space records the least time on local compairison.

http://sheol.org/throopw/sr-twin-01.html

Wowww Uncle Al what's that below an Entire Epistle.
They're aint no way I can follow such details, all the models I posted
are very very simple and even you can stand reading the few lines.
You've got a million and one different FACTORS to promote your demo.

We load them (or their parts, or ore and a smelter and a machine

shop)

in individual spaceships and set up the experiment.

Ores? smelters? Machine shops? sledgehammers?
I bet you write 1/5 of all below an still maintain a simplified
intergrety to what you wish to demonstrate.

The clock that goes forward and then backwards travels more

undeniable

from any reference frame. The same is true for somebody in a circular
orbit hwerein the non-inertial reference frame ages more slowly.

The ratio by which the two have aged at the end when they are back
together again is the same in all reference frames:

ratio = sqrt(t^2 - x^2 - y^2 - z^2)/t (with units of c=1)

Acceleration breaks the symmetry of who ages faster. To accomplish
that, the acceleration can occur before the clocks (or the twins)
exist. Only reference frames matter.

Inertial frames with relative *velocities* pursue different paths
through spacetime in Special Relativity. No clock anomaly is

apparent

in any of them until clocks are compared (by all being local when you
do it, initial calibration then experiment). Acceleration is
irrelevant in SR to the running of the clocks (as opposed to
Equivalence Principle acceleration in GR). Acceleration is necessary
at some arbitrary time not associated with the experiment itself for
breaking the symmetry of clock observation. Acceleration defines
which reference frame takes what path through spacetime - even if it
occurs when the clocks are *off* (or not even constructed yet, or
destroyed) - so the situation is NOT symmetric. There is a

difference

between the reference frame and any clocks in it.

1) Acceleration is an absolute measurement and it does not require a
clock to make the measurement (e.g, simultaneous displacement of

three

independent orthogonally cantilevered masses). There is no doubt who
was accelerated even if a clock was not running/existing during
aceleration. Any past accelerated reference frame has a different
mixture of space and time from an unaccelerated frame.

2) Past acceleration is irrelevant to the running of present clocks,
but not to the mixture of space and time in the reference frame that
said clocks measure. This is an important subtlety and the key to

the

whole thing. You cannot synchronize clocks except by having them
local. That's what Relativity demands. If they are local at the
start, you can tell who was naughty thereafter without needing a

clock

to do the acceleration measurement. Accelerometers are not clocks.

EXAMPLE: We have three identical clocks that are off (a state of not
running, or of not even having been fabricated) and zeroed. Each
clock has/will have a very short toggle jiggger switch sticking out.
We load them (or their parts, or ore and a smelter and a machine

shop)

in individual spaceships and set up the experiment.

CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Touch the jigger
and the "off" state becomes "on" or the "on" state becomes "off."
Clock 1 is "off." Or we can build it from parts just before we need
it, and in the "off" state, zeroed.

CLOCK 2: In a spaceship traveling at 0.999c relative to our inertial
frame of reference. Clock 2 is "off." It was built after all
acceleration ceased, and set to zero. It skims past Clock 1 (our
clock), the jiggers touch, both Clocks 1 and 2 are now "on" and
locally synchronized by touching. Elapsed time accumulates in each
one. The situation is NOT symmetric! We know who accelerated to set
up the experiment even if there wasn't a clock present when it
happened.

CLOCK 3: In a spaceship traveling at 0.999c relative to our inertial
frame of reference, but 180 degrees counter in direction to Clock 2.
Clock 3 is zeroed and "off." It was built after all acceleration
ceased, and set to zero.

Some arbitrary time after Clocks 1 and 2 synchronize and turn "on" by
touching, Clocks 2 and 3 brush past each other, touching jiggers.
Clock 2 is now "off," Clock 3 is now "on." Write down the elapsed
time in now "off" Clock 2, then smash the clock with a sledgehammer.
Or melt it down, or toss it over the side. The spaceship with Clock

3

is returning back over the path taken by the spaceship with Clock 2.

CLOCK 1: That's our clock. It sits stationary in our inertial
reference frame with a little jigger sticking out. Clock 3 rushes
past, jiggers touch. Clocks 3 and 1 are now off. All clocks are
off. No clock has accelerated while "on" or even while existing.
Write down elapsed times, smash each clock with a sledgehammer. Or
melt them down, or toss them.

BOTTOM LINE: Get all three slips of paper together... Accelerate as
you need. Or send all the results to all three folks by radio and
never decelerate. All clocks have been smashed, melted, tossed.
Their elapsed times were written down. The numbers on the papers
won't change when you accelerate or broadcast the data.

Acceleration is arguably General Relativity, as we did setting up the
experiment. It is irrelevant to the clocks. No clock is running or
even exists during acceleration. Numbers written on slips of paper
are unaffected by Special or General Relativity. One could as easily
build the clocks from their component parts after setting up the
experiment. No clock exists during acceleration up or down. The
*reference frame* has accelerated in the past, and that changes its
mix of space and time relative to an unaccelerated frame. The clocks
are passive observers in a presently unaccelerated setting.

Finally.... compare elapsed times. Elapsed time #2=#3 (straight line
motion for both traveling clocks, no acceleration!), but elapsed time
#2+#3 does not equal #1, the local stationary reference frame
summation. The sum of #2+#3 elasped time is only about 4.5% that

than

of #1's accumulated elapsed time. You have the Twin Paradox (or,
Triplets) without any running clock having been accelerated - or
having even existed during acceleration up or down.


--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf

.


User: "Jesse Mazer"

Title: Re: My mistake on Time Dilation? 11 Feb 2005 11:44:29 AM
wrote:

Sorry,

One can get lost when it comes to perspectives and observation, the end
fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks would
have been re-modified????

Both there is still one STRANGE question...Both "believe" the other has
AGED LESS...In a way could this mean time is but a mirage?


1. I had 2 pairs a twins on Earth.

2. One pair left Earth at 1/3c so say after 1 month, they were say 1
year younger than the Earth pair.

3. Then one brother of each pair flies at 2/3c to each immigrate on the
opposit's platform.

4. Now they remain this way at 1/3c for 10 years (making the period in
#1 more of an irrelevant factor since this period is much longer).


So from the laws of symmetry (and Inertial Reference Frames) both new
non-twin-brother pairs must be younger?



If I'm understanding your example correctly, yes. If quadruplets A and B
are on earth and quadruplets C and D are on a ship moving at 1/3c away
from earth, then if B flies out at 2/3c to catch up with the ship and D
flies back at 2/3c to catch up with the earth, then B will find himself
younger than C when they meet, and D will find himself younger than A
when they meet.
Jesse
.
User: ""

Title: Re: My mistake on Time Dilation? 12 Feb 2005 07:58:15 AM
Jesse Mazer wrote:

guskz@hotmail.com wrote:

Sorry,

One can get lost when it comes to perspectives and observation, the

end

fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks

would

have been re-modified????

Both there is still one STRANGE question...Both "believe" the other

has

AGED LESS...In a way could this mean time is but a mirage?


1. I had 2 pairs a twins on Earth.

2. One pair left Earth at 1/3c so say after 1 month, they were say 1
year younger than the Earth pair.

3. Then one brother of each pair flies at 2/3c to each immigrate on

the

opposit's platform.

4. Now they remain this way at 1/3c for 10 years (making the period

in

#1 more of an irrelevant factor since this period is much longer).


So from the laws of symmetry (and Inertial Reference Frames) both

new

non-twin-brother pairs must be younger?




If I'm understanding your example correctly, yes. If quadruplets A

and B

are on earth and quadruplets C and D are on a ship moving at 1/3c

away

from earth, then if B flies out at 2/3c to catch up with the ship and

D

flies back at 2/3c to catch up with the earth, then B will find

himself

younger than C when they meet, and D will find himself younger than A
when they meet.

Jesse

Dead-on Jesse
1. It's just that from A's perspective C is aging less
2. C forgot he left A and his perspective is D is aging less:
Whether D departs from C at 2/3 and then 1/3c with A, D continues to
age LESS but at a reduced rate.
Therefore:
In 1: A aging more than C
In 2: D aging less than C
When A&D are together their clocks are TOGETHER SIDE BY SIDE and MUST
behave in the exact same way yet there's an irregularity according to 1
and 2 above.
Does this make time a perspective only?
.


User: ""

Title: Re: My mistake on Time Dilation? 11 Feb 2005 10:55:31 AM
I think the 3 observations below are correct?
1. Therefore if I'm not mistaken if two planes leave east and west from
earth then whom ever of the 2 planes decides to accelerate to see the
other one's clock will be the younger....
2. or if both planes decide to both return and meet each othe half way
then once again their clocks will be the same.
----------------------------------------------------------------
So in a way...it doesn't matter whom left whom?
Meaning if one left Earth at 1/3c so he's aging less.
3. But if Earth which to catch up the distance lost between them then
1/3c is insufficient, so if Earth goes 2/3c to see the departed's clock
then Earth with be younger.
guskz@hotmail.com wrote:

Sorry,

One can get lost when it comes to perspectives and observation, the

end

fact they MUST ACCELERATE (for their distance increases considerably
with time) to compare each others values and by then the clocks would
have been re-modified????

Both there is still one STRANGE question...Both "believe" the other

has

AGED LESS...In a way could this mean time is but a mirage?


1. I had 2 pairs a twins on Earth.

2. One pair left Earth at 1/3c so say after 1 month, they were say 1
year younger than the Earth pair.

3. Then one brother of each pair flies at 2/3c to each immigrate on

the

opposit's platform.

4. Now they remain this way at 1/3c for 10 years (making the period

in

#1 more of an irrelevant factor since this period is much longer).


So from the laws of symmetry (and Inertial Reference Frames) both new
non-twin-brother pairs must be younger?

.


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