Nonrenormalization vs Renormalization 24.4: The Case x = y = z in D1xyz
From Osher Doctorow
Consider:
1) D1xyz(1, x, y, z) = y(1 + y) + (y - z)(1 - x) - yz - x = 0
If x = y = z, we get:
2) x(1 + x) + 0 - x^2 - x = 0
which says:
3) x + x^2 - x^2 - x = 0
which is the identity 0 = 0.
Osher Doctorow
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