Bilge wrote: > > guskz@hotmail.com:
I find it a VERY interesting and perplexing question because if
HEAT IS NEVER LOST and only shifts to other locations ....
THEREFORE the very thermodynamic laws affecting the Big Bang
would be "quazy" wrong since the Universe never actually does
"cool" down and the original heat (quantity of heat) of the
explosion will NEVER go away thus interfering with the cooling
down theory???
PV = nkT
$$ Pauli EXCLUSiON factor k, in Big Bang GR (Bilge).
$$ Pressure*Volume = n*k*degKelvin ..k is Boltzmann/Pauli PARTiTiON k.
'Statistical Physics for Students of Science and Engineering'; Dover.
E = eM + eK = iNTRiNSiC energy + LaGrangian L + Volt*A*sec energy eV.
Where, LaGrangian L = degKelvin*entropy[S] ..and, E = Total ENTHALPY.
Where Pa = Pascal PRESSURE ..and degK = Kelvin Temperature. ```Brian.
-=-
However, your question is completely answered by the first law
of thermodynamics: dU = dQ - dW, or the change in internal energy is
equal to the change in heat minus the work done by the system.
-=-
Example: > >> -=-
water particles turn turbines (converts to kinetic energy) but
the water itself never disappears (or becomes converted)
...therefore is it likewise for Temperature??
If so this should have implications on the laws of thermodynamis
with regards to the ***BIG BANG*** and the final suggested state
of the Universe? > >
Re: Pressure*Volume = n*k*degKelvin ..k is Boltzmann/Pauli PARTiTiON k.
Re: Pauli EXCLUSiON factor k, in Big Bang GR (Bilge).
.
