Physics Help. Spring Problem



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Topic: Science > Physics
User: ""
Date: 04 Oct 2005 02:59:30 PM
Object: Physics Help. Spring Problem
Here is the problem.
Bodies A, B, and C are arrayed in a triangle. A and B are connected by
a spring with spring constant K and length r. B and C are also
connected by a spring with the same spring constant K and same length
r. Let the angle ABC be theta radians. Angle ABC has a bending spring
constant k_bend. All potentials are harmonic.
So, what is the effective spring constant between A and C?
This problem has me stumped.
Thanks a lot.
.

User: "Gregory L. Hansen"

Title: Re: Physics Help. Spring Problem 05 Oct 2005 10:23:36 AM
In article <1128455970.752360.190540@g43g2000cwa.googlegroups.com>,
<timwryan@gmail.com> wrote:

Here is the problem.

Bodies A, B, and C are arrayed in a triangle. A and B are connected by
a spring with spring constant K and length r. B and C are also
connected by a spring with the same spring constant K and same length
r. Let the angle ABC be theta radians. Angle ABC has a bending spring
constant k_bend. All potentials are harmonic.

So, what is the effective spring constant between A and C?

This problem has me stumped.

Thanks a lot.

Who would give an insane spring problem like this one?
First we have to make sure all our assumptions are straight. We always
start with a diagram. Slightly rotated for ASCII purposes...
K
A-------B
|
k_bend | K
|
C
I suppose the effective spring constant between A and C means the force
per unit displacement if we tied strings to A and C and pulled them apart.
That is, the force will act directly through the line connecting A and C.
Not explicitly stated in the problem, but probably reasonable, is to
suppose that the springs on AB and BC are in telescoping tubes that keep
the springs straight, and B is hinged.
If AB and BC are connected by rigid rods and B is hinged with a spring
constant k_bend, can you calculate the effective spring constant between A
and C?
If AB and BC are connected by springs inside telescoping tubes and B is
locked into position at some angle theta, can you calculate the effective
spring constant between A and C?
You should be able to solve those two partial problems by decomposing
the force between A and C into components that are parallel and
perpendicular to AB and BC. When you combine those two effects, should
the effective spring constant increase or decrease?
--
"Is that plutonium on your gums?"
"Shut up and kiss me!"
-- Marge and Homer Simpson
.
User: "Randy Poe"

Title: Re: Physics Help. Spring Problem 05 Oct 2005 10:54:05 AM
Gregory L. Hansen wrote:

In article <1128455970.752360.190540@g43g2000cwa.googlegroups.com>,
<timwryan@gmail.com> wrote:

Here is the problem.

Bodies A, B, and C are arrayed in a triangle. A and B are connected by
a spring with spring constant K and length r. B and C are also
connected by a spring with the same spring constant K and same length
r. Let the angle ABC be theta radians. Angle ABC has a bending spring
constant k_bend. All potentials are harmonic.

So, what is the effective spring constant between A and C?

This problem has me stumped.

Thanks a lot.


Who would give an insane spring problem like this one?

It seems like a strange homework problem, but not a strange
real-life problem. Perhaps I want to know how to build spring
systems with any desired spring constant out of a stock collection
of springs.


First we have to make sure all our assumptions are straight. We always
start with a diagram. Slightly rotated for ASCII purposes...

K
A-------B
|
k_bend | K
|
C

I suppose the effective spring constant between A and C means the force
per unit displacement if we tied strings to A and C and pulled them apart.
That is, the force will act directly through the line connecting A and C.

Yes. I envision a piece of spring steel mounted at the
corner ABC, pre-bent to the desired equilibrium angle.

Not explicitly stated in the problem, but probably reasonable, is to
suppose that the springs on AB and BC are in telescoping tubes that keep
the springs straight, and B is hinged.

If AB and BC are connected by rigid rods and B is hinged with a spring
constant k_bend, can you calculate the effective spring constant between A
and C?

If AB and BC are connected by springs inside telescoping tubes and B is
locked into position at some angle theta, can you calculate the effective
spring constant between A and C?

Couldn't you do it all in one step? Stretch the line
AC by some amount dx. This will cause a change in lines
AB and BC by an amount which depends on theta. It will
also change theta by an amount d(theta).
As a result of those three stretches, there will be a
total restoring force. The ratio between force and dx
is the effective spring constant.
Of course because of the dependence on theta, I suspect that
Hooke's law doesn't apply for large deformations (dF/dx is
not a constant), so the idea of an "effective spring constant"
only works if dx is small compared to, say, r.
- Randy
.
User: "Gregory L. Hansen"

Title: Re: Physics Help. Spring Problem 05 Oct 2005 11:28:20 AM
In article <1128527645.706098.218280@g14g2000cwa.googlegroups.com>,
Randy Poe <poespam-trap@yahoo.com> wrote:


Gregory L. Hansen wrote:

In article <1128455970.752360.190540@g43g2000cwa.googlegroups.com>,
<timwryan@gmail.com> wrote:

Here is the problem.

Bodies A, B, and C are arrayed in a triangle. A and B are connected by
a spring with spring constant K and length r. B and C are also
connected by a spring with the same spring constant K and same length
r. Let the angle ABC be theta radians. Angle ABC has a bending spring
constant k_bend. All potentials are harmonic.

So, what is the effective spring constant between A and C?

This problem has me stumped.

Thanks a lot.


Who would give an insane spring problem like this one?


It seems like a strange homework problem, but not a strange
real-life problem. Perhaps I want to know how to build spring
systems with any desired spring constant out of a stock collection
of springs.


First we have to make sure all our assumptions are straight. We always
start with a diagram. Slightly rotated for ASCII purposes...

K
A-------B
|
k_bend | K
|
C

I suppose the effective spring constant between A and C means the force
per unit displacement if we tied strings to A and C and pulled them apart.
That is, the force will act directly through the line connecting A and C.


Yes. I envision a piece of spring steel mounted at the
corner ABC, pre-bent to the desired equilibrium angle.

I can see it as a strength of materials problem, too, if we dispense with
a common pedagogical assumption that all members are attached by hinges.


Not explicitly stated in the problem, but probably reasonable, is to
suppose that the springs on AB and BC are in telescoping tubes that keep
the springs straight, and B is hinged.

If AB and BC are connected by rigid rods and B is hinged with a spring
constant k_bend, can you calculate the effective spring constant between A
and C?

If AB and BC are connected by springs inside telescoping tubes and B is
locked into position at some angle theta, can you calculate the effective
spring constant between A and C?


Couldn't you do it all in one step? Stretch the line
AC by some amount dx. This will cause a change in lines
AB and BC by an amount which depends on theta. It will
also change theta by an amount d(theta).

As a result of those three stretches, there will be a
total restoring force. The ratio between force and dx
is the effective spring constant.

I'm sure it could be done in one step, but timwryan hasn't if he's posting
the question here. Reducing a complicated problem to several smaller
problems, or to a related but simpler problem, is an important technique.
Complexity can be added in steps as the simpler problems are understood.


Of course because of the dependence on theta, I suspect that
Hooke's law doesn't apply for large deformations (dF/dx is
not a constant), so the idea of an "effective spring constant"
only works if dx is small compared to, say, r.

I would think so. Clearly the effective spring constant would be
different when the legs are closed, when it would be all k_bend, versus
all the way open, when it would be all K.
--
"In any case, don't stress too much--cortisol inhibits muscular
hypertrophy. " -- Eric Dodd
.

User: ""

Title: Re: Physics Help. Spring Problem 05 Oct 2005 01:10:23 PM
Thank you for your reply.
I too agree that Hooke's law does not apply for large deformations.
Fortunately, if r is the distance |AB| or |BC|, then dr should be on
the order of 3% of r. Likewise, the angle ABC should only vary by 3 - 5
degrees. My hope is that I can find an analytic solution to the problem
in which the effective "spring constant" is constant, to a first
approximation, and not a function itself of the displacement along
|AC|.
Tim
.


User: ""

Title: Re: Physics Help. Spring Problem 05 Oct 2005 12:48:58 PM
Thanks for the response. Here is my attempt at a diagram. Recall that
the distance |AB| is equal to the distance |BC| and the spring constant
k is the same for each of these two springs.
k k_bend
A----------B
` |
` |
` | k
` |
` C
Here are some answers to your questions. First, AB and BC are straight
and can be though of as connected by telescoping tubes. Given a fixed
angle ABC, I can calculate an effective spring constant along the line
AC. I know the spring constant k_bend as a function of the angular
displacement, i.e. [theta_0 - theta], which is used to describe the
potential energy, V_bend = 1/2*k_bend*[theta_0 - theta]^2, where
theta_0 is the angle of minimal potential energy.
I believe I still need to know how to transform the "angular" or
"torsional" spring constant k_bend into a function of the linear
displacement along the line AC, in order to derive an expression for
the total potential as a function of the linear displacement along AC.
Really, I am trying to understand AC as an oscillator. That is, I would
like to get a handle on how the magnitude of the distance between AC
fluctuates, with specific interest in the potential energy of such
oscillations.
Thank you again for your help,
Tim
P.S. I am an undergraduate at the University of Oregon.
.
User: "tadchem"

Title: Re: Physics Help. Spring Problem 05 Oct 2005 01:38:31 PM
wrote:

Thanks for the response. Here is my attempt at a diagram. Recall that
the distance |AB| is equal to the distance |BC| and the spring constant
k is the same for each of these two springs.

k k_bend
A----------B
` |
` |
` | k
` |
` C

Nice work for ASCII...

I believe I still need to know how to transform the "angular" or
"torsional" spring constant k_bend into a function of the linear
displacement along the line AC, in order to derive an expression for
the total potential as a function of the linear displacement along AC.
Really, I am trying to understand AC as an oscillator. That is, I would
like to get a handle on how the magnitude of the distance between AC
fluctuates, with specific interest in the potential energy of such
oscillations.

What you need to know is the equilibrium value of angle <ABC. That will
determine the values for angles <BAC and <BCA [each = (pi - <ABC)/2].
The coupling between A and C will then depend on the components of the
forces along AB and BC that are parallel to AC. You should see that
the sin(<BAC)=sin(<BCA) will figure into the solution.
Tom Davidson
Richmond, VA
.




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