| Topic: |
Science > Physics |
| User: |
"dflower50" |
| Date: |
13 Feb 2005 05:36:05 PM |
| Object: |
PLEASE HELP..! |
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
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| User: "Siddhartha" |
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| Title: Re: PLEASE HELP..! |
14 Feb 2005 10:27:42 PM |
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"dflower50" <dflower50@yahoo-dot-com.no-spam.invalid> wrote in message
news:420fe465$1_1@127.0.0.1...
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com
Was this your homework?
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| User: "KanggyeSon" |
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| Title: Re: PLEASE HELP..! |
13 Feb 2005 07:43:16 PM |
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"dflower50" <dflower50@yahoo-dot-com.no-spam.invalid> wrote in message
news:420fe465$1_1@127.0.0.1...
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
v=at + v0
s=at^2+(v-v0)t+s0
s1+s2=36
Your turn.
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| User: "bxbxb3" |
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| Title: Re: PLEASE HELP..! |
14 Feb 2005 02:38:39 AM |
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The correct answer is : after time 7.17 seconds, the two players will
colide. The first player is at a distance 0.4*t*t =
0.4*7.17.7.17=20.56meters
and the second player is at a distance 0.3*t*t =
0.3*7.17*7.17=15.42meters. 20.56+15.42=36, if I am not wrong.
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| User: "CWatters" |
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| Title: Re: PLEASE HELP..! |
14 Feb 2005 02:23:30 AM |
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"dflower50" <dflower50@yahoo-dot-com.no-spam.invalid> wrote in message
news:420fe465$1_1@127.0.0.1...
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
Find the standard equation that relates distance, time and acceleration.
Write two versions - one for each player.
Note that each player runs for the same amount of time so t1=t2
Note that the distance each one travels added together = 36M
You should now have several equations and the same number of unknowns.
Solve to give the answers you need.
Check: since they are going in oposite directions the polarity of some
variables will need thought.
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| User: "Greg Neill" |
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| Title: Re: PLEASE HELP..! |
13 Feb 2005 06:01:40 PM |
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"dflower50" <dflower50@yahoo-dot-com.no-spam.invalid> wrote in message
news:420fe465$1_1@127.0.0.1...
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
What's the net closing acceleration?
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| User: "Ken S. Tucker" |
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| Title: Re: PLEASE HELP..! |
13 Feb 2005 07:17:04 PM |
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Greg...
It all depends on how close the soccer
players are to event horizon.
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| User: "tadchem" |
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| Title: Re: PLEASE HELP..! |
14 Feb 2005 09:53:29 AM |
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By "event horizon" do you mean the event that renders them both
horizontal?
Tom Davidson
Richmond, VA
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| User: "Uncle Al" |
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| Title: Re: PLEASE HELP..! |
13 Feb 2005 05:58:21 PM |
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dflower50 wrote:
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
Find the time to impact from summed accelerations, s=at^2/2. Go on
from there.
Usenet's cloaca,
Posted Via Usenet.com Premium Usenet Newsgroup Services
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** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
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--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf
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| User: "PD" |
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| Title: Re: PLEASE HELP..! |
14 Feb 2005 11:42:15 AM |
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dflower50 wrote:
I can't seem to find the correct equation to solve these two
problems...please help...
two soccer players start from rest, 36meters apart. They run directly
toward each other, both players accelerating. the first player has
an acceleration of 0.40m/s^2 and the second players acceleration is
0.30m/s^2.
A)how much time passes before the collide?
B)at the instant they collide, how far has the first player run?
any help would be awesome
First and always: Draw it. Draw, draw, draw, draw, draw, draw, draw.
Draw a line, put one player in one spot (what value do you want to give
to that location?), and put the other player in the other spot (what
value do you want to give to that location?)
Now DRAW acceleration vectors from each player, roughly to scale and in
the right directions.
Now DRAW a place where you think they'll meet. You should be able to
guess from the size of your acceleration vectors whether that meeting
spot will be dead in the middle, or closer to the first player, or
closer to the second. This guess will help you check your calculator
answer in the end to see if you made a mistake.
Now, write down the displacement of the first player as a function of
time (an algebraic equation), making sure that you use your drawing to
know which quantities are zero, which are positive, and which are
negative.
Do the same thing for the second player.
Here's what you know: when they collide, they've both run the same
amount of time (so you don't have to call them t1 and t2, it's just t),
and they meet at the same place (obviously) at that time t.
Physics is done. Rest is just algebra.
PD
Posted Via Usenet.com Premium Usenet Newsgroup Services
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** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
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