Science > Physics > Quantum Gravity 119.6: Example of Generalized Lie Derivative in Golden Mean
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Science > Physics |
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"OsherD" |
| Date: |
24 Apr 2007 06:20:01 PM |
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Quantum Gravity 119.6: Example of Generalized Lie Derivative in Golden Mean |
From Osher Doctorow
The Generalized Lie Derivative in the special form:
1) L(x, y) = 2xy, x and y real
yields the Riccati Differential equation terms by:
2) L(y, y) = 2y^2
3) L(y, 1) = 2y
4) L(1, 1) = 2
which directly go into the Riccati Differential Equation:
5) dy/dt = A(t) + B(t)y + C(t)y^2 = (1/2)[A(t)L(1, 1) + B(t)L(y, 1) +
C(t)L(y,y)]
For an example, let's look at the golden mean. Geometrically and
algebraic, the Golden Mean is defined by the ratios (where a and b can
be two sides of similar figures, etc.):
6) (a + b)/a = (a/b)
Notice that a occurs in the denominator of the left hand side and in
the numerator of the right hand side, corresponding to the definition
of a as the "mean" of the ratio(s), while a + b and b, which occur in
the numerator of the left hand side and the denominator of the right
hand side respectively, are called the "extremes" of the ratio(s).
The quantity a or a^2 (the product of the a's in the numerator and
denominator as indicated) arguably plays the most critical
(interactive, communicating, etc.) role as the mean of the ratio(s),
and therefore a^2 should occur as the (Probably) Causing variable (the
negative term) in Probable Causation/Influence (PI). To see whether
this is correct, multiply both sides of (6) by ab, which yields:
7) ab + b^2 = a^2
and therefore:
8) ab + b^2 - a^2 = 0
and by adding 1 to both sides of (8) we finally get:
9) 1 + (ab + b^2) - a^2 = 1
which says that P(A-->B) = 1 + y - x = 1 with x = a^2, y = (ab +
b^2). As expected, the negative term -x = -a^2 is precisely what was
predicted, and a^2 is the Causal "variable", while (ab + b^2)
represents the Effect.
In the usual method of finding the Golden Mean from (7), we divide
both sides by b^2 to obtain:
10) 1 + (a/b) - (a/b)^2 = 0
and defining phi as a/b, we get:
11) phi = (1/2)(1 +/- sqrt(5))
which is the Golden Mean and/or its "Conjugate". Notice that (10)
itself does not obey the optimal P(A-->B) = 1 equation analogous to
(9), precisely because (10) interpreted as a Probable Causation/
Influence would be equivalent to the claim that the PI of (a/b)^2
causing or influencing (a/b) is 0, a rather curious interpretion to
say the least. Since a or a^2 is actually Causal rather than a/b,
and the Golden Mean phi is a/b, the fact that a = (a/b)b means that b
times the Golden Mean (or the square of this) is the Cause rather than
just the Golden Mean itself.
The quantity a^2 = L(a, a), which is where the Generalized Lie
Derivative comes in, and the Generalized Lie Derivative is indeed
Causal here.
Osher Doctorow
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| User: "OsherD" |
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| Title: Re: Quantum Gravity 119.6: Example of Generalized Lie Derivative in Golden Mean |
25 Apr 2007 08:53:02 PM |
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From Osher Doctorow
I meant at the end of the last post that a^2 = (1/2)L(a, a) since L(a,
a) = 2a^2.
Osher DOctorow
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