From Osher Doctorow
Notice that:
1) sqrt(2) < sqrt(4) < sqrt(5)
so with y = sqrt(n) having n = 4 as one of the 2 solutions of last
time, and with sqrt(2) and sqrt(5) generating the Pell Numbers and
Fibonacci Numbers respectively, we arguably are zeroing in on the
generators of the latter two types of number.
The case y = sqrt(0) = 0 is as close to sqrt(2) in the argument at
least as the latter is to sqrt(4)'s argument, so the other solution
for y is "reasonable". Again, these are non-normalized except for 0,
which arguably doesn't affect the general idea.
Osher Doctorow
.
|
