Quantum Imaging



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Topic: Science > Physics
User: "Jim Lewis"
Date: 10 Feb 2004 11:52:56 AM
Object: Quantum Imaging
Would it be possible, at least in principle, to have an idler beam and
a signal beam of polarization-entangled photons, in which most (over
50%) of the entangled photons have the same polarization? You would
not need to know the actual polarization, just that they had the same
polarization.
If so, suppose you place a reflecting object (smaller than the signal
beam) in the path of the signal beam, 9 meters from the source of the
signal beam.
Assuming the "signal beam" photons reflecting off the object now have
an opposite polarization (to those not striking the object), would
the corresponding entangled photons in the idler beam now have this
same polarization?
If so, could you place a detector (perhaps after a vertical polarizer)
at 10 meters from the source of the idler beam, and regardless of
whether the initial polarization were vertical or horizontal, detect
the object in the idler beam, without using a coincidence detector?
In order to not use a coincidence counter, I assume I would need an
idler and signal beam in which most of the photons are entangled
photons, versus non-entangled photons.
Presumably this quantum imaging technique would not work, even in
principle, since it implies FTL communication, but I am interested in
why this will not work, and thus what my misunderstandings are.
.

User: "Michael Varney"

Title: Re: Quantum Imaging 10 Feb 2004 03:31:38 PM
"Jim Lewis" <jim_lewis_11@hotmail.com> wrote in message
news:1fa4bbdf.0402100952.373740e0@posting.google.com...

Would it be possible, at least in principle, to have an idler beam and
a signal beam of polarization-entangled photons, in which most (over
50%) of the entangled photons have the same polarization? You would
not need to know the actual polarization, just that they had the same
polarization.

If so, suppose you place a reflecting object (smaller than the signal
beam) in the path of the signal beam, 9 meters from the source of the
signal beam.

Assuming the "signal beam" photons reflecting off the object now have
an opposite polarization (to those not striking the object), would
the corresponding entangled photons in the idler beam now have this
same polarization?

If so, could you place a detector (perhaps after a vertical polarizer)
at 10 meters from the source of the idler beam, and regardless of
whether the initial polarization were vertical or horizontal, detect
the object in the idler beam, without using a coincidence detector?

In order to not use a coincidence counter, I assume I would need an
idler and signal beam in which most of the photons are entangled
photons, versus non-entangled photons.

Presumably this quantum imaging technique would not work, even in
principle, since it implies FTL communication, but I am interested in
why this will not work, and thus what my misunderstandings are.

Relativity.
.

User: "Mathew Orman"

Title: Re: Quantum Imaging 10 Feb 2004 12:38:31 PM
"Jim Lewis" <jim_lewis_11@hotmail.com> wrote in message
news:1fa4bbdf.0402100952.373740e0@posting.google.com...

Would it be possible, at least in principle, to have an idler beam and
a signal beam of polarization-entangled photons, in which most (over
50%) of the entangled photons have the same polarization? You would
not need to know the actual polarization, just that they had the same
polarization.

If so, suppose you place a reflecting object (smaller than the signal
beam) in the path of the signal beam, 9 meters from the source of the
signal beam.

Assuming the "signal beam" photons reflecting off the object now have
an opposite polarization (to those not striking the object), would
the corresponding entangled photons in the idler beam now have this
same polarization?

If so, could you place a detector (perhaps after a vertical polarizer)
at 10 meters from the source of the idler beam, and regardless of
whether the initial polarization were vertical or horizontal, detect
the object in the idler beam, without using a coincidence detector?

In order to not use a coincidence counter, I assume I would need an
idler and signal beam in which most of the photons are entangled
photons, versus non-entangled photons.

Presumably this quantum imaging technique would not work, even in
principle, since it implies FTL communication, but I am interested in
why this will not work, and thus what my misunderstandings are.

Simply,
because QED is FALSE!
Sincerely,
Mathew Orman
www.ultra-faster-than-light.com
www.radio-faster-than-light.com
.
User: "Michael Varney"

Title: Re: Quantum Imaging 10 Feb 2004 03:32:04 PM
"Mathew Orman" <orman@nospam.com> wrote in message
news:c0b86h$av6$1@news.onet.pl...


"Jim Lewis" <jim_lewis_11@hotmail.com> wrote in message
news:1fa4bbdf.0402100952.373740e0@posting.google.com...

Would it be possible, at least in principle, to have an idler beam and
a signal beam of polarization-entangled photons, in which most (over
50%) of the entangled photons have the same polarization? You would
not need to know the actual polarization, just that they had the same
polarization.

If so, suppose you place a reflecting object (smaller than the signal
beam) in the path of the signal beam, 9 meters from the source of the
signal beam.

Assuming the "signal beam" photons reflecting off the object now have
an opposite polarization (to those not striking the object), would
the corresponding entangled photons in the idler beam now have this
same polarization?

If so, could you place a detector (perhaps after a vertical polarizer)
at 10 meters from the source of the idler beam, and regardless of
whether the initial polarization were vertical or horizontal, detect
the object in the idler beam, without using a coincidence detector?

In order to not use a coincidence counter, I assume I would need an
idler and signal beam in which most of the photons are entangled
photons, versus non-entangled photons.

Presumably this quantum imaging technique would not work, even in
principle, since it implies FTL communication, but I am interested in
why this will not work, and thus what my misunderstandings are.


Simply,
because QED is FALSE!

www.crank.net
.



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