On May 30, 6:15 pm, "CWatters"
<colin.watt...@turnersNOSPAMoak.plus.com> wrote:
"PD" <TheDraperFam...@gmail.com> wrote in message
news:1180536742.218931.87270@u30g2000hsc.googlegroups.com...
Hmmm... I'm not sure I agree with your last assertion/guess.
After all, the K-long and K-short are entangled states of two
different mass eigenstates.
I'll have to look up what an eigenstate is - long time since I heard
that
term.
I was thinking...Say you are able to split "something" into to two
entangled
objects, then seperate them by some distance and examine them.
Presumably
there would be reaction forces as the objects were seperated. Would the
two
forces be identical? If not then it would appear you have gained
information
as to which object is going to be more massive when untangled. If they
are
the same then how can the objects untangle themselves into different
masses?
Wouldn't that you had moved mass without a reaction force.
I must be making a mistake.
Perhaps. I believe the problem is the application of an interaction to
the particles in the entangled state, which would *automatically*
collapse the entangled wave function. The entangled two-particle state
exists precisely by virtue of not performing individual measurements
on the particles in the state. See Feynman's description of the two-
slit experiment in The Character of Physical Law.
Yeah I recall that peeking in the box kills the cat or not. So we can't tell
a K-long from a K-short until they collapse.
So if you could somehow liberate a K-long and a K-short from a bit of
matter, what happens to that remaining bit? Does it experience a reaction
force and move off in the opposite direction? I guess the answer must be
that the remaining bit of matter is also entangled with the L-long and short
so that trying to measure which way it moves also collapses the lot?
Yes, I believe that's right.
PD
.
