| Topic: |
Science > Physics |
| User: |
"Paul Ciszek" |
| Date: |
08 Jan 2008 01:04:43 PM |
| Object: |
Question about Radiative Heat Transfer in vacuum |
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
--
Please reply to: | "Any sufficiently advanced incompetence is
pciszek at panix dot com | indistinguishable from malice."
Autoreply is disabled |
.
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| User: "Androcles" |
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| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 01:54:11 PM |
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|
"Paul Ciszek" <nospam@nospam.com> wrote in message
news:fm0hgb$t5i$1@reader2.panix.com...
| Say I have a Dewar, a double-walled container with vacuum between the
| two walls. So far as I can tell, the rate of heat transfer from one
| wall to the other is propotional to (T1^4-T2^4) and the width of the
| gap doesn't figure into it at all. Is this true? What if the gap is
| so narrow that it is on the order of the wavelength of light that makes
| up the peak emission of the hotter surface? Would this have an effect
| on the black body radiation?
Interesting question.
The first part can be dealt with by increasing the gap to
enormous and approximating the flask as a sphere. The
omnidirectional inverse square law applies until the temperatures
of the inner and outer surfaces on each side of the gap reach
equilibrium.
Obviously reaching equilibrium is not gap dependent, however
the time it takes to do so (rate of heat transfer) may be.
The reason being that if the area to be heated (or cooled)
by radiation from the inner surface is quadrupled it will
take four times longer for it to match the inner temperature.
As to the second part:
The wavelength of heat is longer than the wavelength of light.
If you put your hand near an ordinary incandescent light bulb
you'll feel the heat from the glass bulb, even if vacuum
and not inert gas filled. The gap between the glass and
the tungsten filament is considerably greater than the
gap in a Dewar flask.
"Black body" is a misnomer, the sun is a black body radiator in
the context of radiation and energy. It will radiate at ALL
wavelengths, but one doesn't call it "black".
http://www.egglescliffe.org.uk/physics/astronomy/blackbody/bbody.html
.
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| User: "Llanzlan Klazmon the 15th" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 04:19:00 PM |
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|
"Androcles" <Engineer@hogwarts.physics_c> wrote in news:DxQgj.95776
$036.68308@fe1.news.blueyonder.co.uk:
"Paul Ciszek" <nospam@nospam.com> wrote in message
news:fm0hgb$t5i$1@reader2.panix.com...
| Say I have a Dewar, a double-walled container with vacuum between the
| two walls. So far as I can tell, the rate of heat transfer from one
| wall to the other is propotional to (T1^4-T2^4) and the width of the
| gap doesn't figure into it at all. Is this true? What if the gap is
| so narrow that it is on the order of the wavelength of light that makes
| up the peak emission of the hotter surface? Would this have an effect
| on the black body radiation?
Interesting question.
The first part can be dealt with by increasing the gap to
enormous and approximating the flask as a sphere. The
omnidirectional inverse square law applies until the temperatures
of the inner and outer surfaces on each side of the gap reach
equilibrium.
Obviously reaching equilibrium is not gap dependent, however
the time it takes to do so (rate of heat transfer) may be.
The reason being that if the area to be heated (or cooled)
by radiation from the inner surface is quadrupled it will
take four times longer for it to match the inner temperature.
As to the second part:
The wavelength of heat is longer than the wavelength of light.
If you put your hand near an ordinary incandescent light bulb
you'll feel the heat from the glass bulb, even if vacuum
and not inert gas filled. The gap between the glass and
the tungsten filament is considerably greater than the
gap in a Dewar flask.
"Black body" is a misnomer, the sun is a black body radiator in
the context of radiation and energy. It will radiate at ALL
wavelengths, but one doesn't call it "black".
http://www.egglescliffe.org.uk/physics/astronomy/blackbody/bbody.html
Read Uncle Al's answer for the correct explanation. As usual Androcles
provides a useless response.
.
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| User: "Androcles" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 04:38:13 PM |
|
|
"Llanzlan Klazmon the 15th" <Klazmon@llurdiaxorb.govt> wrote in message
news:Xns9A20731EA1951Klazmonllurdiaxorbgo@203.97.37.6...
| "Androcles" <Engineer@hogwarts.physics_c> wrote in news:DxQgj.95776
| $036.68308@fe1.news.blueyonder.co.uk:
|
| >
| > "Paul Ciszek" <nospam@nospam.com> wrote in message
| > news:fm0hgb$t5i$1@reader2.panix.com...
| >| Say I have a Dewar, a double-walled container with vacuum between the
| >| two walls. So far as I can tell, the rate of heat transfer from one
| >| wall to the other is propotional to (T1^4-T2^4) and the width of the
| >| gap doesn't figure into it at all. Is this true? What if the gap is
| >| so narrow that it is on the order of the wavelength of light that makes
| >| up the peak emission of the hotter surface? Would this have an effect
| >| on the black body radiation?
| >
| > Interesting question.
| > The first part can be dealt with by increasing the gap to
| > enormous and approximating the flask as a sphere. The
| > omnidirectional inverse square law applies until the temperatures
| > of the inner and outer surfaces on each side of the gap reach
| > equilibrium.
| > Obviously reaching equilibrium is not gap dependent, however
| > the time it takes to do so (rate of heat transfer) may be.
| > The reason being that if the area to be heated (or cooled)
| > by radiation from the inner surface is quadrupled it will
| > take four times longer for it to match the inner temperature.
| >
| > As to the second part:
| > The wavelength of heat is longer than the wavelength of light.
| > If you put your hand near an ordinary incandescent light bulb
| > you'll feel the heat from the glass bulb, even if vacuum
| > and not inert gas filled. The gap between the glass and
| > the tungsten filament is considerably greater than the
| > gap in a Dewar flask.
| > "Black body" is a misnomer, the sun is a black body radiator in
| > the context of radiation and energy. It will radiate at ALL
| > wavelengths, but one doesn't call it "black".
| > http://www.egglescliffe.org.uk/physics/astronomy/blackbody/bbody.html
| >
|
| Read Uncle Al's answer for the correct explanation. As usual Androcles
| provides a useless response.
|
*****.
*plonk*
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| User: "Douglas Eagleson" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 02:29:38 PM |
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|
On Jan 8, 11:04=A0am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. =A0So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. =A0Is this true? =A0What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? =A0Would this have an effect
on the black body radiation?
--
Please reply to: =A0 =A0 =A0 =A0 =A0 =A0| "Any sufficiently advanced incom=
petence is
pciszek at panix dot com =A0 =A0| =A0indistinguishable from malice."
Autoreply is disabled =A0 =A0 =A0 |
A soliton as the vibration was allowed to model temperature. And to
alter the gap to conductive as opposed to radiative was the possible
implication of gap minimization.
At a certain small 1 angstrom like gap, the solitons will just jump to
the second dewar wall. And the difference was the result. A
conductive transfer was to alter the black body. A complete loss of
vacuum is the outcome, making the radiative outer wall now a new
spectrum.
A certain mass would cause the new spectrum.
.
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| User: "Uncle Al" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 03:00:28 PM |
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|
Douglas Eagleson wrote:
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
--
Please reply to: | "Any sufficiently advanced incompetence is
pciszek at panix dot com | indistinguishable from malice."
Autoreply is disabled |
A soliton as the vibration was allowed to model temperature. And to
alter the gap to conductive as opposed to radiative was the possible
implication of gap minimization.
At a certain small 1 angstrom like gap, the solitons will just jump to
the second dewar wall. And the difference was the result. A
conductive transfer was to alter the black body. A complete loss of
vacuum is the outcome, making the radiative outer wall now a new
spectrum.
A certain mass would cause the new spectrum.
Fails the Turing test.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2
.
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| User: "Douglas Eagleson" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 03:03:05 PM |
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|
On Jan 8, 1:00=A0pm, Uncle Al <Uncle...@hate.spam.net> wrote:
Douglas Eagleson wrote:
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. =A0So far as I can tell, the rate of heat transfer from one=
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. =A0Is this true? =A0What if the gap=
is
so narrow that it is on the order of the wavelength of light that make=
s
up the peak emission of the hotter surface? =A0Would this have an effe=
ct
on the black body radiation?
--
Please reply to: =A0 =A0 =A0 =A0 =A0 =A0| "Any sufficiently advanced i=
ncompetence is
pciszek at panix dot com =A0 =A0| =A0indistinguishable from malice."
Autoreply is disabled =A0 =A0 =A0 |
A soliton as the vibration was allowed to model temperature. =A0And to
alter the gap to conductive as opposed to radiative was the possible
implication of gap minimization.
At a certain small 1 angstrom like gap, the solitons will just jump to
the second dewar wall. =A0And the difference was the result. =A0A
conductive transfer was to alter the black body. =A0A complete loss of
vacuum is the outcome, making the radiative outer wall now a new
spectrum.
A certain mass would cause the new spectrum.
Fails the Turing test.
--
Uncle Alhttp://www.mazepath.com/uncleal/
=A0(Toxic URL! Unsafe for children and most mammals)http://www.mazepath.co=
m/uncleal/lajos.htm#a2- Hide quoted text -
- Show quoted text -
you are clueless ain't ya.
.
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| User: "Douglas Eagleson" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 02:52:40 PM |
|
|
On Jan 8, 12:29=A0pm, Douglas Eagleson <eaglesondoug...@yahoo.com>
wrote:
On Jan 8, 11:04=A0am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. =A0So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. =A0Is this true? =A0What if the gap i=
s
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? =A0Would this have an effect=
on the black body radiation?
--
Please reply to: =A0 =A0 =A0 =A0 =A0 =A0| "Any sufficiently advanced inc=
ompetence is
pciszek at panix dot com =A0 =A0| =A0indistinguishable from malice."
Autoreply is disabled =A0 =A0 =A0 |
A soliton as the vibration was allowed to model temperature. =A0And to
alter the gap to conductive as opposed to radiative was the possible
implication of gap minimization.
At a certain small 1 angstrom like gap, the solitons will just jump to
the second dewar wall. =A0And the difference was the result. =A0A
conductive transfer was to alter the black body. =A0A complete loss of
vacuum is the outcome, making the radiative outer wall now a new
spectrum.
A certain mass would cause the new spectrum.
fyi, a mass is inverted in the black cavity causing the finite
radiation to appear in relation to the cavity diameter. A perfect
symmetry.
frequency of the body as a mass obeys a debated frequency law. Most
methods fail to follow the data, ergo I debate the true issue not a
pap empreical formula. Intensity versus frequnecy i.e. the data.
A bodies temperature in relation to its mass is the issue. How does a
uncorrelated transfer effect? Remember a soliton is a simple
correlated dimension of heat.
So uncorellated as opposed to correlated solitons define temeprature.
Solid state physics is like this when it inverts a space dimension to
the effect. i.e. a mass to a matter. SO a round disk may have
harmonic exictations, like a hydrogen atom.
NON-harmonic state was to define the uncorrelated heat quanta.
Allowing the basic harmonic to describe temeprature in solid state as
radiative transfer. A sphere of mass was to transfer according to the
intensity plot. intensity versus frequency.
A one-dimensional osscilator then states the distribution. Look up
any osscilator and use the frequnecy distribution of the plain old
Schrodinger equation.
A nonconventional quantum theory is stated, but real data fitting.
.
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| User: "tadchem" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 04:15:15 PM |
|
|
On Jan 8, 3:29 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
--
Please reply to: | "Any sufficiently advanced incompetence is
pciszek at panix dot com | indistinguishable from malice."
Autoreply is disabled |
A soliton as the vibration was allowed to model temperature.
You haven't got a clue what a 'soliton' is, do you?
http://en.wikipedia.org/wiki/Soliton
Since the space between the walls of the Dewar is (by assumption) a
vacuum, it is both non-dispersive and linear. Under these conditions
'solitons' (wave packets comprised of multiple interacting wavelengths
of differing amplitudes) are moot.
Haugtrold...
Tom Davidson
Richmond, VA
.
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| User: "Douglas Eagleson" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 04:19:38 PM |
|
|
On Jan 8, 2:15=A0pm, tadchem <tadc...@comcast.net> wrote:
On Jan 8, 3:29 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. =A0So far as I can tell, the rate of heat transfer from one=
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. =A0Is this true? =A0What if the gap=
is
so narrow that it is on the order of the wavelength of light that make=
s
up the peak emission of the hotter surface? =A0Would this have an effe=
ct
on the black body radiation?
--
Please reply to: =A0 =A0 =A0 =A0 =A0 =A0| "Any sufficiently advanced i=
ncompetence is
pciszek at panix dot com =A0 =A0| =A0indistinguishable from malice."
Autoreply is disabled =A0 =A0 =A0 |
A soliton as the vibration was allowed to model temperature.
You haven't got a clue what a 'soliton' is, do you?http://en.wikipedia.org=
/wiki/Soliton
Since the space between the walls of the Dewar is (by assumption) a
vacuum, it is both non-dispersive and linear. =A0Under these conditions
'solitons' (wave packets comprised of multiple interacting wavelengths
of differing amplitudes) are moot.
Haugtrold...
Tom Davidson
Richmond, VA- Hide quoted text -
- Show quoted text -
a vibration causes the soliton to exist, the propagation follows the
appearance. So look up the appearance on wiki. And they are just
another quanta. They appear like all other in fifth order form of all
interaction. SO I understand the question of ignorance. And you are.
.
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| User: "tadchem" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
09 Jan 2008 02:50:56 AM |
|
|
On Jan 8, 5:19 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:
On Jan 8, 2:15 pm, tadchem <tadc...@comcast.net> wrote:
On Jan 8, 3:29 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
--
Please reply to: | "Any sufficiently advanced incompetence is
pciszek at panix dot com | indistinguishable from malice."
Autoreply is disabled |
A soliton as the vibration was allowed to model temperature.
You haven't got a clue what a 'soliton' is, do you?http://en.wikipedia.org/wiki/Soliton
Since the space between the walls of the Dewar is (by assumption) a
vacuum, it is both non-dispersive and linear. Under these conditions
'solitons' (wave packets comprised of multiple interacting wavelengths
of differing amplitudes) are moot.
Haugtrold...
Tom Davidson
Richmond, VA- Hide quoted text -
- Show quoted text -
a vibration causes the soliton to exist,
AHA! You appear to be confounding the "soliton" (multi-component wave
packet) with a "phonon" (a single frequency *sound* wave). Phonons
are representations of the mechanical vibrations of an object, and are
very useful in discussing heat *conduction*. Phonons cannot exist in
a vacuum.
the propagation follows the
appearance. So look up the appearance on wiki. And they are just
another quanta. They appear like all other in fifth order form of all
interaction. SO I understand the question of ignorance. And you are.
The topic is *electromagnetic* radiation - i.e. "photons", the
creation of which requires a change of the energy state of an electric
dipole. Photons have quantized angular momentum and a single
frequency. Solitons lack both.
Tom Davidson
Richmond, VA
.
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| User: "Douglas Eagleson" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
09 Jan 2008 08:35:16 AM |
|
|
On Jan 9, 12:50=A0am, tadchem <tadc...@comcast.net> wrote:
On Jan 8, 5:19 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:
On Jan 8, 2:15 pm, tadchem <tadc...@comcast.net> wrote:
On Jan 8, 3:29 pm, Douglas Eagleson <eaglesondoug...@yahoo.com> wrote:=
On Jan 8, 11:04 am, (Paul Ciszek) wrote:
Say I have a Dewar, a double-walled container with vacuum between =
the
two walls. =A0So far as I can tell, the rate of heat transfer from=
one
wall to the other is propotional to (T1^4-T2^4) and the width of t=
he
gap doesn't figure into it at all. =A0Is this true? =A0What if the=
gap is
so narrow that it is on the order of the wavelength of light that =
makes
up the peak emission of the hotter surface? =A0Would this have an =
effect
on the black body radiation?
--
Please reply to: =A0 =A0 =A0 =A0 =A0 =A0| "Any sufficiently advanc=
ed incompetence is
pciszek at panix dot com =A0 =A0| =A0indistinguishable from malice=
.."
Autoreply is disabled =A0 =A0 =A0 |
A soliton as the vibration was allowed to model temperature.
You haven't got a clue what a 'soliton' is, do you?http://en.wikipedia=
..org/wiki/Soliton
Since the space between the walls of the Dewar is (by assumption) a
vacuum, it is both non-dispersive and linear. =A0Under these condition=
s
'solitons' (wave packets comprised of multiple interacting wavelengths=
of differing amplitudes) are moot.
Haugtrold...
Tom Davidson
Richmond, VA- Hide quoted text -
- Show quoted text -
a vibration causes the soliton to exist,
AHA! =A0You appear to be confounding the "soliton" (multi-component wave
packet) with a "phonon" (a single frequency *sound* wave). =A0Phonons
are representations of the mechanical vibrations of an object, and are
very useful in discussing heat *conduction*. =A0Phonons cannot exist in
a vacuum.
the propagation follows the
appearance. =A0So look up the appearance on wiki. =A0And they are just
another quanta. =A0They appear like all other in fifth order form of all=
interaction. SO I understand the question of ignorance. =A0And you are.
The topic is *electromagnetic* radiation - i.e. "photons", the
creation of which requires a change of the energy state of an electric
dipole. =A0Photons have quantized angular momentum and a single
frequency. =A0Solitons lack both.
Tom Davidson
Richmond, VA- Hide quoted text -
- Show quoted text -
I never said solitons ARE vibration did I. Cause and Effect must
confuse you. How does heat causes em. WHY does a black body radiate?
You need to answer that to do what you want to do. Having a function
stating the fact is not the cause to em emission of the body.
WHERE in the solid does the electric field commence existence.
Solitons are the correct theory of correlated heat. For a reason, and
the meaning of phonon in evident relation to soliton was the two body
vibration, just like heat. A double quanta harmonic was the
distinction between the two only. A well wall therefor caused the
soliton whereas a wavefunction osscilation caused the phonon to exist.
IN first order diaper physicist a sound as state of well is real. A
temperature correlated function may propagate in air. NOW you kno whow
submarines are seen. Propagation as a real function appears the signal
in modern sonars. And the ping ping diaper guy gets to figure out
where he gets his electric field form.
.
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| User: "Uncle Al" |
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| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 01:34:02 PM |
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|
Paul Ciszek wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
Surface emissivity matters, hence silvering.
Gap effects depend on geometry. Two infinite in extent parallel
planes don't care about gap (until lightspeed vs. separation distance
becomes important). If the gap approaches wavelength you have an
etalon cavity - and certain wavelength windows will be excluded
depending upon reflectivity. Narrow gaps beg the question of what
emission means.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2
.
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| User: "Sam Wormley" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
08 Jan 2008 02:17:03 PM |
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|
Paul Ciszek wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true?
If the width was 1 AU....
What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
.
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| User: "Andy Resnick" |
|
| Title: Re: Question about Radiative Heat Transfer in vacuum |
09 Jan 2008 12:01:01 PM |
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|
Paul Ciszek wrote:
Say I have a Dewar, a double-walled container with vacuum between the
two walls. So far as I can tell, the rate of heat transfer from one
wall to the other is propotional to (T1^4-T2^4) and the width of the
gap doesn't figure into it at all. Is this true? What if the gap is
so narrow that it is on the order of the wavelength of light that makes
up the peak emission of the hotter surface? Would this have an effect
on the black body radiation?
In heat transfer calculations (and radiometry, as well), there's
something called the "configuration factor" which handles the relevant
geometry:
http://www.me.utexas.edu/~howell/intro.html
For your case the configuration factor is simply 1.
In terms of the spacing, radiative transfer is a continuum concept, and
so all length scales must be larger than the size of atoms or wavelengths.
The quantum optics of microcavities is very interesting, but I don't
know of anyone who has tried to recover the continnum limit in regards
to thermal transport.
--
Andrew Resnick, Ph.D.
Department of Physiology and Biophysics
Case Western Reserve University
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