From Mark:
The equations of motion for r(t), v(t) are still the same
r'(t) = v(t), v'(t) = -kr(t)/|r(t)|^3
From Shmuel (Seymour J.) Metz (spamtrap@library.lspace.org.invalid):
No,
Yes. Note the comment in particular (you deleted).
Hence Hydrogen SO(4).
This is standard material.
they are [sic] replaced by Schrodinger's Equation
No. They are the SAME as Schroedinger's Equation.
More precisely, it's the more fundamental of the two pictures.
The Schroedinger equation only emerges as a theorem late in the
picture (and by a chain that does not apply in the general
context in a general spacetime manifold); and the picture of
a (pure) state as a Schroedinger wave function is only a
theorem (Stone von Neumann), not an axiom or definition.
Technically, the definition of a state is a linear, positive
function over the C* algebra of observables, which yields
the value 1, when applied to the algebra's unit element. Not
a "wave function".
.
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