| Topic: |
Science > Physics |
| User: |
"gravity" |
| Date: |
13 Oct 2005 10:09:38 PM |
| Object: |
Re: relativity of time. |
"francisco" <paco1955@sbcglobal.net> wrote in message
news:JLB3f.1034$dO2.114@newssvr29.news.prodigy.net...
let A = an observer. and let B = another observer.
let B stand still next to A. let A carry a watch. and let B carry a watch.
let the watch of A be synchronized with the watch of B. in other words,
let A read both his watch and the watch of B. and let A determine that 1 s
by his own watch = 1 s by the watch of B.
now let B move forward at a constant specified speed close to the speed of
light. and let A remain standing still.
now if A is able to read the watch of B, he will observe that (at that
specified speed in which B is moving) 2 s by his own watch = 1 s by the
watch of B. in other words, A will observe that 1 s by the watch of B is
longer than 1 s by his own watch (2 s by the watch of A = 1 s by the watch
of B).
it is the same as if we say that 2 pesos = 1 dollar. in other words, it
takes two pesos to make one dollar. so, the same applies in this case of
relative time: according to observer A, it takes 2 s by his own watch to
make 1 s by the watch of B.
.
|
|
| User: "Sue..." |
|
| Title: Re: relativity of time. |
14 Oct 2005 01:47:27 AM |
|
|
gravity wrote:
"francisco" <paco1955@sbcglobal.net> wrote in message
news:JLB3f.1034$dO2.114@newssvr29.news.prodigy.net...
let A = an observer. and let B = another observer.
let B stand still next to A. let A carry a watch. and let B carry a watch.
let the watch of A be synchronized with the watch of B. in other words,
let A read both his watch and the watch of B. and let A determine that 1 s
by his own watch = 1 s by the watch of B.
now let B move forward at a constant specified speed close to the speed of
light. and let A remain standing still.
now if A is able to read the watch of B, he will observe that (at that
specified speed in which B is moving) 2 s by his own watch = 1 s by the
watch of B. in other words, A will observe that 1 s by the watch of B is
longer than 1 s by his own watch (2 s by the watch of A = 1 s by the watch
of B).
it is the same as if we say that 2 pesos = 1 dollar. in other words, it
takes two pesos to make one dollar. so, the same applies in this case of
relative time: according to observer A, it takes 2 s by his own watch to
make 1 s by the watch of B.
Neither observer sees the other getting a free lunch but
one is seen to swap his watch for the train conductor's
sack lunch.
<< invariance with respect to time translation gives the well known law
of conservation of energy; >>
http://en.wikipedia.org/wiki/Noether's_theorem
http://farside.ph.utexas.edu/teaching/jk1/lectures/node13.html
http://arxiv.org/abs/physics/0204034
Sue...
.
|
|
|
|

|
Related Articles |
|
|