| Topic: |
Science > Physics |
| User: |
"Edward Green" |
| Date: |
03 Nov 2006 07:56:57 PM |
| Object: |
Re: Something special about the event horizon |
Ben Rudiak-Gould wrote:
Edward Green wrote:
Ben Rudiak-Gould wrote:
This is also true of a Rindler horizon. You need to specify what you mean by
"the outside point" -- it sounds coordinate-dependent.
In hindsight I should have left out the second sentence of that paragraph.
The first sentence is the important one.
Perhaps. It is another parallel in the back and forth between
analogies in flat spacetime to phenomena in curved spacetime, and one
that happens -- if we are reduced to "well, it could be like this, but
it could also be like this, while on the other hand ..." to fall on
your side of the balance beam.
But really sir ... you are quite impossible: "the" outside point is
clearly "an outside point" from the first paragraph (manifested by the
reference "sequence of suspended ropes")
It's equally problematic there, but I didn't bring it up because it's
overshadowed by the other problem with that test.
and "an" outside point means
just that -- a completely arbitrary point outside the event horizon. I
presume "horzon" and "outside" are coordinate free concepts.
Yes, but "point" isn't. Unless you mean "spacetime point", but you can't
mean that because you're talking about radar return times.
Many are the times I've accidentally left some side door open in a
post, realized it afterwards, and sure enough found the reader
wandering about in the broom closet. At the same time I'm perplexed by
your perplexity. Surely it's obvious I meant a spatial point -- and
before you lecture me on the meaninglessness of that concept, recall we
are in a static geometry, where we can return to the "same" spatial
point as often as we like along our worldline.
Perhaps you think that a "static spatial point" is a coordinate
dependent concept? I disagree vigorously. The only exception I can
think of (I'm cheating -- I though of this until later, and inserted
it), is the special static geometry of flat spacetime. There indeed a
"point" (static spatial point) has no natural meaning, since other
"static" points may be flying by an arbitrary relative velocities. I
guess you were thinking of this, which perhaps is why you otherwise
inexplicably regard my unqualified use of "point" as problematic.
Flat spacetime may be a kind of analytically limiting case -- like the
extension of fourier series over finite intervals to the "limit" of
fourier integrals -- which is both natural and pathogenic. I'm not
sure of this observations full significance to our discussion, but I
think it may be deep.
The real problem is that there's no way to tell what "a point outside the
event horizon" or even "a worldline outside the event horizon" means until
after you know where the event horizon is, but the purpose of your test is
to characterize the event horizon in the first place.
I find this objection bizarre. You stated that there is nothing very
special about the horizon -- other than the behavior of the Killing
vector, and some condition on observability -- and that no coordinate
independent infinities lurk nearby. I claim the radar return time
refutes both these arguments. I take the point of view that the
spacetime geometry is a given and that I can use that given geometry
freely in formulating my reply. You want me to take the view, I think,
that I'm plunked down in an unknown spacetime, and must begin piecing
its geometry together by operational tests.
I'm not sure why this is necessary, but Ok, let's look at that
question.
Feeling out the local spacetime geometry is a complicated business, but
I take it if we are plopped into a static geometry, we can, given the
ability to carry out measurements over a local, but not too local
region (not pointlike), discover that we are in a static spacetime.
Assume for now the spacetime is not flat. We will simultaneously
establish, perhaps, that we are moving wrt the static background. Then
we may being firing our rockets sufficiently to maintain a fixed
position in the time invariant spatial geometry. Once we are in a
static position, we may identify "down" as the opposite of the
direction we are accelerating in to hold ourselves in place.
Identifying "down", we may then begin placing meter sticks end to end
in that direction, with reflectors attached at certain lengths.
If there happens to be an event horizon below us, we are going to have
problems placing some finite meter stick (as I now know); I guess we
keep dropping it. So at that point -- oops... I mean "juncture" -- we
place, say, half a meter stick, or a third, or whatever we can manage.
At this same state of affairs, we notice the radar return times to our
fixed mother ship are growing large very quickly with length. In fact,
we will find that by adding some finite additional increment of stick,
we can make the return time grow as large as we like.
This entire construction sounds to me like a coordinate independent
operation characterization of an infinity associated with something
that begins to look like an event horizon.
If, on the other hand, our initial determinations were that the
spacetime were flat, we could begin unfolding our infinite folding
ruler, as before, and again measure an unbounded increasing series of
return times -- the difference being, in this case, the amount of ruler
we can extend is unbounded also. I guess in this case I would like to
say we have a "coordinate independent infinity" also -- the usual one.
An objection that can be made:
"We never measure 'infinity', but only an increasing sequence of
positive numbers."
This is more a kind of statement of the halting problem, or the
impossibility of "measuring an infinity" in general, than a specific
objection to characterizing this infinity. Of course we can never be
sure that, measuring a sequence of ever increasing numbers which do not
seem to approach an asymptote, that the sequence will not stop growing
with the next number or the one after it. At best we can say that "the
postulate of an infinity has not yet been falsified".
Need I say I would find this objection silly?
Let's fire up our spaceship and go event-horizon hunting. Event horizons
always move toward you at the speed of light (until you fall through, then
they move away at the speed of light). So our first order of business had
better be to fire the rockets to avoid falling in. Which direction? Well, we
don't know yet, but let's try thataway. Now as soon as we start
accelerating, we'll find that there's an event horizon below us which passes
your radar-time test, *whether or not there's a black hole nearby*.
Accelerating makes a Rindler horizon, and Rindler horizons have the same
properties as black hole horizons. In fact you can choose any approaching
null surface whatsoever, and as long as you avoid falling through it, it'll
pass your test.
Now that's an interesting argument. Essentially you are saying that my
first assertion is false -- that we _can't_ survey the local spacetime
geometry by kind of poking around with scout ships and lasers and dust
clouds. Maybe, worse, we can't even survey it when it is static,
finding out in the process that it is static, and hold ourselves in
(now meaningful) spatial position. If we could carry out this survey,
and if we just turned off the rocket for a minute, we could discover
that not only is the spacetime static but flat, and we wouldn't be
fooled by the dumb old Rindler horizon for a minute, recognizing it for
what it is.
I think we can infer the local geometry, at least when it is static.
Some years back, when giants roamed sci.physics, there was reference to
a published paper, or at least a respectable pre-print, asserting that
(static?) gravitational fields were in fact distinguishable from
effects associated with an accelerating observer in flat spacetime
_even_ in the limiting case of a gravitational field with zero spatial
curvature. You will agree this assertion is of some interest here.
(I've tried to search the archive, but I've been unable to find the
reference again.) You in effect assert the contrary -- that the
uniformly accelerating observer in flat spacetime _cannot_ tell the
difference between his situation and a gravitational field of an
"infinitely large" black hole geometry -- that's why he can't tell the
difference (you imply) between his own Rindler horizon and a black hole
in the ground.
I remember that the paper was over my head, but even now I can think of
some supporting arguments based on low brow reasoning. For example...
if we were outside the event horizon of a black hole so large that we
couldn't detect the spatial curvature, then we would find we had
manuvering room in how far (as measured by a finite extension of meter
sticks -- I bet you're sorry you showed me that) we were from the
horizon at a constant proper acceleration g: if the horizon is
essentially flat, gravitational acceleration is essentially constant.
But we would have no such freedom with the Rindler horizon, since its
distance behind us depends only on g: what else could it possibly
depend on?
[...] so is the finite proper length
filament somehow a mapping of an infinitely long filament whose
"spatial acceleration" (variation of velocity with position) is strong
enough that the integral of the relativistically contracted length is
finite, again into a curved spacetime which hides the effective
relative velocity in the curvature -- and also contrives to allow a
static filament whose segments are effectively moving at different
velocities.
No, it's just a plain, ordinary finite distance. Really truly it is.
That was a completely unedited flight of speculative fancy. However,
while I don't present it as a close argument, I'm unconvinced that it
might not correspond to a close argument.
Physics
near the event horizon is just like physics everywhere else.
Except of course for that pesky Killing vector thing.
You're intent
on making it look weird by viewing it in a weird way, but as you've pointed
out yourself, even good old Minkowski space is weird if you admit
sufficiently weird worldlines.
Well, the longer we discuss this, the more I see many things hinging on
a series of parallels between behavior in Minkowski space, as you
prefer to call it, and analogous behaviors in more general spacetimes.
Not all the parallels seem to urge us in the same direction: we can
either focus on the Rindler horizon, and conclude that that looks
plenty weird -- though we know its a kind of observational artifact in
flat spacetime -- and hence convince ourselves that maybe the
Schwarzschild horizon isn't all that weird either, or else we can focus
on the trajectories which "reach infinity" in finite proper time in
Minkowski space -- though we would tend to think they never get there
-- and convince ourselves that maybe crossing the event horizon never
happens either. I've mentioned that the good old (and relevant) Zeno's
paradox can be looked at from two ends also (Zeno and Onez?), though
the tradition apparently only includes one reading.
That's a kind of ethically relativistic "I'm ok, you're ok" kind of
version, though I still think I'm just a little more ok here ;-) I
deny I'm looking at things in a "weird way" -- perhaps I'm just looking
at things in a fresh way: I am in fact a tyro, but not a completely
unsophisticated one. The Rindler horizon thing is a standard analogy
-- I see -- known by many -- but the aberrant trajectories I happened
to discover independently don't seem to be all that well known, nor
traditionally discussed. Hence they don't seem to carry equal weight
in the philosophically tinged discussions touching on this topic --
though I don't see why not.
There's nothing weird in the vicinity of a
black hole event horizon that you couldn't find pretty much anywhere else in
the universe.
Still disagree.
If you expand your viewpoint to take in the entire black hole, or even just
an equatorial slice through it, then you can probably find a working
characterization of the event horizon. But that's no longer a local test,
because the size of the black hole sets a lower bound on the size of your
laboratory.
I indeed took it as a given that we could simply take the entire black
hole geometry as a given in looking for interesting operational tests.
You apparently are interested in a slightly different question.
However, adding your requirements, it still seems to me that the
operational characterization can be carried out. Here's the meta-code:
Survey local spacetime geometry
If geometry is flat, then stop: no nearby horizon
If geometry is nonstatic, stop: we are not outside a pure
Schwarzschild horizon
Else, stop motion wrt static spatial geometry by proper acceleration
Find "down"
Extend array of meter sticks with reflectors
If return time and proper length both diverge, we are facing a
"normal" infinity
If return time diverges while proper length remains finite, we are
facing a presumptive bh
If proper length diverges while return time remains finite... ???
That would be weird. ;-)
.
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| User: "Sorcerer" |
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| Title: Re: Something special about the event horizon |
03 Nov 2006 08:04:34 PM |
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"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
Set 1, 2-0 to Androcles
Game 3 in progress.
Androcles
.
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| User: "Eric Gisse" |
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| Title: Re: Something special about the event horizon |
03 Nov 2006 10:16:51 PM |
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Sorcerer wrote:
"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
Set 1, 2-0 to Androcles
Game 3 in progress.
Androcles
Oh boy.
I wonder what Androcles will win when Androcles eventually proclaims
himself to be the winner of the game only Androcles is playing.
.
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| User: "Dirk Van de moortel" |
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| Title: Re: Something special about the event horizon |
04 Nov 2006 06:56:28 AM |
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"Eric Gisse" <jowr.pi@gmail.com> wrote in message news:1162613811.831450.201880@m7g2000cwm.googlegroups.com...
Sorcerer wrote:
"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
Set 1, 2-0 to Androcles
Game 3 in progress.
Androcles
Oh boy.
I wonder what Androcles will win when Androcles eventually proclaims
himself to be the winner of the game only Androcles is playing.
He can win the Usenet Autist of the Year Award.
Dirk Vdm
.
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| User: "Daryl McCullough" |
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| Title: Re: Something special about the event horizon |
04 Nov 2006 01:18:01 PM |
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Edward Green says...
Ben Rudiak-Gould wrote:
Ben Rudiak-Gould wrote:
This is also true of a Rindler horizon. You need to specify what
you mean by "the outside point" -- it sounds coordinate-dependent.
Perhaps. It is another parallel in the back and forth between
analogies in flat spacetime to phenomena in curved spacetime, and one
that happens -- if we are reduced to "well, it could be like this, but
it could also be like this, while on the other hand ..." to fall on
your side of the balance beam.
I think it's more than an analogy---the Rindler spacetime is a limiting
case of the Schwarzschild spacetime.
Consider two different situations:
(1) A rocket is hovering a small distance above a very massive
black hole. (Schwarzschild spacetime)
(2) A rocket is undergoing constant proper acceleration in a straight
line in flat spacetime. (Rindler spacetime)
Every experiment (at least those mentioned so far) involving lowering
ropes or sending light signals or whatever applies equally well to
both situations. The two situations are locally indistinguishable.
But in the case of Rindler spacetime, there is clearly no physically
meaningful, observer-independent event horizon. So clearly, if there
is some sense in which the Schwarzschild horizon is more real than
the Rindler horizon, then it's not revealed by these thought
experiments.
All the familiar properties of the event horizon in Schwarzschild
spacetime also hold for the event horizon at x=0 in Rindler spacetime.
For example:
1. If you drop an object in the Rindler spacetime, then its
position will asymptotically approach the event horizon as
t --> infinity, but will never reach it for any finite value of t.
2. The delay for a signal to travel from height x1 to height x2 goes
to infinity as x1 approaches the event horizon.
3. The force necessary to keep an object stationary (at a constant
value of x) goes to infinity as x approaches the event horizon.
4. In spite of all this, a freefalling observer can reach the event
horizon in a finite amount of proper time.
5. The stresses on a freefalling observer remain bounded as the
observer approaches the event horizon.
6. An observer on one side of the event horizon can never
send a signal to a stationary observer on the other side.
Mathematically, we can start with the Schwarzschild spacetime
(ignoring angular coordinates for simplicity)
ds^2 = (1-2m/r) dt^2 - 1/(1-2m/r) dr^2
Now, transform from coordinate r to coordinate x related
to r via:
x = square-root(8m (r-2m))
So the event horizon at r=2m becomes, in these new coordinates,
an event horizon at x=0.
In terms of x we have:
ds^2 = (x^2/16m^2)/(1 + x^2/16m^2) dt^2
- (1+x^2/16m^2) dx^2
If x/4m is much less than 1, then this is approximately the same
as
ds^2 = (x^2/16m^2) dt^2 - dx^2
which is the Rindler spacetime.
Perhaps you think that a "static spatial point" is a coordinate
dependent concept?
Yes, it certainly is. That's what relativity is all about.
An object that is at rest according to one observer is in
motion according to another observer. Neither is more correct
than the other.
I disagree vigorously.
The vigor of your disagreement doesn't make it more correct.
From the point of view of General Relativity, a "static spatial
point" just means a worldline x^u(s) such that the spatial
components of the proper velocity dx^u/ds are all zero. But
that's certainly a coordinate-dependent definition.
The only exception I can think of (I'm cheating -- I though
of this until later, and inserted it), is the special static
geometry of flat spacetime. There indeed a "point" (static
spatial point) has no natural meaning, since other "static"
points may be flying by an arbitrary relative velocities.
That's exactly why the notion of a static point makes no sense.
Why do you think it makes more sense when spacetime is curved?
I find this objection bizarre. You stated that there is nothing very
special about the horizon -- other than the behavior of the Killing
vector, and some condition on observability -- and that no coordinate
independent infinities lurk nearby. I claim the radar return time
refutes both these arguments.
Yes, you claim that, but it's wrong. The analogous
experimental setup in Rindler spacetime gives the same qualitative
answers. (The precise details are slightly different, because the
variation of the force needed to hover at a constant height is
different for the two spacetimes.)
If there happens to be an event horizon below us, we are going to have
problems placing some finite meter stick (as I now know); I guess we
keep dropping it. So at that point -- oops... I mean "juncture" -- we
place, say, half a meter stick, or a third, or whatever we can manage.
At this same state of affairs, we notice the radar return times to our
fixed mother ship are growing large very quickly with length. In fact,
we will find that by adding some finite additional increment of stick,
we can make the return time grow as large as we like.
The Rindler spacetime has exactly this characteristics. You have
a spacetime that is undergoing constant proper acceleration. You
start lowering a meter stick in the opposite direction from the
direction the spaceship is accelerating. You time how long it takes
for radar to travel from the ship to the end of the stick and back.
You notice that there is a point beyond which this time diverges.
That's all true of a constantly accelerating ship in flat spacetime.
If, on the other hand, our initial determinations were that the
spacetime were flat, we could begin unfolding our infinite folding
ruler, as before, and again measure an unbounded increasing series of
return times -- the difference being, in this case, the amount of ruler
we can extend is unbounded also.
No, that's not true. If you do the analogous thing in flat
spacetime as in Schwarzschild spacetime, you get the analogous
answers. For Schwarzschild spacetime, you are in a spacetime
that is hovering at a constant radius above the event horizon.
For flat spacetime, you have a spaceship that is undergoing
constant proper acceleration. In both cases, there is an "event
horizon" a finite distance below the ship such that the time
for a signal to reach from that distance to the ship diverges.
You can certainly detect the difference between a Rindler
spacetime and Schwarzschild spacetime. As I said, the force
required to hover at a constant height is different in the
two cases. However, the qualitative features of the event
horizon are the same in both cases.
--
Daryl McCullough
Ithaca, NY
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| User: "Jim Black" |
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| Title: Re: Something special about the event horizon |
03 Nov 2006 11:42:27 PM |
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Edward Green wrote:
Ben Rudiak-Gould wrote:
Edward Green wrote:
Ben Rudiak-Gould wrote:
This is also true of a Rindler horizon. You need to specify what you mean by
"the outside point" -- it sounds coordinate-dependent.
In hindsight I should have left out the second sentence of that paragraph.
The first sentence is the important one.
Perhaps. It is another parallel in the back and forth between
analogies in flat spacetime to phenomena in curved spacetime, and one
that happens -- if we are reduced to "well, it could be like this, but
it could also be like this, while on the other hand ..." to fall on
your side of the balance beam.
But really sir ... you are quite impossible: "the" outside point is
clearly "an outside point" from the first paragraph (manifested by the
reference "sequence of suspended ropes")
It's equally problematic there, but I didn't bring it up because it's
overshadowed by the other problem with that test.
and "an" outside point means
just that -- a completely arbitrary point outside the event horizon. I
presume "horzon" and "outside" are coordinate free concepts.
Yes, but "point" isn't. Unless you mean "spacetime point", but you can't
mean that because you're talking about radar return times.
Many are the times I've accidentally left some side door open in a
post, realized it afterwards, and sure enough found the reader
wandering about in the broom closet. At the same time I'm perplexed by
your perplexity. Surely it's obvious I meant a spatial point -- and
before you lecture me on the meaninglessness of that concept, recall we
are in a static geometry, where we can return to the "same" spatial
point as often as we like along our worldline.
Are we? That black hole wasn't always there, and there remains the
opportunity for more stuff to fall in, making the black hole even
larger. And if you leave the vicinity of the black hole and explore
the rest of the universe, you'll find very massive objects moving
around relative to the points you are calling fixed, changing the
geometry. Granted, if we find a black hole that nothing's falling
into, the spacetime in the vicinity of the black hole is likely static
to a good approximation.
But assuming we restrict ourselves to the boring case where the
geometry around us can be called static, the Rindler horizon objection
still holds. The metric of flat space-time written in terms of the
Rindler coordinates is
ds^2 = - x^2 dt^2 + dx^2 + dy^2 + dz^2,
and if we declare each worldline of constant (x,y,z) to be "static
spatial point," then your argument applies to the Rindler horizon as
well.
Perhaps you think that a "static spatial point" is a coordinate
dependent concept? I disagree vigorously.
Well, you haven't quite built a coordinate system. All you've done is
painted over the nice, pristine spacetime with the worldlines that you
call spatial points. To get a coordinate system, you'll need to assign
three numbers to each of these worldlines, and also throw in a
convention for simultaneity and a moment when t = 0. But you're on
your way.
Of course the issue really isn't about coordinate systems; it's about
arbitrary choices. If you declare certain worldines to be spatial
points, then you need to show how you can figure out which worldlines
consitute spatial points, given only the geometry.
The only exception I can
think of (I'm cheating -- I though of this until later, and inserted
it), is the special static geometry of flat spacetime. There indeed a
"point" (static spatial point) has no natural meaning, since other
"static" points may be flying by an arbitrary relative velocities.
And arbitrary proper accelerations, also, as the Rindler coordinate
example demonstrates.
I
guess you were thinking of this, which perhaps is why you otherwise
inexplicably regard my unqualified use of "point" as problematic.
Flat spacetime may be a kind of analytically limiting case -- like the
extension of fourier series over finite intervals to the "limit" of
fourier integrals -- which is both natural and pathogenic. I'm not
sure of this observations full significance to our discussion, but I
think it may be deep.
The real problem is that there's no way to tell what "a point outside the
event horizon" or even "a worldline outside the event horizon" means until
after you know where the event horizon is, but the purpose of your test is
to characterize the event horizon in the first place.
I find this objection bizarre. You stated that there is nothing very
special about the horizon -- other than the behavior of the Killing
vector, and some condition on observability -- and that no coordinate
independent infinities lurk nearby. I claim the radar return time
refutes both these arguments. I take the point of view that the
spacetime geometry is a given and that I can use that given geometry
freely in formulating my reply. You want me to take the view, I think,
that I'm plunked down in an unknown spacetime, and must begin piecing
its geometry together by operational tests.
I'm not sure why this is necessary, but Ok, let's look at that
question.
Feeling out the local spacetime geometry is a complicated business, but
I take it if we are plopped into a static geometry, we can, given the
ability to carry out measurements over a local, but not too local
region (not pointlike), discover that we are in a static spacetime.
Assume for now the spacetime is not flat. We will simultaneously
establish, perhaps, that we are moving wrt the static background. Then
we may being firing our rockets sufficiently to maintain a fixed
position in the time invariant spatial geometry. Once we are in a
static position, we may identify "down" as the opposite of the
direction we are accelerating in to hold ourselves in place.
Identifying "down", we may then begin placing meter sticks end to end
in that direction, with reflectors attached at certain lengths.
If there happens to be an event horizon below us, we are going to have
problems placing some finite meter stick (as I now know); I guess we
keep dropping it. So at that point -- oops... I mean "juncture" -- we
place, say, half a meter stick, or a third, or whatever we can manage.
At this same state of affairs, we notice the radar return times to our
fixed mother ship are growing large very quickly with length. In fact,
we will find that by adding some finite additional increment of stick,
we can make the return time grow as large as we like.
This entire construction sounds to me like a coordinate independent
operation characterization of an infinity associated with something
that begins to look like an event horizon.
If, on the other hand, our initial determinations were that the
spacetime were flat, we could begin unfolding our infinite folding
ruler, as before, and again measure an unbounded increasing series of
return times -- the difference being, in this case, the amount of ruler
we can extend is unbounded also. I guess in this case I would like to
say we have a "coordinate independent infinity" also -- the usual one.
An objection that can be made:
"We never measure 'infinity', but only an increasing sequence of
positive numbers."
This is more a kind of statement of the halting problem, or the
impossibility of "measuring an infinity" in general, than a specific
objection to characterizing this infinity. Of course we can never be
sure that, measuring a sequence of ever increasing numbers which do not
seem to approach an asymptote, that the sequence will not stop growing
with the next number or the one after it. At best we can say that "the
postulate of an infinity has not yet been falsified".
Need I say I would find this objection silly?
Let's fire up our spaceship and go event-horizon hunting. Event horizons
always move toward you at the speed of light (until you fall through, then
they move away at the speed of light). So our first order of business had
better be to fire the rockets to avoid falling in. Which direction? Well, we
don't know yet, but let's try thataway. Now as soon as we start
accelerating, we'll find that there's an event horizon below us which passes
your radar-time test, *whether or not there's a black hole nearby*.
Accelerating makes a Rindler horizon, and Rindler horizons have the same
properties as black hole horizons. In fact you can choose any approaching
null surface whatsoever, and as long as you avoid falling through it, it'll
pass your test.
Now that's an interesting argument. Essentially you are saying that my
first assertion is false -- that we _can't_ survey the local spacetime
geometry by kind of poking around with scout ships and lasers and dust
clouds. Maybe, worse, we can't even survey it when it is static,
finding out in the process that it is static, and hold ourselves in
(now meaningful) spatial position. If we could carry out this survey,
and if we just turned off the rocket for a minute, we could discover
that not only is the spacetime static but flat, and we wouldn't be
fooled by the dumb old Rindler horizon for a minute, recognizing it for
what it is.
And then you would die. You were fooled into thinking you were passing
a Rindler horizon by the fact that you started receiving radar signals
again, but, in fact, you just fell through the event horizon of a black
hole.
I think we can infer the local geometry, at least when it is static.
Some years back, when giants roamed sci.physics, there was reference to
a published paper, or at least a respectable pre-print, asserting that
(static?) gravitational fields were in fact distinguishable from
effects associated with an accelerating observer in flat spacetime
_even_ in the limiting case of a gravitational field with zero spatial
curvature.
Something is fishy here. Unless some sort of loophole is being
employed (Are components of the curvature they don't consider "spatial"
nonzero? Are they making nonlocal measurements, such as looking
outside?), that would be a direct contradiction of the Strong
Equivalence Principle.
You will agree this assertion is of some interest here.
(I've tried to search the archive, but I've been unable to find the
reference again.)
That's unfortunate. Assuming it's not nonsense, there's got to be some
sort of loophole they're exploiting, and we'd need to know what that
loophole is to evaluate its relevance to this discussion.
You in effect assert the contrary -- that the
uniformly accelerating observer in flat spacetime _cannot_ tell the
difference between his situation and a gravitational field of an
"infinitely large" black hole geometry
Well, without making nonlocal measurements, of course. Looking at the
sky would suffice.
-- that's why he can't tell the
difference (you imply) between his own Rindler horizon and a black hole
in the ground.
I remember that the paper was over my head, but even now I can think of
some supporting arguments based on low brow reasoning. For example...
if we were outside the event horizon of a black hole so large that we
couldn't detect the spatial curvature, then we would find we had
manuvering room in how far (as measured by a finite extension of meter
sticks -- I bet you're sorry you showed me that) we were from the
horizon at a constant proper acceleration g: if the horizon is
essentially flat, gravitational acceleration is essentially constant.
But we would have no such freedom with the Rindler horizon, since its
distance behind us depends only on g: what else could it possibly
depend on?
The distance to the horizon you will detect by the radar scheme is a
function of g for the case of the black hole also. It's just that the
horizon you detect may not be the true event horizon.
[...] so is the finite proper length
filament somehow a mapping of an infinitely long filament whose
"spatial acceleration" (variation of velocity with position) is strong
enough that the integral of the relativistically contracted length is
finite, again into a curved spacetime which hides the effective
relative velocity in the curvature -- and also contrives to allow a
static filament whose segments are effectively moving at different
velocities.
No, it's just a plain, ordinary finite distance. Really truly it is.
That was a completely unedited flight of speculative fancy. However,
while I don't present it as a close argument, I'm unconvinced that it
might not correspond to a close argument.
Physics
near the event horizon is just like physics everywhere else.
Except of course for that pesky Killing vector thing.
You're intent
on making it look weird by viewing it in a weird way, but as you've pointed
out yourself, even good old Minkowski space is weird if you admit
sufficiently weird worldlines.
Well, the longer we discuss this, the more I see many things hinging on
a series of parallels between behavior in Minkowski space, as you
prefer to call it, and analogous behaviors in more general spacetimes.
Not all the parallels seem to urge us in the same direction: we can
either focus on the Rindler horizon, and conclude that that looks
plenty weird -- though we know its a kind of observational artifact in
flat spacetime -- and hence convince ourselves that maybe the
Schwarzschild horizon isn't all that weird either, or else we can focus
on the trajectories which "reach infinity" in finite proper time in
Minkowski space -- though we would tend to think they never get there
-- and convince ourselves that maybe crossing the event horizon never
happens either. I've mentioned that the good old (and relevant) Zeno's
paradox can be looked at from two ends also (Zeno and Onez?), though
the tradition apparently only includes one reading.
That's a kind of ethically relativistic "I'm ok, you're ok" kind of
version, though I still think I'm just a little more ok here ;-) I
deny I'm looking at things in a "weird way" -- perhaps I'm just looking
at things in a fresh way: I am in fact a tyro, but not a completely
unsophisticated one. The Rindler horizon thing is a standard analogy
-- I see -- known by many -- but the aberrant trajectories I happened
to discover independently don't seem to be all that well known, nor
traditionally discussed. Hence they don't seem to carry equal weight
in the philosophically tinged discussions touching on this topic --
though I don't see why not.
There's nothing weird in the vicinity of a
black hole event horizon that you couldn't find pretty much anywhere else in
the universe.
Still disagree.
If you expand your viewpoint to take in the entire black hole, or even just
an equatorial slice through it, then you can probably find a working
characterization of the event horizon. But that's no longer a local test,
because the size of the black hole sets a lower bound on the size of your
laboratory.
I indeed took it as a given that we could simply take the entire black
hole geometry as a given in looking for interesting operational tests.
You apparently are interested in a slightly different question.
Well, there's no argument that if you consider the whole spacetime,
then the event horizon is a special place. It separates events in the
past of lightlike infinity from the events not in the past of lightlike
infinity. It is only when we restrict ourselves to local measurements
that the event horizon becomes "nothing special."
And if we assume classical mechanics (Hawking radiation complicates
things), then whenver you have a lightlike surface that's stopped
expanding (that is, the surface area has stopped increasing) or started
to get smaller, you can deduce that it's either an event horizon or
inside (possibly touching along some worldline) an event horizon. That
seems to be similar to what you're suggesting by insisting things be
static. The reason Hawking radiation would complicate this is because
it allows the surface area of an event horizon to get smaller, so there
would be some lightlike surface just outside the event horizon with
unchanging (i.e., dA/dt = 0) surface area.
However, adding your requirements, it still seems to me that the
operational characterization can be carried out. Here's the meta-code:
Survey local spacetime geometry
If geometry is flat, then stop: no nearby horizon
What if the geometry is almost flat? Then this requires either
arbitrarily good precision or an arbitrarily large lab.
If geometry is nonstatic, stop: we are not outside a pure
Schwarzschild horizon
This might require surveying the entire event horizon, which is what
we're trying to avoid doing.
Else, stop motion wrt static spatial geometry by proper acceleration
Find "down"
Extend array of meter sticks with reflectors
If return time and proper length both diverge, we are facing a
"normal" infinity
If return time diverges while proper length remains finite, we are
facing a presumptive bh
If proper length diverges while return time remains finite... ???
That would be weird. ;-)
.
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|
|
| User: "Edward Green" |
|
| Title: Re: Something special about the event horizon |
05 Nov 2006 08:12:10 AM |
|
|
<on the possible operational distinction between a Rindler horizon and
the field outside a black hole so large we cannot detect the spatial
curvature of the field>
if we were outside the event horizon of a black hole so large that we
couldn't detect the spatial curvature, then we would find we had
manuvering room in how far <...> we were from the
horizon at a constant proper acceleration g: if the horizon is
essentially flat, gravitational acceleration is essentially constant.
But we would have no such freedom with the Rindler horizon, since its
distance behind us depends only on g: what else could it possibly
depend on?
Jim Black wrote:
The distance to the horizon you will detect by the radar scheme is a
function of g for the case of the black hole also. It's just that the
horizon you detect may not be the true event horizon.
Yes. But in the case of the very large black hole, after manuvering,
we could again assume our initial value of g and find that the horizon
had _moved_ relative to us, as measured by meter sticks. We can never
do this in the case of the Rindler horizon -- manuver as we like, for a
fixed g the horizon will always be just as close to us as before.
<...>
.
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|
|
| User: "Sorcerer" |
|
| Title: Re: Something special about the event horizon |
05 Nov 2006 08:24:05 AM |
|
|
"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162735930.768150.283120@f16g2000cwb.googlegroups.com...
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162735930.768150.283120@f16g2000cwb.googlegroups.com...
Set 1, 3-0 to Androcles
Game 4 in progress.
Androcles
.
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|
|
|
| User: "Daryl McCullough" |
|
| Title: Re: Something special about the event horizon |
05 Nov 2006 12:02:01 PM |
|
|
Edward Green says...
Jim Black wrote:
The distance to the horizon you will detect by the radar scheme is a
function of g for the case of the black hole also. It's just that the
horizon you detect may not be the true event horizon.
Yes. But in the case of the very large black hole, after manuvering,
we could again assume our initial value of g and find that the horizon
had _moved_ relative to us, as measured by meter sticks.
No, that's not true. Whether you are in Rindler spacetime or in
Schwarzschild spacetime, the distance to the apparent event horizon
is a function of your rocket's current proper acceleration.
The sorts of experiments you are talking about cannot distinguish
between a real event horizon and a Rindler-type event horizon. The
only way you can distinguish them is to note that, in the case of
the Schwarzschild spacetime, the metric is time-dependent for all
except a special class of accelerated observers. The Schwarzschild
event horizon *is* the Rindler horizon for these observers.
--
Daryl McCullough
Ithaca, NY
.
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|
|
| User: "Edward Green" |
|
| Title: Re: Something special about the event horizon |
05 Nov 2006 09:27:19 PM |
|
|
Daryl McCullough wrote:
Edward Green says...
Jim Black wrote:
The distance to the horizon you will detect by the radar scheme is a
function of g for the case of the black hole also. It's just that the
horizon you detect may not be the true event horizon.
Yes. But in the case of the very large black hole, after manuvering,
we could again assume our initial value of g and find that the horizon
had _moved_ relative to us, as measured by meter sticks.
No, that's not true. Whether you are in Rindler spacetime or in
Schwarzschild spacetime, the distance to the apparent event horizon
is a function of your rocket's current proper acceleration.
It's possible that I am mistaken, but the reason you blurt out is
inadequate as a counterargument, because it does not falsify my
assumptions.
I wrote (you snipped):
"if the horizon is essentially flat, gravitational acceleration is
essentially constant"
This shows that I am aware that in a Schwarzschild spacetime the
distance to the event horizon is a function of proper acceleration --
else why would I bother stating some additional condition under which
it was essentially constant? My argument was that if spatial curvature
of the field is undetectable then so may be variation in g. There may
be -- and I think there is -- some kind of typical limit fallacy
lurking here, related to the actual form of the terms involved: but you
have done nothing to clarify it with your a-contextual argument,
repeating what I showed knowledge of.
I find you unpleasantly adversarial and careless of late, to tell the
truth. You take my remarks out of context and make them look as foolish
as possible, you respond to chance fragments rather than to structure,
and you make cheap comebacks -- snide remarks which no person would
make to a friend or colleague. I conclude I am neither your friend nor
colleague, and that you don't really want a dialogue, but simply to use
me as a foil to play to an the audience. That would explain why what I
actually write is of no significance, and why you seem to have such an
erratic opinion of my abilities -- taking me for an absolute fool one
moment, making detailed arguments the next!
You are not unique, although I remember you as more pleasant in the
past. Go teach others or fight with them if they will. I will not.
sigh.
.
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|
| User: "Sorcerer" |
|
| Title: Re: Something special about the event horizon |
05 Nov 2006 09:58:51 PM |
|
|
"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162783639.263470.194600@i42g2000cwa.googlegroups.com...
<...>
| I find you unpleasantly adversarial and careless of late, to tell the
| truth.
I find you a hypocrite, to tell the truth.
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162735930.768150.283120@f16g2000cwb.googlegroups.com...
news:1162746625.722171.218630@f16g2000cwb.googlegroups.com...
news:1162757050.569064.75170@k70g2000cwa.googlegroups.com...
news:1162753354.832364.63830@h48g2000cwc.googlegroups.com...
news:1162783639.263470.194600@i42g2000cwa.googlegroups.com...
1st set to Androcles
Second set: 1st game to Androcles
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|
| User: "Daryl McCullough" |
|
| Title: Re: Something special about the event horizon |
06 Nov 2006 06:08:16 AM |
|
|
Edward Green says...
I find you unpleasantly adversarial and careless of late, to tell the
truth. You take my remarks out of context and make them look as foolish
as possible, you respond to chance fragments rather than to structure,
and you make cheap comebacks -- snide remarks which no person would
make to a friend or colleague.
I guess this is one of those mirror moments. I feel the same way,
but with the roles reversed. I don't feel that I've said anything
snide, other than to point out when what you're saying is false.
I conclude I am neither your friend nor colleague, and that you
don't really want a dialogue, but simply to use me as a foil to
play to an the audience.
Ed, The only audience here is you. I'm sorry if I'm bombing so badly
with the audience.
I'm sorry you feel that way, but I think you are being way
over-sensitive and unreasonable. I believe that my responses have
been at least as respectful as yours have. I don't feel that I
have said anything snide. I know that it's a lot easier to detect
another person's rudeness than one's own, and so we both have to
watch out about that.
As far as dialog, what point of yours have I missed? You describe
experiments that show that there is "something special about the
event horizon" and I point out that none of those experiments actually
do that---the same experimental facts hold for Rindler spacetime,
as well. There *are* differences, namely that Rindler spacetime
is flat and Schwarzschild spacetime is not. Careful experiments
can detect these differences, but *not* the experiments that you
are talking about. The rope-lowering and radar signal experiments
*don't* single out Schwarzschild spacetime.
--
Daryl McCullough
Ithaca, NY
.
|
|
|
| User: "Sorcerer" |
|
| Title: Re: Something special about the event horizon |
06 Nov 2006 07:07:00 AM |
|
|
"Daryl McCullough" <stevendaryl3016@yahoo.com> wrote in message
news:ein8jg01u3u@drn.newsguy.com...
| Edward Green says...
|
| >I find you unpleasantly adversarial and careless of late, to tell the
| >truth. You take my remarks out of context and make them look as foolish
| >as possible, you respond to chance fragments rather than to structure,
| >and you make cheap comebacks -- snide remarks which no person would
| >make to a friend or colleague.
|
| I guess this is one of those mirror moments. I feel the same way,
| but with the roles reversed. I don't feel that I've said anything
| snide, other than to point out when what you're saying is false.
|
| >I conclude I am neither your friend nor colleague, and that you
| >don't really want a dialogue, but simply to use me as a foil to
| >play to an the audience.
|
| Ed, The only audience here is you. I'm sorry if I'm bombing so badly
| with the audience.
|
| I'm sorry you feel that way, but I think you are being way
| over-sensitive and unreasonable. I believe that my responses have
| been at least as respectful as yours have. I don't feel that I
| have said anything snide. I know that it's a lot easier to detect
| another person's rudeness than one's own, and so we both have to
| watch out about that.
|
| As far as dialog, what point of yours have I missed? You describe
| experiments that show that there is "something special about the
| event horizon" and I point out that none of those experiments actually
| do that---the same experimental facts hold for Rindler spacetime,
| as well. There *are* differences, namely that Rindler spacetime
| is flat and Schwarzschild spacetime is not. Careful experiments
| can detect these differences, but *not* the experiments that you
| are talking about. The rope-lowering and radar signal experiments
| *don't* single out Schwarzschild spacetime.
|
| --
| Daryl McCullough
| Ithaca, NY
|
Kook fight!
.
|
|
|
|
| User: "Edward Green" |
|
| Title: Re: Something special about the event horizon |
06 Nov 2006 07:30:24 PM |
|
|
Daryl McCullough wrote:
Edward Green says...
I find you unpleasantly adversarial and careless of late, to tell the
truth. You take my remarks out of context and make them look as foolish
as possible, you respond to chance fragments rather than to structure,
and you make cheap comebacks -- snide remarks which no person would
make to a friend or colleague.
I guess this is one of those mirror moments. I feel the same way,
but with the roles reversed. I don't feel that I've said anything
snide, other than to point out when what you're saying is false.
Ok, Daryl... I didn't really expect a reply to my outburst, and I
didn't really expect to read it should you have written one --
expecting only the same in return, but since you seem interested and
not unreasonable, let me give you some examples of your remarks that
have created this reaction in me:
Taking remarks out of context:
Perhaps you think that a "static spatial point" is a coordinate
dependent concept?
Yes, it certainly is. That's what relativity is all about.
Taken in isolation that might seem like a reasonable response.
However, in context, I was discussing with Ben Rudiak-Gould the
possible meaning of static spatial points in the Schwarzschild
geometry. _Your_ response suggests I was probably thinking of
something like a particular spatial position in a particular inertial
coordinate system in flat spacetime -- with a lack of understanding of
"relativity" which would shame a talented high school student. I even
went on to discuss the extension of this idea to flat spacetime --
concluding, perhaps because I had started in a spacetime where the
concept made more sense, that we may well want to consider such points
"static" in some sense, but other equally static points would be flying
by them.
The details are not important. What galled me -- and this is not the
first time I've had this reaction, and not just with you -- is that
we've been having some kind of intermittent exchange for, what... maybe
a decade? And you _still_ have such a low opinion of my abilities that
if an isolated phrase makes it sound like I have no understanding of
the most elementary consequences of "relativity", then indeed I must
have none? Why even waste your time then? Do you form _any_ ongoing
model of correspondents -- what they are likely understand based on
their past performance -- or is it all an undifferentiated sea of
amateur ignorance?
Cheap come-backs:
I disagree vigorously.
The vigor of your disagreement doesn't make it more correct.
Did I _say_ it made it more correct? Why is it necessary even to make
such comments -- because I left myself open -- like a fencer
momentarily dropping his guard -- and you saw an opportunity to get in
a quick jab? Touche!
I conclude I am neither your friend nor colleague, and that you
don't really want a dialogue, but simply to use me as a foil to
play to an the audience.
Ed, The only audience here is you. I'm sorry if I'm bombing so badly
with the audience.
I'm sorry you feel that way, but I think you are being way
over-sensitive and unreasonable. I believe that my responses have
been at least as respectful as yours have. I don't feel that I
have said anything snide. I know that it's a lot easier to detect
another person's rudeness than one's own, and so we both have to
watch out about that.
Ok. All I ask is that next time you think I may have said something
_particularly_ stupid you stop and consider for a moment "hmm...
generally Ed seems to know a little more than that, I wonder what he
may have been getting at". I'm willing to accept that I'm fallible,
but it's tiresome to be taken for a greater idiot than I am.
As far as dialog, what point of yours have I missed? You describe
experiments that show that there is "something special about the
event horizon" and I point out that none of those experiments actually
do that---the same experimental facts hold for Rindler spacetime,
as well. There *are* differences, namely that Rindler spacetime
is flat and Schwarzschild spacetime is not. Careful experiments
can detect these differences, but *not* the experiments that you
are talking about. The rope-lowering and radar signal experiments
*don't* single out Schwarzschild spacetime.
I've looked into this a bit, and it seems I may have to concede your
point -- as far as I can tell, a Rindler horizon in flat spacetime
actually _is_ some proper mathematical limit of the region near a black
hole horizon as R (gravitational radius) -> oo. We even have the nice
feature that as R -> oo, keeping the horizon in sight, the singularity
recedes to infinity also, so we are left with ... plain old Minkowski
space. The error I made in my little thought experiment was to
disregard that g _always_ goes to infinity at the horizon ... even when
the horizon is effectively flat. I was casually thinking something
like "effectively flat horizon/effectively constant g" -- which is true
far from the Schwarschild radius, say at the surface of the Earth, but
not close to it.
On the other hand, in researching this point, I found a net reference
-- anonymous but seemingly of high quality -- which indicates that my
weird idea, that the area inside the horizon may be "beyond infinity",
is not novel, and in fact has occurred to, and been seriously
considered by, minds far smarter than my own. In other words, whether
or not one eventually accepts the idea, maybe it wasn't so stupid.
Check out:
http://www.mathpages.com/rr/s7-02/7-02.htm
http://www.mathpages.com/rr/s7-03/7-03.htm
I must continue to think about this.
.
|
|
|
| User: "Daryl McCullough" |
|
| Title: Re: Something special about the event horizon |
06 Nov 2006 08:47:54 PM |
|
|
Edward Green says...
Daryl McCullough wrote:
...let me give you some examples of your remarks that
have created this reaction in me:
Taking remarks out of context:
Perhaps you think that a "static spatial point" is a coordinate
dependent concept?
Yes, it certainly is. That's what relativity is all about.
Taken in isolation that might seem like a reasonable response.
However, in context, I was discussing with Ben Rudiak-Gould the
possible meaning of static spatial points in the Schwarzschild
geometry.
Yes, I know that that was the context, but I don't see how
that changes anything. "static spatial point" doesn't have
a coordinate-independent meaning in curved or flat spacetime.
_Your_ response suggests I was probably thinking of
something like a particular spatial position in a particular inertial
coordinate system in flat spacetime -- with a lack of understanding of
"relativity" which would shame a talented high school student.
No, obviously you didn't mean that, but it seemed to me that
you *did* mean a particular spacial position in a particular
*noninertial* coordinate system. If that's not what you meant,
then I don't know what you meant.
The details are not important. What galled me -- and this is not the
first time I've had this reaction, and not just with you -- is that
we've been having some kind of intermittent exchange for, what... maybe
a decade? And you _still_ have such a low opinion of my abilities that
if an isolated phrase makes it sound like I have no understanding of
the most elementary consequences of "relativity", then indeed I must
have none?
I have plenty of respect for your abilities and your knowledge,
but that doesn't translate into believing that you would never
make an elementary mistakes. I make elementary mistakes all the
time.
Why even waste your time then? Do you form _any_ ongoing
model of correspondents -- what they are likely understand based on
their past performance -- or is it all an undifferentiated sea of
amateur ignorance?
No, I have a pretty good feel for the personalities and quirks
and abilities of many of the people that I've corresponded with
on USENET.
Cheap come-backs:
I disagree vigorously.
The vigor of your disagreement doesn't make it more correct.
Did I _say_ it made it more correct?
No, you didn't. I didn't mean anything by my remark, other than
to acknowledge the disagreement. I'm sorry if it was a rude way
of responding.
Ok. All I ask is that next time you think I may have said something
_particularly_ stupid you stop and consider for a moment "hmm...
generally Ed seems to know a little more than that, I wonder what he
may have been getting at". I'm willing to accept that I'm fallible,
but it's tiresome to be taken for a greater idiot than I am.
Okay, I'll try to do better in the future.
I've looked into this a bit, and it seems I may have to concede your
point -- as far as I can tell, a Rindler horizon in flat spacetime
actually _is_ some proper mathematical limit of the region near a black
hole horizon as R (gravitational radius) -> oo. We even have the nice
feature that as R -> oo, keeping the horizon in sight, the singularity
recedes to infinity also, so we are left with ... plain old Minkowski
space. The error I made in my little thought experiment was to
disregard that g _always_ goes to infinity at the horizon ... even when
the horizon is effectively flat. I was casually thinking something
like "effectively flat horizon/effectively constant g" -- which is true
far from the Schwarschild radius, say at the surface of the Earth, but
not close to it.
Right. The artificial gravity aboard a constantly accelerating
ship changes with height something like this
a = g/(1+gh)
where g is the acceleration felt at the center of the ship
(h=0) and where h is positive for positions above the center
(in the direction of acceleration) and negative for positions below
the center. If you drop a rope below the ship a distance of 1/g
(so h = -1/g) the acceleration goes to infinity.
On the other hand, in researching this point, I found a net reference
-- anonymous but seemingly of high quality -- which indicates that my
weird idea, that the area inside the horizon may be "beyond infinity",
is not novel, and in fact has occurred to, and been seriously
considered by, minds far smarter than my own. In other words, whether
or not one eventually accepts the idea, maybe it wasn't so stupid.
Check out:
http://www.mathpages.com/rr/s7-02/7-02.htm
http://www.mathpages.com/rr/s7-03/7-03.htm
I must continue to think about this.
Thanks for the references, and sorry again for my rudeness.
--
Daryl McCullough
Ithaca, NY
.
|
|
|
| User: "Edward Green" |
|
| Title: Re: Something special about the event horizon |
07 Nov 2006 07:44:33 PM |
|
|
Daryl McCullough wrote:
Edward Green says...
Daryl McCullough wrote:
...let me give you some examples of your remarks that
have created this reaction in me:
Taking remarks out of context:
Perhaps you think that a "static spatial point" is a coordinate
dependent concept?
Yes, it certainly is. That's what relativity is all about.
Taken in isolation that might seem like a reasonable response.
However, in context, I was discussing with Ben Rudiak-Gould the
possible meaning of static spatial points in the Schwarzschild
geometry.
Yes, I know that that was the context, but I don't see how
that changes anything. "static spatial point" doesn't have
a coordinate-independent meaning in curved or flat spacetime.
Well then, I think you are wrong. Let me be precise:
I conjecture there is a definition which has coordinate independent
meaning in all spacetimes possessing the prerequisites, and in
sufficiently assymmetric spacetimes corresponds to what we might
reasonably mean by a "static spatial point". I'm not sure if the
Schwarzschild spacetime -- with its spherical symmetry -- is
"sufficiently asymmetric", which is why in that other post I started by
considering the aspherical potato. Here is a working model for such a
definition:
X': a worldline with constant proper acceleration whose tangent
is a timelike Killing vector
<1162746625.722171.218630@f16g2000cwb.googlegroups.com>
Read the further motivation there, if you wish. To me the technical
definition is window-dressing, since the concept seems self-evident --
though, evidently not to you, and, before you say so, I know that its
subjective self-evidentiary property is not proper evidence. So there
is a technical proposal to chew on.
_Your_ response suggests I was probably thinking of
something like a particular spatial position in a particular inertial
coordinate system in flat spacetime -- with a lack of understanding of
"relativity" which would shame a talented high school student.
No, obviously you didn't mean that, but it seemed to me that
you *did* mean a particular spacial position in a particular
*noninertial* coordinate system. If that's not what you meant,
then I don't know what you meant.
It appears what I'm after may be described in such terms. But, just
because something has a description in certain coordinate systems, does
it follow that that something is necessarily purely an artifact of
coordinate systems, or that it has no other description?
The proposed definition may have the following alternative form:
(Conjectured equivalent)
X'' : in a manifestly static representation of the metric, a spacetime
locus corresponding to particular values of the spatial coordinates
"manifestly static" means, in a coordinate system having three
spacelike and one timelike coordinates, no metric coefficients depend
on the timelike coordinate
This alternative definition depends on coordinates, but I think it will
turn out that the loci so defined are the same set of loci in all such
coordinate systems, for a given spacetime.
I have plenty of respect for your abilities and your knowledge,
but that doesn't translate into believing that you would never
make an elementary mistakes. I make elementary mistakes all the
time.
Ok. I'll try to keep that in mind, and not be so prickly.
I've looked into this a bit, and it seems I may have to concede your
point -- as far as I can tell, a Rindler horizon in flat spacetime
actually _is_ some proper mathematical limit of the region near a black
hole horizon as R (gravitational radius) -> oo. We even have the nice
feature that as R -> oo, keeping the horizon in sight, the singularity
recedes to infinity also, so we are left with ... plain old Minkowski
space.
Right. The artificial gravity aboard a constantly accelerating
ship changes with height something like this
a = g/(1+gh)
where g is the acceleration felt at the center of the ship
(h=0) and where h is positive for positions above the center
(in the direction of acceleration) and negative for positions below
the center. If you drop a rope below the ship a distance of 1/g
(so h = -1/g) the acceleration goes to infinity.
It's almost as if the only role of spacetime curvature were not to
create the horizon -- as we might think -- but to bend it around, so we
have a Rindler horizon which looks like a closed sphere; which has the
curious effect that observers accelerating in various directions may
remain is a static relationship. It's a powerful idea, but I'm still
not quite ready to divorce my previous thinking -- maybe they can learn
to live together.
Thanks for the references, and sorry again for my rudeness.
Thanks for your patience.
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| User: "Tom Roberts" |
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| Title: Re: Something special about the event horizon |
07 Nov 2006 10:23:43 PM |
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Edward Green wrote:
I conjecture there is a definition which has coordinate independent
meaning in all spacetimes possessing the prerequisites, and in
sufficiently assymmetric spacetimes corresponds to what we might
reasonably mean by a "static spatial point".
Nope. Not a chance. That is only possible in a region with a timelike
Killing vector, and the universe we inhabit has no such regions.
requiring any Killing vector is requiring far too much symmetry -- the
universe we inhabit manifestly has no Killing vectors.
I'm not sure if the
Schwarzschild spacetime -- with its spherical symmetry -- is
"sufficiently asymmetric",
It is really the timelike Killing vector that is the problem. But the
rotational ones are also too much symmetry.
X'' : in a manifestly static representation of the metric, a spacetime
locus corresponding to particular values of the spatial coordinates...
"manifestly static" means, in a coordinate system having three
spacelike and one timelike coordinates, no metric coefficients depend
on the timelike coordinate
But in general there is no such "representation" and no such
coordinates. Indeed such coordinates can be found ONLY in a static or
stationary region of the manifold. But the world we inhabit MANIFESTLY
has no such regions (there are regions that are approximately static,
but not _exactly_ so).
Tom Roberts
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| User: "Edward Green" |
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| Title: Re: Something special about the event horizon |
08 Nov 2006 04:53:14 AM |
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I made the mistake of inadvertantly reading what Tom Roberts wrote:
Edward Green wrote:
I conjecture there is a definition which has coordinate independent
meaning in all spacetimes possessing the prerequisites, and in
sufficiently assymmetric spacetimes corresponds to what we might
reasonably mean by a "static spatial point".
Nope. Not a chance. That is only possible in a region with a timelike
Killing vector, and the universe we inhabit has no such regions.
requiring any Killing vector is requiring far too much symmetry -- the
universe we inhabit manifestly has no Killing vectors.
Tom, you willfully obtuse stick in the mud, my conjecture was not that
there exist "static spatial points" in the universe, but that there
exist static spatial points in general relativity. Jim Black made the
same "objection", and, if I didn't know better, I would think you were
both argumentative tyros who didn't understand the nature of physical
abstraction. We may abstract to situations which will not be ideally
realized in the physical universe, but may be realized in a sufficient
degree of approximation that the abstraction and what we can deduce
from it have utility.
Reread my conjecture: "there is a definition which has ... meaning in
all spacetimes _possessing the prerequisites_. That would include the
idealization known as Schwarzschild spacetime, but not, as you so
helpfully point out, any sufficiently precise model of the real
universe. The ability and inclination to form idealized models and to
analyze their consequences is part of science 101. Since I presume you
have progressed in your career to at least science 102, I think you are
being deliberately and bizarrely provocative. You are not a tyro; stop
affecting to think like one.
<snip rest -- vow try not to repeat mistake>
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| User: "Sorcerer" |
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| Title: Re: Something special about the event horizon |
08 Nov 2006 02:51:50 PM |
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"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162983194.467372.148090@f16g2000cwb.googlegroups.com...
|I made the mistake of inadvertantly reading what Tom Roberts wrote:
|
| <snip rest -- vow try not to repeat mistake>
How very sensible.
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| User: "malibu" |
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| Title: Re: Something special about the event horizon |
04 Nov 2006 08:16:12 AM |
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"Black holes" are vortices in space.
If you get pulled into them you are simply
torn apart into plasma and shot out their poles.
We have seen and measured the plasma
coming out. We are still hanging on to the
comfort-blanket that this is just what is being
blown off the accretion disc. It is not.
John
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| User: "Edward Green" |
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| Title: Re: Something special about the event horizon |
05 Nov 2006 11:10:25 AM |
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Jim Black wrote:
<...>
Thank you for your comments! We've branched out onto a lot of ground
here, and to cover it all thoroughly would result in a book. Here is a
tentative list of topics:
[1] "Static points" in GR : what meaning can we give to the concept
[2] God's eye vs. ant's eye views : what can we say about a spacetime
knowing its structure in advance vs. being dropped blindfolded onto an
arbitrary point
[3] The meaning of "local" : relevant to both the ant and to the next
topic
[4] The Strong Equivalence Principle: is the Rindler horizon a proper
limit of Schwarzschild geometries as R -> oo? can the ant tell the
difference? God?
To keep things reasonable, let's just focus on the first topic here.
First, names. "Point" invites ambiguity between "spatial point" and
"spacetime point". Shall we call the idea "static worldlines"? On the
other hand "static spacetime point" doesn't mean very much. So I
propose allowing the language "static point", as long as we always
remember to add the "static", to distinguish it from (spacetime) point.
Assume for now a static point is a concept we are tying to make sense
of, corresponding roughly to the role of an observer on some special
set of worldlines.
Objections?
Now, context. This side issue came up because I offhandedly referred
to a "point", meaning what I ought to refer to as a "static point" in
discussing Schwarzschild geometry with Ben. He affected not to
understand me, although I took the idea to be clear in context. Hence
the more detailed discussion.
Part of Ben's objection seems to fall under the topic "Ant vs. God". He
wanted to know how we could tell we were at a static point. It's too
much to discuss everything at the same time, so I would like first to
simply discuss the idea from the God's eye point of view: given an
arbitrary spacetime laid out before, can we make sense of the idea of
"static point". Let me take a stab at a technical definition:
X: a worldline whose tangent is a timelike Killing vector
Does concept X capture what we might like to mean by static point?
Does it capture things we might have liked to throw back? We may be
stuck with the whole kit and kaboodle of 'em, if we would like a simple
definition.
Consider an arbitrary massive potato. Its gravitational field is
lumpy. It seems reasonable to assume the only Killing vectors possible
will be timelike. Static points in this setup will correspond to what
we ordinarily consider spatial points keeping a fixed (spatial)
geometric relation to the potato. The definition seems to work.
Objections?
Now, consider Minkowski space. The problem with Minkowski space, from
the point of view of this definition, is that it has too much symmetry.
At each point there is not only a timelike Killing vector, there are
three linearly independent spacelike Killing vectors (understanding
check?). Therefore we may construct an arbitrary number of new
timelike Killing vectors at each point.
I had already anticipated that what I might be inclined to label a
"static point" in flat spacetime may be passed by other static points
moving at various relative velocities. I don't really see a problem
with this -- from the point of view of each associated inertial
observer, the featureless background is certainly "static". We have
merely an example of concept splitting -- in our ordinary experience
two "static" trajectories may not pass each other. But in Minkowski
space -- or indeed even in featureless Gallilean spacetime -- it is
different. So what? If we want to keep the uniqueness property just
mentioned we must say there are no static points in Minkowski space; if
we omit it, we say there are, but (tautologically) they lack an
expected property.
You [Jim Black] suggest a more unexpected idea. In Minkowksi space,
not only are all inertial observers static, but it looks like observers
undergoing constant acceleration are as well.
The metric of flat space-time written in terms of the Rindler coordinates is
ds^2 = - x^2 dt^2 + dx^2 + dy^2 + dz^2,
and if we declare each worldline of constant (x,y,z) to be "static
spatial point," then ...
Beside the suggested coordinate definition, these worldlines would also
seem to meet definition X. Worse, it appears as if any arbitrary
worldline in Minkowski space is X. Are the associated observers
"static"? They seem to meet at least one test: an instantaneously
co-moving inertial observer always seems the same boring featureless
background. But it seems to do a little too much violence to the idea
of "static" to admit violently accelerating observers -- we could argue
that effects in a co-moving laboratory aren't static with proper time
-- so perhaps we should amend concept X:
X': a worldline with constant proper acceleration whose tangent
is a timelike Killing vector
What do you think?
Another doubt I have is concerning intermediate degrees of symmetry
between flat spacetime and the potato. Is a particle in circular orbit
around a spherical mass distribution "static"? It meets the informal
test of "always seeing the same environment", and its proper
acceleration is constant (zero). I recall that for the Kerr spacetime
we might be inclined to say it is "static" as a whole, but we invoke
some condition about time-reversibility. Do we need to add some such
condition here, or does the Killing vector take care of it?
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| User: "Sorcerer" |
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| Title: Re: Something special about the event horizon |
05 Nov 2006 11:32:20 AM |
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"Edward Green" <spamspamspam3@netzero.com> wrote in message
news:1162746625.722171.218630@f16g2000cwb.googlegroups.com...
| <...>
That's quite clever. Hmm... <...>
How about <... ...> ?
news:1162515510.123181.189530@m7g2000cwm.googlegroups.com...
news:1162519570.124138.300990@h48g2000cwc.googlegroups.com...
news:1162605417.255281.133430@i42g2000cwa.googlegroups.com...
news:1162735930.768150.283120@f16g2000cwb.googlegroups.com...
news:1162746625.722171.218630@f16g2000cwb.googlegroups.com...
Set 1, 4-0 to Androcles
Game 5 in progress.
Androcles
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| User: "Ben Rudiak-Gould" |
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| Title: Re: Something special about the event horizon |
07 Nov 2006 07:09:29 PM |
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Edward Green wrote:
Surely it's obvious I meant a spatial point -- and
before you lecture me on the meaninglessness of that concept, recall we
are in a static geometry, where we can return to the "same" spatial
point as often as we like along our worldline.
I didn't know we were in a static geometry. I thought you were trying to
characterize black hole event horizons in general. If we're in one of the
standard time-independent black hole solutions, then your test will work.
Perhaps you think that a "static spatial point" is a coordinate
dependent concept?
It's not if it's defined in terms of symmetries of the spacetime background.
It's sometimes ambiguous (notably in Minkowski space), but in most
geometries if it's definable at all then it's unambiguous. Usually, though,
it's not definable at all, because most spacetimes don't have any symmetries.
You want me to take the view, I think,
that I'm plunked down in an unknown spacetime, and must begin piecing
its geometry together by operational tests.
It's more that I thought that's what you were trying to do.
Feeling out the local spacetime geometry is a complicated business, but
I take it if we are plopped into a static geometry, we can, given the
ability to carry out measurements over a local, but not too local
region (not pointlike), discover that we are in a static spacetime.
Only that it's locally static. But if you know a priori that the spacetime
is globally static, then I think that all black hole event horizons will
necessarily be stationary, and then there's nothing to prevent you from
making a surveying trip to locate them. Rather than looking at radar return
times it might be simpler to put a laser on a stick and look at the Doppler
shift, since this is a direct measurement of the dt^2 component of the
metric at a single point (in stationary coordinates).
Other, less direct techniques can also work in these special cases. For
example, if you know that you're in a vacuum solution, you can just measure
the local geometry anywhere and analytically extend it to find the
singularities, and hence the event horizons.
Some years back, when giants roamed sci.physics, there was reference to
a published paper, or at least a respectable pre-print, asserting that
(static?) gravitational fields were in fact distinguishable from
effects associated with an accelerating observer in flat spacetime
_even_ in the limiting case of a gravitational field with zero spatial
curvature.
You may be talking about Stephen Parrott and this paper:
http://arxiv.org/abs/gr-qc/9303025
I haven't read it in a while, but I'm almost sure his claim is that the
equivalence principle is wrong, so it's irrelevant as long as our discussion
stays within the framework of GR.
You in effect assert the contrary -- that the
uniformly accelerating observer in flat spacetime _cannot_ tell the
difference between his situation and a gravitational field of an
"infinitely large" black hole geometry --
Yes, because they are literally the same geometry. The M -> infinity limit
of the Schwarzschild geometry in the vicinity of the event horizon is the
Rindler geometry.
if the horizon is
essentially flat, gravitational acceleration is essentially constant.
But we would have no such freedom with the Rindler horizon, since its
distance behind us depends only on g: what else could it possibly
depend on?
Yes, it's equal to c^2/g. But the same formula holds in the M -> infinity
Schwarzschild limit.
Physics near the event horizon is just like physics everywhere else.
Except of course for that pesky Killing vector thing.
Well, yes, but that only exists because of the unusual amount of symmetry in
the Schwarzschild solution. A characterization of a planet that required
that it be a perfect sphere would not be very useful in practice.
The Rindler horizon thing is a standard analogy
-- I see -- known by many -- but the aberrant trajectories I happened
to discover independently don't seem to be all that well known, nor
traditionally discussed.
They're certainly known -- I'd heard of them before, and I didn't come up
with them independently.
Hence they don't seem to carry equal weight
in the philosophically tinged discussions touching on this topic --
though I don't see why not.
No, that's not why. It's because the Rindler horizon analogy is a much
closer one. There's a precise mathematical correspondence there, which
seriously limits the number of things that GR can say are true about one but
false about the other. The aberrant-Minkowski-trajectory analogy is much
more informal, and I don't find it very convincing because of the fact that
the metric behaves differently in the two cases (ill defined at Minkowski
infinity, well defined at the event horizon).
-- Ben
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| User: "Edward Green" |
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| Title: Re: Something special about the event horizon |
08 Nov 2006 12:57:37 PM |
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Ben Rudiak-Gould wrote:
Edward Green wrote:
Surely it's obvious I meant a spatial point -- and
before you lecture me on the meaninglessness of that concept, recall we
are in a static geometry, where we can return to the "same" spatial
point as often as we like along our worldline.
I didn't know we were in a static geometry. I thought you were trying to
characterize black hole event horizons in general. If we're in one of the
standard time-independent black hole solutions, then your test will work.
OK. I see that, even in informal discussions, it is a good idea to
restate one's assumptions occasionally. I will try to do better in the
future. I thought we were still discussing the ideal Schwarzschild
metric.
<snip most statements of resulting agreement>
Other, less direct techniques can also work in these special cases. For
example, if you know that you're in a vacuum solution, you can just measure
the local geometry anywhere and analytically extend it to find the
singularities, and hence the event horizons.
Yes... I've thought of the analytic extension thing. I presumed it
works. It hadn't dawned on me that what we find is the extended vacuum
solution; the mass has to be inserted by hand, so to speak, and its
implied presence will show up as singularities.
Some years back ... there was reference to a ... paper ... asserting that
(static?) gravitational fields were in fact distinguishable from
effects associated with an accelerating observer in flat spacetime
_even_ in the limiting case of a gravitational field with zero spatial
curvature.
You may be talking about Stephen Parrott and this paper:
http://arxiv.org/abs/gr-qc/9303025
I haven't read it in a while, but I'm almost sure | | |