My GUESS iSS Hamiltonian Gibbs LaGrangian Helmoltz Stuckless analysis:
[Note pL=LiNEAR & pA=ANGULAR, momenta; And fA & fL related frequency.]
[Note nL=LiNEAR & nA=ANGULAR, NUMBERS; GUESS energy L the LaGrangian.]
m1*v1^2 m1
GUESS ENTHALPY E = m1*c^2 + {(-- - --)*(-- + 1)} + eV
2 M1
nA*{mph}*ls*c^2 m1*v1^2
= m1*c^2 + (-- -- --- -- --) - (-- - --)
rA 2
= m1*c^2 + ( pL*c ) + ( pA*fA )
= m1*c^2 + ( h*fL ) + ( nA*hbar*fA )
= m1*c^2 + ( pL*c ) + ( nA*hbar*fA )
= m1*c^2 + ( h*fL ) + ( pA*fA )
= eM + ( LaGrangian, L ) + eV
= eM + L + eV
= eM + eK
= eG + eK - eV
= eG + L.
Note:
EiTHER, energy + eV, OR energy - (m1*v1^2 / 2) ..NOT BOTH, AT ONCE.
[ This means that in any calculation you SWiTCH one to the OTHER. ]
- eV = + (m1*v1^2 / 2) = (E - eK - eG) = (L - eK) = (- E + L + eM).
Where-as:
+ eV = - (m1*v1^2 / 2) = (E - eM - L) = (eK - L) = (- E + eK + eG).
[ BOTH + eV and - (m1*v1^2 / 2) are CHARGEs, but DiFFERENT SiGNs. ]
[ BECAUSE + eV and - (m1*v1^2 / 2) are BOTH, Volt*Ampere*seconds. ]
$ Arithmetically speaking:
CLEARLY the BiGGEST DiFFERENCE, between - eV & + eV, is TWO (2) eV.
[ This is because ELECTRONs of mass leave electron HOLEs of mass. ]
[ There is NO OTHER WAY, to account for ELECTRON HOLEs phenomena. ]
[ The GUESS iSS test ELECTRON HOLE is a CAViTY of CHARGE of mass. ]
There's NO ANGULAR momentum in the General Relativity GTR equation.
There's NO CENTRAL mass QUANTiTY in the ANGULAR momentum equation.
UNanswered QUESTiON put to GR (gtr) Tivity, over, over & over..
Note: Angular momentum pA
=[(PLANET-like mass)*(orbit radius)*(velocity)];
[..with units of -> kilogram*(meter)^2/second].
Q. There is NO CENTRAL-mass quantity; WHY is that.?
There's NO mass in General Relativity, mathematically speaking.!!
PROFOUNDLY, iRONiCALLY, there's NO GR "space-time-curvature".
(The GR, G_uv = T_uv CANNOT be DEFiNED, in TERMs of "mass".!!)
possibly other factors relating to density and momentum, -=-
There is NO "mass -=- density and momentum", in GEOMETRY, duh.
G*Mp*{mph} C1*(C2a*C2b) C1
-- --- -- = -- -- -- -- = -- = 4*pi*Vu*{e}*lo = 4*pi*#*{e}*c ;
(n - 1) C2^2*c c
C1*(p1*p2)*c C1*({e}^2*c^2)*c C1(q1*q2)*c^3 C1*{e}*c
= -- --- -- -- = -- -- ---- -- -- = -- - --- - -- = -- -- --
C2^2 C2^2 C2^2 C2 ..!!
GENERAL GUESS photon mass [mph] = nA*{mph}*ls / rA = m1 = mD / n.
PARTiCULAR iSS photon mass {mph} = 2*pi*h / tp*c^2 = hbar / ls*c
= hbar / ts*c^2 = h / 2*pi*ls*c.
GRAViTY acceleration g = (g1 + g2) = G*(M1 + m2) / (n - 1)*d^2:
|G*(M1 + m2)| |4*(pi)^2*d| | 4*(pi)^2*r1 4*(pi)^2*r2 |
|-- -- -- --| = |-- -- - --| = |(-- -- -- --) + (-- -- -- --)|
|(n - 1)*d^2| | T^2 | | T^2 T^2 |
|4*(pi)^2*lbob| |4*(pi)^2*(r1 + r2)|
= |-- -- - -- --| = |-- -- --- -- -- --| = g1 + g2 = gravity g.
| (tbob)^2 | | T^2 |
$ M1*v1^2 m2*v2^2
THEN: -- - -- = -- - -- = M1*r1 = m2*r2
$ g1 g2.
NOTE: Mp*lp = {mph)*ls = me*wls = Moo*loo / 4*pi = hbar / c.
Note therefore, as radii r1 & r2 vary and/or M1 & m2 vary, etc,
then, BOTH, M1 & m2 can *TOUCH down* ON each other's SURFACE.!!
Dimension, d = r1 + r2 = centre-to-centre distance, of M1 & m2.
This isN'T fluffy-level math; This is My WHOLE-wheat arithmetic.
The GUESS iSS GR G_uv = T_uv = Ga / G = 1 / (n - 1) = G_relative.
CLOSE: Brian A M Stuckless ..over & OUT.
^
GUESS RESTmass*c^4=(iNTRiNSiC energy e)*c^2=(mol part)*K*Volt*meter.
My GUESS iSS STANDARD
< The STANDARD set. >
/\
__ _\/_ __
\_\/_/\_\/_/
/\_\/_/\ ("`-/")_.-'"``-._
_\/_/\_\/_ \. . `; -._ )-;-, `)
/_/\_\/_/\_\ \ / (v_,) _ )`-.\ ``-'
/\ - O - _ .- _..-_/ / ((.'
\/ / \ ((,.-' ((,/ By: Toe.!
$$ By deeds you know them.!! >><> >><> >><> >><> >><>
BEHOLD, IAM THAT IAM hath circumcised the FORESKiNs of your hearts.!!
$ :-.,_,.-:*'``'*:-.,_,.-:*'``'*:-.,_,.-:*'``'*:-.,_,.-:*'`
$ ____ _ _ _ _
$ | _ \ | | ___ _ __ | | __ | | | |
$ | |_) | | | / _ \ | '_ \ | |/ / | | | |
$ My _ENORMOUS_ | __/ | | | (_) | | | | | | < _ |_| |_|
$ |_| |_| \___/ |_| |_| |_|\_\ (_) (_) (_)
$
$ :*'``'*:-.,_,.-:*'``'*:-.,_,.-:*'``'*:-.,_,.-:*'``'*:-.,_
BEHOLD, IAM THAT IAM WHOLLY WHOLLY WHOLLY He ..and no more is more.!!
PD wrote: > > Len Gaasenbeek wrote: > > > >
Actually, "relativistic mass" is an outmoded term. Instead,
physicists no longer think there is a linear relationship
between kinetic energy absorbed and linear speed (squared).
...................................................
To Eric,
So where does the additional kinetic energy of the particle
come from?
Len.
Come from? It comes from the agent that poured energy into it. How do
you describe an object's kinetic energy? It is
sqrt[(mc^2)^2 + (pc)^2] - mc^2.
In this expression, the only thing that changes
as you pour energy in is p.
[Nomen Clature] insert ..see top of PAGE.!!
This in spite of the fact that relativists agree with me, that all
relativistic particles spin around their own spin axis as they travel
along,
which contributes to their overall kinetic energy.
The problem is, the spin seems to stay the same regardless of the
amount of energy absorbed.
....................................................
To Eric,
The spin of a relativistic particle increases as it continues to absorb
energy in a particle accelerator. It is a measure of its temperature. You
are wrong again.
Len.
The temperature of particles in an acceleration is actually quite cold.
See "stochastic cooling".
The spin of particles is quite easily measurable by their coupling to
an applied magnetic field. There is no measurable increase in spin in
such magnetic fields.
PD
Re: Time dilation etc.
.
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