RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS



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Topic: Science > Physics
User: "Pentcho Valev"
Date: 18 May 2007 01:58:23 AM
Object: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS
http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a90057feb?
On Oct 25, 1995, John Baez wrote in sci.physics:
"Nonetheless, it's a fact that a photon has a nonzero momentum."
A curious person asked:
"Are you therefore asserting that it has nonzero mass? If not, why
not?"
John Baez replied:
"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."
The curious person could have asked:
"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"
John Baez would have replied:
"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."
Pentcho Valev
.

User: "Androcles"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 18 May 2007 03:09:18 AM
"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...
:
http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a90057feb?
:
: On Oct 25, 1995, John Baez wrote in sci.physics:
:
: "Nonetheless, it's a fact that a photon has a nonzero momentum."
:
: A curious person asked:
:
: "Are you therefore asserting that it has nonzero mass? If not, why
: not?"
:
: John Baez replied:
:
: "You can see that I did not assert anything about the photon's mass. I
: know what the photon's mass is, but I never talk about it around here
: because the endless discussion of the photon's mass is boring, boring,
: boring."
:
: The curious person could have asked:
:
: "Are you therefore asserting that the speed of light varies in a
: gravitational field in accordance with Einstein's 1911 equation
: c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
: c'=c+v, where v is the relative speed of the light source and the
: observer?"
:
: John Baez would have replied:
:
: "You can see that I did not assert anything about the variable speed
: of light. I know how the speed of light varies in a gravitational
: field, but I never talk about it around here because the endless
: discussion of the variability of the speed of light is boring, boring,
: boring."
:
: Pentcho Valev
:
In other words Baez pretends he knows what mass is.
I'm so fantastically clever I know what mass is too, but
if I told you then it would be boring.
If you guess right, then I told you so.
Get it wrong and you can blame Baez.
.
User: "Pentcho Valev"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 18 May 2007 04:04:46 AM
Androcles wrote:

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...
:
http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a90057feb?
:
: On Oct 25, 1995, John Baez wrote in sci.physics:
:
: "Nonetheless, it's a fact that a photon has a nonzero momentum."
:
: A curious person asked:
:
: "Are you therefore asserting that it has nonzero mass? If not, why
: not?"
:
: John Baez replied:
:
: "You can see that I did not assert anything about the photon's mass. I
: know what the photon's mass is, but I never talk about it around here
: because the endless discussion of the photon's mass is boring, boring,
: boring."
:
: The curious person could have asked:
:
: "Are you therefore asserting that the speed of light varies in a
: gravitational field in accordance with Einstein's 1911 equation
: c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
: c'=c+v, where v is the relative speed of the light source and the
: observer?"
:
: John Baez would have replied:
:
: "You can see that I did not assert anything about the variable speed
: of light. I know how the speed of light varies in a gravitational
: field, but I never talk about it around here because the endless
: discussion of the variability of the speed of light is boring, boring,
: boring."
:
: Pentcho Valev
:
In other words Baez pretends he knows what mass is.
I'm so fantastically clever I know what mass is too, but
if I told you then it would be boring.
If you guess right, then I told you so.
Get it wrong and you can blame Baez.

The question:
"Does the speed of light vary in a gravitational field in accordance
with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a
gravitational field, becomes c'=c+v, where v is the relative speed of
the light source and the observer?"
can (and should) be answered without necessarily considering the
related question:
"Does the photon have a mass?"
Of course, in a normal situation the two questions would always be
considered together. However in Einstein's world the situation is by
no means normal and Einsteinians would take any opportunity to convert
the second question into a red herring. One should not give them such
opportunities: the first question alone is fatal for Einstein's
relativity.
Pentcho Valev
.
User: "Androcles"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 18 May 2007 10:52:16 AM
"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179479086.027853.325960@h2g2000hsg.googlegroups.com...
: Androcles wrote:
: > "Pentcho Valev" <pvalev@yahoo.com> wrote in message
: > news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...
: > :
: >
http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a90057feb?
: > :
: > : On Oct 25, 1995, John Baez wrote in sci.physics:
: > :
: > : "Nonetheless, it's a fact that a photon has a nonzero momentum."
: > :
: > : A curious person asked:
: > :
: > : "Are you therefore asserting that it has nonzero mass? If not, why
: > : not?"
: > :
: > : John Baez replied:
: > :
: > : "You can see that I did not assert anything about the photon's mass. I
: > : know what the photon's mass is, but I never talk about it around here
: > : because the endless discussion of the photon's mass is boring, boring,
: > : boring."
: > :
: > : The curious person could have asked:
: > :
: > : "Are you therefore asserting that the speed of light varies in a
: > : gravitational field in accordance with Einstein's 1911 equation
: > : c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
: > : c'=c+v, where v is the relative speed of the light source and the
: > : observer?"
: > :
: > : John Baez would have replied:
: > :
: > : "You can see that I did not assert anything about the variable speed
: > : of light. I know how the speed of light varies in a gravitational
: > : field, but I never talk about it around here because the endless
: > : discussion of the variability of the speed of light is boring, boring,
: > : boring."
: > :
: > : Pentcho Valev
: > :
: > In other words Baez pretends he knows what mass is.
: > I'm so fantastically clever I know what mass is too, but
: > if I told you then it would be boring.
: > If you guess right, then I told you so.
: > Get it wrong and you can blame Baez.
:
: The question:
:
: "Does the speed of light vary in a gravitational field in accordance
: with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a
: gravitational field, becomes c'=c+v, where v is the relative speed of
: the light source and the observer?"
:
: can (and should) be answered without necessarily considering the
: related question:
:
: "Does the photon have a mass?"
:
: Of course, in a normal situation the two questions would always be
: considered together. However in Einstein's world the situation is by
: no means normal and Einsteinians would take any opportunity to convert
: the second question into a red herring. One should not give them such
: opportunities: the first question alone is fatal for Einstein's
: relativity.
:
: Pentcho Valev
Find a flaw in this argument:
1) We measure mass by applying force and measuring acceleration.
2) Acceleration is overcoming inertia.
2a) "Inertia" is shorthand for Galileo/Newton's first law.
"Every body perseveres in its state of rest, or of uniform motion in a right
line, unless it is compelled to change that state by forces impressed
thereon."
2b) Acceleration is Galileo/Newton's second law:
"The alteration of motion is ever proportional to the motive force
impressed;
and is made in the direction of the right line in which that force is
impressed."
3) Intuitively, matter has mass; by definition, by observation, by
experience.
4) Newton's third law is conservation of momentum.
"To every action there is always opposed an equal reaction; or the mutual
actions of two bodies upon each other are always equal, and directed to
contrary parts."
5) Photons are not matter, they are the electromagnetic transfer of energy.
Photons come in pairs. For every photon there is an equal and opposite
rephoton; a restatement of Newton's third law in a different situation.
6) A photon is the wave superposition of two or more oscillators which only
move once (the so-called "quantum" of energy).
http://www.androcles01.pwp.blueyonder.co.uk/rephoton.gif
6a) The total energy of two photons is mc^2.
7) Asking if a photon has mass is asking if a photon has inertia.
8) The path of a photon is curved in a rotating frame:
http://ww2010.atmos.uiuc.edu/(Gh)/guides/mtr/fw/crls.rxml
9) By observation of 9) Photons have inertia.
10) Photons are not matter.
11) Whatever matter is, we can only detect it by it radiating energy by
reflection or its own emission.
12) Newton was puzzled by "action at a distance", yet accepted the
existence of matter axiomatically. It's a given. What he did not know of
was the periodic table, the Bohr model of the atom or electrodynamics.
I suggest we reverse that old, worn out way of thinking and accept
action-at-a-distance as a given and then ponder over matter.
The pieces of the puzzle are all there. Yes, the photon has mass. One can
apply a force to it and nudge it from its path. That's what a diffraction
grating or prism does.
What a photon lacks is matter. The photon is the link between
action-at-a-distance
and matter, a line of enquiry to investigate.
What *IS* matter?
"Great spirits have always found violent opposition from mediocrities.
The latter cannot understand it when a man does not thoughtlessly submit to
hereditary prejudices but honestly and courageously uses his
ntelligence." -- Einstein.
.
User: "Dirk Van de moortel"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 18 May 2007 12:41:53 PM
"Androcles" <Engineer@hogwarts.physics> wrote in message news:QYj3i.35723$Ch.28298@fe2.news.blueyonder.co.uk...


"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179479086.027853.325960@h2g2000hsg.googlegroups.com...
: Androcles wrote:
: > "Pentcho Valev" <pvalev@yahoo.com> wrote in message
: > news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[snip of usual exchange of irrelevancies]

I suggest we reverse that old, worn out way of thinking and accept
action-at-a-distance as a given and then ponder over matter.

That sums it up pretty well.
The return to Aristotle of the "Electronic Engineer, Professionally"
Dirk Vdm
.

User: "The TimeLord"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 25 May 2007 12:51:14 AM
Androcles wrote in "sci.physics.relativity":

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179479086.027853.325960@h2g2000hsg.googlegroups.com...
: Androcles wrote:
: > "Pentcho Valev" <pvalev@yahoo.com> wrote in message
: > news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[...]

Find a flaw in this argument:

1) We measure mass by applying force and measuring acceleration.

Mmmmm - OK.


2) Acceleration is overcoming inertia.

More to the point: acceleration is change in velocity.


2a) "Inertia" is shorthand for Galileo/Newton's first law.

"Every body perseveres in its state of rest, or of uniform motion in a right
line, unless it is compelled to change that state by forces impressed
thereon."

OK. In symbols, Newton's first law is:
F=0 => v=constant


2b) Acceleration is Galileo/Newton's second law:

"The alteration of motion is ever proportional to the motive force
impressed;
and is made in the direction of the right line in which that force is
impressed."

Newton wrote it this way:
F = dp/dt


3) Intuitively, matter has mass; by definition, by observation, by
experience.

Definition is that mass is the amount of matter.


4) Newton's third law is conservation of momentum.

No. Read your quote immediately below.


"To every action there is always opposed an equal reaction; or the mutual
actions of two bodies upon each other are always equal, and directed to
contrary parts."

What this actually means is that if F_ab is the force that a exerts on
b, then F_ba = -F_ab.


5) Photons are not matter, they are the electromagnetic transfer of energy.

True. Since mass is the amount of matter and photons have no matter,
they have no mass.

Photons come in pairs. For every photon there is an equal and opposite
rephoton; a restatement of Newton's third law in a different situation.

Huh? Why would you say this? What experimental evidence is there that
photons always come in pairs? Newton's third law certainly has nothing
to do with this.


6) A photon is the wave superposition of two or more oscillators which only
move once (the so-called "quantum" of energy).

Not sure what you mean by this. You can have photons of a single
frequency as in monochromatic light.


http://www.androcles01.pwp.blueyonder.co.uk/rephoton.gif

This does not elucidate what you claim.


6a) The total energy of two photons is mc^2.

No. The total energy of two photons is E1+E2=(p1+p2)*c=h*(f1+f2).
Photons have no mass.


7) Asking if a photon has mass is asking if a photon has inertia.

Perhaps. But really that point is irrelevant.


8) The path of a photon is curved in a rotating frame:
http://ww2010.atmos.uiuc.edu/(Gh)/guides/mtr/fw/crls.rxml

It's interesting you chose that site as opposed to
http://en.wikipedia.org/wiki/Coriolis_effect
However, the statement is probably correct, providing the frame
rotates fast enough.


9) By observation of 9) Photons have inertia.

Huh? Anyway, it's irrelevant.

10) Photons are not matter.

True; but you already stated that.


11) Whatever matter is, we can only detect it by it radiating energy by
reflection or its own emission.

And collision with other matter, among other ways.


12) Newton was puzzled by "action at a distance", yet accepted the
existence of matter axiomatically. It's a given. What he did not know of
was the periodic table, the Bohr model of the atom or electrodynamics.

So what?


I suggest we reverse that old, worn out way of thinking and accept
action-at-a-distance as a given and then ponder over matter.

Why?



The pieces of the puzzle are all there. Yes, the photon has mass. One can

Now you are contradicting yourself. Photon is not matter, so it can't
have mass since mass is the amount of matter.
[...]
The flaw is that you are self-contradictory and have no conclusion.
Also you seem to not pay much attention to definitions that are
already accepted by physicists.
--
// The TimeLord says:
// Pogo 2.0 = We have met the aliens, and they are us!
.

User: "The_Man"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 18 May 2007 03:50:39 PM
On May 18, 11:52 am, "Androcles" <Engin...@hogwarts.physics> wrote:
<Snipped nonsense, because I know it pisses Androcles ("Roar!") off.

Find a flaw in this argument:

Only one?


3) Intuitively, matter has mass; by definition, by observation, by
experience.

Wow, very deep understanding of particle physics.


4) Newton's third law is conservation of momentum.

So you agree with the law of conservation of ANGULAR momentum, too?


"To every action there is always opposed an equal reaction; or the mutual
actions of two bodies upon each other are always equal, and directed to
contrary parts."

5) Photons are not matter, they are the electromagnetic transfer of energy.
Photons come in pairs. For every photon there is an equal and opposite
rephoton; a restatement of Newton's third law in a different situation.

Yet the existence of SINGLE photons is a requirement of the Law of
conservation of angular momentum!
Suppose we have emission from a 2P (3/2) or 2P (1/2) state to a 1S
state, say in sodium (Ken Seto's obsession). An electron in a p
orbital has a angular momentum quantum number of 1 [for a total
angular momentum of sqrt(2) h bar]. An electron in a p orbital has 0
angular momentum. After emission, the angular momentum is sqrt(2) hbar
less than it was before.
The question for the (ersatz) "engineer" is: what happened to the
missing angular momentum? Haven't we violated the Law of conservation
of angular momentum?


6) A photon is the wave superposition of two or more oscillators which only
move once (the so-called "quantum" of energy).

Blah, blah, blah. Roar, roar, roar.


http://www.androcles01.pwp.blueyonder.co.uk/rephoton.gif

6a) The total energy of two photons is mc^2.

7) Asking if a photon has mass is asking if a photon has inertia.

No, it isn't.


8) The path of a photon is curved in a rotating frame:
http://ww2010.atmos.uiuc.edu/(Gh)/guides/mtr/fw/crls.rxml

9) By observation of 9) Photons have inertia.
10) Photons are not matter.

11) Whatever matter is, we can only detect it by it radiating energy by
reflection or its own emission.

What about absorption?


12) Newton was puzzled by "action at a distance", yet accepted the
existence of matter axiomatically. It's a given. What he did not know of
was the periodic table, the Bohr model of the atom or electrodynamics.

What is all this nonsense about the Bohr model? Even Bohr dropped the
model when much better stuff came along (QM).


I suggest we reverse that old, worn out way of thinking and accept
action-at-a-distance as a given and then ponder over matter.

Maybe take the splinter out of your paw first. Roar!


The pieces of the puzzle are all there. Yes, the photon has mass. One can
apply a force to it and nudge it from its path. That's what a diffraction
grating or prism does.
What a photon lacks is matter. The photon is the link between
action-at-a-distance
and matter, a line of enquiry to investigate.

What *IS* matter?

Is Androcles the cowardly Lion from the Wizard of Oz?


"Great spirits have always found violent opposition from mediocrities."

i.e., Androcles, hanson, malibu, Ken Seto, Y. Porat, ...

"The latter cannot understand it when a man does not thoughtlessly submit to
hereditary prejudices but honestly and courageously uses his
intelligence." -- Einstein.

.


User: "The TimeLord"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 25 May 2007 12:26:34 AM
Pentcho Valev wrote in "sci.physics.relativity":

Androcles wrote:

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[...]

The question:

"Does the speed of light vary in a gravitational field in accordance
with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a

What's the reference for this formula? As far as I know Einstein never
said this nonsense. (The second axiom for SR is that c is the same for
all reference frames.)
[...]

"Does the photon have a mass?"

The mass of a photon is zero by experiment.


Of course, in a normal situation the two questions would always be
considered together. However in Einstein's world the situation is by
no means normal and Einsteinians would take any opportunity to convert
the second question into a red herring. One should not give them such

I take it that you believe experimental fact to be a red herring. If
so what are you doing in "sci.physics.relativity" as in "science"? Why
not take your religion elsewhere?
[...]
--
// The TimeLord says:
// Pogo 2.0 = We have met the aliens, and they are us!
.
User: "Pentcho Valev"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 25 May 2007 12:47:52 AM
The TimeLord wrote:

Pentcho Valev wrote in "sci.physics.relativity":

Androcles wrote:

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[...]

The question:

"Does the speed of light vary in a gravitational field in accordance
with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a


What's the reference for this formula? As far as I know Einstein never
said this nonsense.

He did say it and it is not nonsense. Einstein's 1911 equation
c'=c(1+V/c^2) describing the variability of the speed of light is
consistent with and explains the gravitational redshift factor:
http://www.physlink.com/Education/AskExperts/ae13.cfm "So, IT IS
ABSOLUTELY TRUE THAT THE SPEED OF LIGHT IS NOT CONSTANT in a
gravitational field [which, by the equivalence principle, applies as
well to accelerating (non-inertial) frames of reference]. If this were
not so, there would be no bending of light by the gravitational field
of stars....Indeed, this is exactly how Einstein did the calculation
in: "On the Influence of Gravitation on the Propagation of Light,"
Annalen der Physik, 35, 1911. which predated the full formal
development of general relativity by about four years. This paper is
widely available in English. You can find a copy beginning on page 99
of the Dover book "The Principle of Relativity." You will find in
section 3 of that paper, Einstein's derivation of the (variable) speed
of light in a gravitational potential, eqn (3). The result is, c' = c0
( 1 + V / c^2 ) where V is the gravitational potential relative to the
point where the speed of light c0 is measured."
http://www.blazelabs.com/f-g-gcont.asp "The first confirmation of a
long range variation in the speed of light travelling in space came in
1964. Irwin Shapiro, it seems, was the first to make use of a
previously forgotten facet of general relativity theory -- that the
speed of light is reduced when it passes through a gravitational
field....Faced with this evidence, Einstein stated:"In the second
place our result shows that, according to the general theory of
relativity, the law of the constancy of the velocity of light in
vacuo, which constitutes one of the two fundamental assumptions in the
special theory of relativity and to which we have already frequently
referred, cannot claim any unlimited validity. A curvature of rays of
light can only take place when the velocity of propagation of light
varies with position."......Today we find that since the Special
Theory of Relativity unfortunately became part of the so called
mainstream science, it is considered a sacrilege to even suggest that
the speed of light be anything other than a constant. This is somewhat
surprising since even Einstein himself suggested in a paper "On the
Influence of Gravitation on the Propagation of Light," Annalen der
Physik, 35, 1911, that the speed of light might vary with the
gravitational potential. Indeed, the variation of the speed of light
in a vacuum or space is explicitly shown in Einstein's calculation for
the angle at which light should bend upon the influence of gravity.
One can find his calculation in his paper. The result is c'=c(1+V/c^2)
where V is the gravitational potential relative to the point where the
measurement is taken. 1+V/c^2 is also known as the GRAVITATIONAL
REDSHIFT FACTOR."
Pentcho Valev
.
User: "The TimeLord"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 25 May 2007 07:06:25 PM
Pentcho Valev wrote in "sci.physics.relativity":

The TimeLord wrote:

Pentcho Valev wrote in "sci.physics.relativity":

Androcles wrote:

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[...]

The question:

"Does the speed of light vary in a gravitational field in accordance
with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a

What's the reference for this formula? As far as I know Einstein never
said this nonsense.


He did say it and it is not nonsense. Einstein's 1911 equation
c'=c(1+V/c^2) describing the variability of the speed of light is
consistent with and explains the gravitational redshift factor:

http://www.physlink.com/Education/AskExperts/ae13.cfm "So, IT IS

V here is not speed. You would have known that had you read it
carefully. No wonder your misquote of Einstein sounded so stupid.
[...]

http://www.blazelabs.com/f-g-gcont.asp "The first confirmation of a

Same thing. The discussion there is about gravity, not anything
related to SR.
[...]
In the original message you posted
<1179471503.611164.124340@o5g2000hsb.googlegroups.com>
you specified "...in the absence of a gravitational field..." and then
tried to claim that the speed of light varies there. That is untrue
and Einstein never claimed that light would vary in the absence of a
gravitational field. Now you're trying to introduce gravitational
fields to justify your claim? How unscientific!
Besides, if you take c'=c(1+V/c^2) and take away the gravitational
field, then V=0 and c'=c, not c'=c+v. Simple!
Also you need to realize that according to Albert Einstein ("The
Meaning of Relativity" pp 87-93), this formula (which has been a bit
misquoted by PhysLink.com) is valid only under certain assumptions,
which violate the subject matter in this discussion. Also, Einstein is
very careful to state (p 92) "In the general theory of relativity also
the velocity of light is everywhere the same, relatively to a local
inertial system."
It never ceases to amaze me how people who criticize Einstein and
Relativity fail to understand what they are criticizing. If you are
going to disagree with Relativity, at least try to make an effort to
launch legitimate complaints rather than railing against stuff you
make up and claim are part of Relativity.
--
// The TimeLord says:
// Pogo 2.0 = We have met the aliens, and they are us!
.
User: "Pentcho Valev"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 26 May 2007 03:37:10 AM
The TimeLord wrote:

Pentcho Valev wrote in "sci.physics.relativity":

The TimeLord wrote:

Pentcho Valev wrote in "sci.physics.relativity":

Androcles wrote:

"Pentcho Valev" <pvalev@yahoo.com> wrote in message
news:1179471503.611164.124340@o5g2000hsb.googlegroups.com...

[...]

The question:

"Does the speed of light vary in a gravitational field in accordance
with Einstein's 1911 equation c'=c(1+V/c^2) which, in the absence of a

What's the reference for this formula? As far as I know Einstein never
said this nonsense.


He did say it and it is not nonsense. Einstein's 1911 equation
c'=c(1+V/c^2) describing the variability of the speed of light is
consistent with and explains the gravitational redshift factor:

http://www.physlink.com/Education/AskExperts/ae13.cfm "So, IT IS


V here is not speed. You would have known that had you read it
carefully. No wonder your misquote of Einstein sounded so stupid.

[...]

http://www.blazelabs.com/f-g-gcont.asp "The first confirmation of a


Same thing. The discussion there is about gravity, not anything
related to SR.

[...]

In the original message you posted
<1179471503.611164.124340@o5g2000hsb.googlegroups.com>
you specified "...in the absence of a gravitational field..." and then
tried to claim that the speed of light varies there. That is untrue
and Einstein never claimed that light would vary in the absence of a
gravitational field. Now you're trying to introduce gravitational
fields to justify your claim? How unscientific!

Besides, if you take c'=c(1+V/c^2) and take away the gravitational
field, then V=0 and c'=c, not c'=c+v. Simple!

You do not think anymore Einstein's 1911 equation c'=c(1+V/c^2) is
"nonsense". Good. Concerning your discovery that c'=c(1+V/c^2) leads
to c'=c and not to c'=c+v and that this is just "simple", ask Master
Tom Roberts, e.g. in the following way:
"Oh Master Roberts, oh Albert Einstein of our generation (Hawking has
NEVER been the Albert Einstein of our generation), is science really
so simple?"
Master Tom Roberts will send you a private message and will explain
everything.
Pentcho Valev
.






User: "RP"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 08:31:53 AM
On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:

http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...

On Oct 25, 1995, John Baez wrote in sci.physics:

"Nonetheless, it's a fact that a photon has a nonzero momentum."

A curious person asked:

"Are you therefore asserting that it has nonzero mass? If not, why
not?"

John Baez replied:

"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."

While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.

From the relativistic (Minkowskian) viewpoint, there doesn't even

exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective. Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.
I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.

The curious person could have asked:

"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"

This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.


John Baez would have replied:

"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."

Pentcho Valev

.
User: "The_Man"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 10:00:20 AM
On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:

On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:





http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.

You state as a fact what seems more like an opinion.
Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")
If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


From the relativistic (Minkowskian) viewpoint, there doesn't even


exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective.

But EM interactons never propogate faster than c.

Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.

I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists

ALL physicists are QM physicists :-)

should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.

Often they don't, agreeing with Dirac "Just shut up and calculate."
However, being that QM is the most tested and most accurate model of
the universe ever created, we are fond of using it to poke holes in
other's philosophical musings.


The curious person could have asked:


"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"


This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.





John Baez would have replied:


"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."


Pentcho Valev- Hide quoted text -


- Show quoted text -- Hide quoted text -

- Show quoted text -

.
User: "RP"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 11:25:44 AM
On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:

On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:





On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.

If special relativity is opinion, then I retract my statement :)

Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")

Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.


If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.

The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible. Please explain why my computer cannot
emit a 5terahertz signal.




From the relativistic (Minkowskian) viewpoint, there doesn't even


exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective.


But EM interactons never propogate faster than c.

"In our theory c play the role of infinity".
Please distinguish between "directly" and "instantaneous".


Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.


I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists


ALL physicists are QM physicists :-)

should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.


Often they don't, agreeing with Dirac "Just shut up and calculate."

So it was Dirac who said that? In a previous thread it seemed that
nobody could come up with a direct reference.

However, being that QM is the most tested and most accurate model of
the universe ever created, we are fond of using it to poke holes in
other's philosophical musings.

Well and good. I don't argue against its empirical merit.


The curious person could have asked:


"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"


This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.


John Baez would have replied:


"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."


Pentcho Valev- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -

- Show quoted text -

.
User: "The_Man"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 11:43:59 AM
On May 19, 12:25 pm, RP <no_mail_no_s...@yahoo.com> wrote:

On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:





On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:


On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.


If special relativity is opinion, then I retract my statement :)

Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")


Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.



If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible.

A sodium atoms is electronically excited by heating it. Sodium emits
light at two very specific wavelengths. These correspond to
transitions from 2P 3/2 -> 1S0, or 2P 1/2 -> 1S0. In the proces, the
atom "loses" 1 unit of orbital angular momentum. Where did it go? This
is a simple question...
The 1 unit of orbital angular momentum is carried away by the photon,
which has a spin angular momentum of 1. We never see electronic
transitions involving changes of anything OTHER than 1 unit of angular
momentum.
If you can tell us how you can derive all the selection rules (for
both 1 electron and multi-electron atoms) WITHOUT a photon, all of
chemistry and physics would be glad to hear it. Not the least, that
you would also have to explain the photoelectric effect, and how TV's
work.

Please explain why my computer cannot
emit a 5terahertz signal.

When you turn it on, it almost surely does emit in the Terahertz range
(since this is the range of IR)




From the relativistic (Minkowskian) viewpoint, there doesn't even


exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective.


But EM interactons never propogate faster than c.


"In our theory c play the role of infinity".

"plays the role of infinity" and EQUALS infinity are NOT the same
thing. The fact that the speed of light was NOT infinity was already
known by the 18th century.


Please distinguish between "directly" and "instantaneous".

Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.


I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists


ALL physicists are QM physicists :-)


should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.


Often they don't, agreeing with Dirac "Just shut up and calculate."


So it was Dirac who said that? In a previous thread it seemed that
nobody could come up with a direct reference.

It is one of those aporcryphal stories, but the sentiments are
consistent with those of Dirac.


However, being that QM is the most tested and most accurate model of
the universe ever created, we are fond of using it to poke holes in
other's philosophical musings.


Well and good. I don't argue against its empirical merit.





The curious person could have asked:


"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"


This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.


John Baez would have replied:


"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."


Pentcho Valev- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -

.
User: "RP"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 12:11:28 PM
On May 19, 11:43 am, The_Man <me_so_hornee...@yahoo.com> wrote:

On May 19, 12:25 pm, RP <no_mail_no_s...@yahoo.com> wrote:





On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:


On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.


If special relativity is opinion, then I retract my statement :)


Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")


Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.


If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible.


A sodium atoms is electronically excited by heating it. Sodium emits
light at two very specific wavelengths. These correspond to
transitions from 2P 3/2 -> 1S0, or 2P 1/2 -> 1S0. In the proces, the
atom "loses" 1 unit of orbital angular momentum. Where did it go? This
is a simple question...

It goes to all other electrons via interaction with the source
electrons, directly, at c. Because of the quantum states of recieving
atoms, they absorb energy by the same amount, and that you assume that
this absorbed energy all derived from the same single point source is
for you to prove, not me. That theory goes against all the known laws
of em. Statistically your version works "because" of global momentum
conservation.


The 1 unit of orbital angular momentum is carried away by the photon,
which has a spin angular momentum of 1. We never see electronic
transitions involving changes of anything OTHER than 1 unit of angular
momentum.

If you can tell us how you can derive all the selection rules (for
both 1 electron and multi-electron atoms) WITHOUT a photon, all of
chemistry and physics would be glad to hear it. Not the least, that
you would also have to explain the photoelectric effect, and how TV's
work.

See above. It's more or less a holographic process.


Please explain why my computer cannot
emit a 5terahertz signal.


When you turn it on, it almost surely does emit in the Terahertz range
(since this is the range of IR)



From the relativistic (Minkowskian) viewpoint, there doesn't even


exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective.


But EM interactons never propogate faster than c.


"In our theory c play the role of infinity".


"plays the role of infinity" and EQUALS infinity are NOT the same
thing. The fact that the speed of light was NOT infinity was already
known by the 18th century.

Please distinguish between "directly" and "instantaneous".


Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.


I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists


ALL physicists are QM physicists :-)


should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.


Often they don't, agreeing with Dirac "Just shut up and calculate."


So it was Dirac who said that? In a previous thread it seemed that
nobody could come up with a direct reference.


It is one of those aporcryphal stories, but the sentiments are
consistent with those of Dirac.

That's what I thought :)
at QM is the most tested and most accurate model of

the universe ever created, we are fond of using it to poke holes in
other's philosophical musings.


Well and good. I don't argue against its empirical merit.


The curious person could have asked:


"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"


This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.


John Baez would have replied:


"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."


Pentcho Valev- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -

.
User: "Eric Gisse"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 03:20:08 PM
On May 19, 10:11 am, RP <no_mail_no_s...@yahoo.com> wrote:
[...]
I love watching idiots, like you, argue with someone who has a PhD in
that subject.
.
User: "RP"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 03:36:17 PM
On May 19, 3:20 pm, Eric Gisse <jowr...@gmail.com> wrote:

On May 19, 10:11 am, RP <no_mail_no_s...@yahoo.com> wrote:
[...]

I love watching idiots, like you, argue with someone who has a PhD in
that subject.

Get yourself a second mirror then, and have twice the fun.
.


User: "The_Man"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 12:30:04 PM
On May 19, 1:11 pm, RP <no_mail_no_s...@yahoo.com> wrote:

On May 19, 11:43 am, The_Man <me_so_hornee...@yahoo.com> wrote:





On May 19, 12:25 pm, RP <no_mail_no_s...@yahoo.com> wrote:


On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:


On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.


If special relativity is opinion, then I retract my statement :)


Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")


Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.


If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible.


A sodium atoms is electronically excited by heating it. Sodium emits
light at two very specific wavelengths. These correspond to
transitions from 2P 3/2 -> 1S0, or 2P 1/2 -> 1S0. In the proces, the
atom "loses" 1 unit of orbital angular momentum. Where did it go? This
is a simple question...


It goes to all other electrons via interaction with the source
electrons, directly, at c.

So the angular momentum of the other electrons change? Yet, if that
happened, you would violate the law of conservation of energy. There
is an even easier refutation - suppose we talking about the spectrum
of hydrogen, which has NO other electrons.
Now the ball is in your court, to explain the selection rules for
hydrogen: Delta l = +/1 1, delta s =0; delta m sub l = 0, +/-1.

Because of the quantum states of recieving
atoms, they absorb energy by the same amount, and that you assume that
this absorbed energy all derived from the same single point source is
for you to prove, not me.

Proven LONG ago. Lasers do single photo absorption experiments all the
time. This is the so-called "resonance condition" - It is the basis of
all spectroscopy.

That theory goes against all the known laws
of em. Statistically your version works "because" of global momentum
conservation.



The 1 unit of orbital angular momentum is carried away by the photon,
which has a spin angular momentum of 1. We never see electronic
transitions involving changes of anything OTHER than 1 unit of angular
momentum.


If you can tell us how you can derive all the selection rules (for
both 1 electron and multi-electron atoms) WITHOUT a photon, all of
chemistry and physics would be glad to hear it. Not the least, that
you would also have to explain the photoelectric effect, and how TV's
work.


See above. It's more or less a holographic process.

No. There is a one-to-one correspondence between the number of photns
absorbed and the number of electrons emitted during the photoelectric
effect.








Please explain why my computer cannot
emit a 5terahertz signal.


When you turn it on, it almost surely does emit in the Terahertz range
(since this is the range of IR)


From the relativistic (Minkowskian) viewpoint, there doesn't even


exist em radiation period, not even in the form of classical em waves;
charges interact directly with one another, and the delay that we see
is a result of our mistaken Galilean observational perspective.


But EM interactons never propogate faster than c.


"In our theory c play the role of infinity".


"plays the role of infinity" and EQUALS infinity are NOT the same
thing. The fact that the speed of light was NOT infinity was already
known by the 18th century.


Please distinguish between "directly" and "instantaneous".


Time
is other than what Newton said it was, that is, it is not the same
time here as it is there. The em field of a charged particle subtends
space and time, rather than space alone.
There exists a coordinate system in which the field of a charged
particle remains perfectly rigid, but in that system the field extends
through time as well as space, which is contrary to our "assumed"
perspective of things existing only from moment to moment.


I've heard the photon-mass debate a million times in this NG, to the
point that it really is boring, boring, boring, but not the subject,
just argument itself. It's the SOS. The QM approach, empirically valid
as it may be, is not an explanation of things, it is only a
statistical quantification. QM physicists


ALL physicists are QM physicists :-)


should refrain from offering
up philosophical interpretations as fact, and especailly as
counterargument to arguments against their philosophical
interpretations.


Often they don't, agreeing with Dirac "Just shut up and calculate."


So it was Dirac who said that? In a previous thread it seemed that
nobody could come up with a direct reference.


It is one of those aporcryphal stories, but the sentiments are
consistent with those of Dirac.


That's what I thought :)

at QM is the most tested and most accurate model of



the universe ever created, we are fond of using it to poke holes in
other's philosophical musings.


Well and good. I don't argue against its empirical merit.


The curious person could have asked:


"Are you therefore asserting that the speed of light varies in a
gravitational field in accordance with Einstein's 1911 equation
c'=c(1+V/c^2) which, in the absence of a gravitational field, becomes
c'=c+v, where v is the relative speed of the light source and the
observer?"


This is simple algebra, and I've never seen a worse example of
deriving a solution. If V=0, then the equation reduces to c' = c. That
you blindly quote this stupidity over and over is good reason to
suggest that you're nothing other than a troll in this group.


John Baez would have replied:


"You can see that I did not assert anything about the variable speed
of light. I know how the speed of light varies in a gravitational
field, but I never talk about it around here because the endless
discussion of the variability of the speed of light is boring, boring,
boring."


Pentcho Valev- Hide quoted text -


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.
User: "RP"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 03:42:30 PM
On May 19, 12:30 pm, The_Man <me_so_hornee...@yahoo.com> wrote:

On May 19, 1:11 pm, RP <no_mail_no_s...@yahoo.com> wrote:





On May 19, 11:43 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 12:25 pm, RP <no_mail_no_s...@yahoo.com> wrote:


On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:


On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.


If special relativity is opinion, then I retract my statement :)


Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")


Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.


If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible.


A sodium atoms is electronically excited by heating it. Sodium emits
light at two very specific wavelengths. These correspond to
transitions from 2P 3/2 -> 1S0, or 2P 1/2 -> 1S0. In the proces, the
atom "loses" 1 unit of orbital angular momentum. Where did it go? This
is a simple question...


It goes to all other electrons via interaction with the source
electrons, directly, at c.


So the angular momentum of the other electrons change? Yet, if that
happened, you would violate the law of conservation of energy. There
is an even easier refutation - suppose we talking about the spectrum
of hydrogen, which has NO other electrons.

Now the ball is in your court, to explain the selection rules for
hydrogen: Delta l = +/1 1, delta s =0; delta m sub l = 0, +/-1.

Because of the quantum states of recieving
atoms, they absorb energy by the same amount, and that you assume that
this absorbed energy all derived from the same single point source is
for you to prove, not me.


Proven LONG ago. Lasers do single photo absorption experiments all the
time. This is the so-called "resonance condition" - It is the basis of
all spectroscopy.





That theory goes against all the known laws
of em. Statistically your version works "because" of global momentum
conservation.


The 1 unit of orbital angular momentum is carried away by the photon,
which has a spin angular momentum of 1. We never see electronic
transitions involving changes of anything OTHER than 1 unit of angular
momentum.


If you can tell us how you can derive all the selection rules (for
both 1 electron and multi-electron atoms) WITHOUT a photon, all of
chemistry and physics would be glad to hear it. Not the least, that
you would also have to explain the photoelectric effect, and how TV's
work.


See above. It's more or less a holographic process.


No. There is a one-to-one correspondence between the number of photns
absorbed and the number of electrons emitted during the photoelectric
effect.

Incorrect. You can't count the photons, only the photoelectrons. At
any given moment a surface is being impinged upon by radiation from
very many sources. If I'm allowed to speak, for arguments sake, of
this radiation in terms of photons, then the number of photons
striking the target is far greater than the photoelectrons. You simply
disgard the fact that the surface is pumped, because it suits your
argument. Again, it is still for you to prove the one-to-one
correspondence that you assume.
.
User: "The_Man"

Title: Re: RELATIVITY HYPNOTISTS ABOUT THE PHOTON MASS 19 May 2007 06:50:37 PM
On May 19, 4:42 pm, RP <no_mail_no_s...@yahoo.com> wrote:

On May 19, 12:30 pm, The_Man <me_so_hornee...@yahoo.com> wrote:





On May 19, 1:11 pm, RP <no_mail_no_s...@yahoo.com> wrote:


On May 19, 11:43 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 12:25 pm, RP <no_mail_no_s...@yahoo.com> wrote:


On May 19, 10:00 am, The_Man <me_so_hornee...@yahoo.com> wrote:


On May 19, 9:31 am, RP <no_mail_no_s...@yahoo.com> wrote:


On May 18, 1:58 am, Pentcho Valev <pva...@yahoo.com> wrote:


http://groups.google.com/group/sci.physics/browse_frm/thread/d28e668a...


On Oct 25, 1995, John Baez wrote in sci.physics:


"Nonetheless, it's a fact that a photon has a nonzero momentum."


A curious person asked:


"Are you therefore asserting that it has nonzero mass? If not, why
not?"


John Baez replied:


"You can see that I did not assert anything about the photon's mass. I
know what the photon's mass is, but I never talk about it around here
because the endless discussion of the photon's mass is boring, boring,
boring."


While I don't agree that the topic is boring, I do agree that it isn't
easy to understand, so I'll try to explain it. Photons don't exist.
Nothing that doesn't exist has mass.


You state as a fact what seems more like an opinion.


If special relativity is opinion, then I retract my statement :)


Photons have (spin) angular mometum. If photons "don't exist", the law
of conservation of angular momentum falls apart. Along with it, the
understanding of which electronic transitons occur, and how often they
occur (what we call "selection rules")


Photons don't have anything, because they don't exist. Momentum is
globally conserved, not locally conserved. The solution to the
radiation reaction problem is that there isn't a reaction, just an
action. Electrons are foward acting particles. The past light cone
contains events that influence the electron, the foward light cone
those events that it influences. There is no experimental evidence of
electron recoil under the influence of its own emitted radiation.
Before replying please note a distinction between a single electron
and an array of electrons, the latter of which produces feedback
effects.


If you can explain why s-> d transitions don't occur, or why p->p
transitions don't occur, or why d->d transitions for high spin Fe 3+
occur with such a small probability, I'm all ears.


The atom is an electronic structure in equilibrium. Some states are
unstable and others impossible.


A sodium atoms is electronically excited by heating it. Sodium emits
light at two very specific wavelengths. These correspond to
transitions from 2P 3/2 -> 1S0, or 2P 1/2 -> 1S0. In the proces, the
atom "loses" 1 unit of orbital angular momentum. Where did it go? This
is a simple question...


It goes to all other electrons via interaction with the source
electrons, directly, at c.


So the angular momentum of the other electrons change? Yet, if that
happened, you would violate the law of conservation of energy. There
is an even easier refutation - suppose we talking about the spectrum
of hydrogen, which has NO other electrons.


Now the ball is in your court, to explain the selection rules for
hydrogen: Delta l = +/1 1, delta s =0; delta m sub l = 0, +/-1.


Because of the quantum states of recieving
atoms, they absorb energy by the same amount, and that you assume that
this absorbed energy all derived from the same single point source is
for you to prove, not me.


Proven LONG ago. Lasers do single photo absorption experiments all the
time. This is the so-called "resonance condition" - It is the basis of
all spectroscopy.


That theory goes against all the known laws
of em. Statistically your version works "because" of global momentum
conservation.


The 1 unit of orbital angular momentum is carried away by the photon,
which has a spin angular momentum of 1. We never see electronic
transitions involving changes of anything OTHER than 1 unit of angular
momentum.


If you can tell us how you can derive all the selection rules (for
both 1 electron and multi-electron atoms) WITHOUT a photon, all of
chemistry and physics would be glad to hear it. Not the least, that
you would also have to explain the photoelectric effect, and how TV's
work.


See above. It's more or less a holographic process.


No. There is a one-to-one correspondence between the number of photns
absorbed and the number of electrons emitted during the photoelectric
effect.


Incorrect. You can't count the photons, only the photoelectrons. At
any given moment a surface is being impinged upon by radiation from
very many sources.

Actually, photon counting is relatively (no pun intended) simple. It
is done all the time - it is necesary to determine the quantum
efficiency of such processes as fluorescence.
As for the "surface being impinged upon by radiation from very many
sources", this suggests a very incompetent experimentalist. The
surface would be sputtered with Ar+ to clean crap off the surface, the
surface would be kept in high vacuum, and all radiation sources other
than the source would be shielded against.

If I'm allowed to speak, for arguments sake, of
this radiation in terms of photons, then the number of photons
striking the target is far greater than the photoelectrons.

I didn't say "striking the target", I said "absorbed". The number of
photons NOT absorbed strikes a detector, and are counted. The number
of electrons ejected is also easily counted. So long as the photons
had the necessry energy, yadda yadda yadda, the # photons launched = #
photons NOT absorbed + # electrons emitted.

You simply
disgard the fact that the surface is pumped, because it suits your
argument. Again, it is still for you to prove the one-to-one
correspondence that you assume.

It is more straightforward to analyze in terms of absorption by atoms,
rather surfaces. You are confusing the fact of the probability of
absorption of a particular photon, which is usually less than 1, with
the probability that upon absorption, the photon will cause a change
in orbital angular momentum of 1 unit, which is exactly1. Of course,
the photon has to have the right energy to cause an electronic
transition, blah,blah, blah, which you don't understand anyway.
The emission spectrum of hydrogen was explained by Bohr - it is quite
simple. The spectra of heavier elements is more complicated (electron
electron repulsion complicates the analysis). Each line corresponds to
the energy difference between two electronic levels in hydrogen, ALL
of which differ in orbital angular momentum by sqrt(2) h bar.
If that isn't good enough for you, too bad. I don't have time to
repeat the results of 100 years of experiments.
You're the contrary one. Just show which lines of ANY atom result from
a change in other than 1 unit of angular momentum. If you understood L-
S or j-j coupling, I would put it in the requisite clarifications, but
I am sure that it is over your head. Just as the normal or anoma