Seto Light Clock Fallacy & False Assumptions



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Topic: Science > Physics
User: "Kowstue"
Date: 08 Jun 2007 08:59:29 AM
Object: Seto Light Clock Fallacy & False Assumptions
In 2025, Seto (or his kids) may still be here to haunt
our grandchildren so we may as well resolve this early
to avoid wasting time.
Reviewing Seto 2005 paper for more than an hour today.
Here's where he made the major false assumptions
that mess up his SR ideas for more than a decade.
After quoting the essential paragraphs of his that
shows his major fallacy (taken from page 16 of
http://www.geocities.com/kn_seto/2005Unification.pdf)
i'll continue my comments of his false assumption.
Seto explained:
"How does light get from point A to point B? The
current assumption is that, locally, light travels
in a straight line towards the target, and that,
in a train of light pulses, the first pulse hits
the target is the first one the source generated.
These assumptions both make sense if the target is
stationary relative to the light pulses, but if
the target moves the second assumption could be
erroneous. Fig 3 describes a thought experiment
that is currently used by physicists to derive the
time dilation equation. A light clock is
constructed of two mirrors parallel to each other
with light pulses bouncing between them. In one
period of the clock, a light pulse travels up to
the top mirror and returns back to the bottom
mirror. The diagram shows that the light pulse is
presumed to travel a slant path when the light
clock is in motion. This is not a realistic
description of the actual event. It raises the
question: How does light know when to follow a
vertical path and when to follow one of the
infinite numbers of slant paths? It is more
realistic to say that light will always follow the
perpendicular path on its way to the upper mirror.
The reason is that the vertical path is the
direction where all the light pulses are directed.
Figure 4 shows this: the first pulse of a train of
pulses follows the original path AB, but the pulse
detected at "E" travels the path CE.
<snip see page 16 of his paper>
(Seto continued)
.... When the mirrors are moving at the speed of light,
no light pulse is able to reach the upper mirror
at all. Current physics interprets this situation
as time standing still at the speed of light. The
new interpretation is that time keeps on ticking
at all speeds of the light clock. The amount of
time (duration) passed depends on the length of
the original light path AB divided by the speed of
light `c'. This new interpretation suggests that
absolute time for a moving frame is not slowed or
dilated as currently assumed. The specific amount
of absolute time (duration) required for light to
travel the original light path AB is equal in all
frames. A light clock runs slow when it is in
motion because it is not catching the first light
pulses, but rather some later one. The lower
elapsed time recorded by a moving clock because
the passage of time is not fully detected when the
clock is in a state of motion.
---------------------------------
My comments (Kows):
In our relativistic universe, the light beam would
get up and reflected down in any inertial frame. Now
what Seto is thinking is that since his light travel
in his aether. When the light beam goes up, it
won't hit the celing mirror in the first few pulses
because the aether is fixed and the light clock is
moving and so the light won't hit the mirror, gets?
Here he notes that the clock in the moving frame
is beating slower because the detector doesn't
get all the light sent because some is lost. This
is how he understood the clock of the moving object
to be slower but it is just the light clock slowing
and not the objects in the moving frame. He believes
in absolute time and absolution motion (that is
an object moving against the fixed background).
So you see, his false assumption is because he
assumes a fixed aether so his reasoning is
connected with it and all the mathematics that
goes with it. Now if he assumes a relativistic
universe, he would know that there is no aether
and so light clock will have the beam still reaching
the mirror on top. And the reason for the time dilation
is because of the finite speed of light and the delay
which is projected to our frame of reference
making the perspective becoming real in that
the time of the moving frame indeed slow down
relative to ours (although of course the objects
in the moving frame wont feel time slowing down).
Now if he uses an atomic clock in his thought
experiment 20 years ago he may not have the
problem. His aether explanation is ingenious
though like LET.. ad hoc but modern experiments
have proven him long as time dilation really have
physical effect in that after comparison later,
there is time difference in the physical state of
the objects such as muon living longer, etc.
Seto. Give reason a chance.
Kows
.

User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 08 Jun 2007 01:18:05 PM
"Kowstue" <kowstue@yahoo.com> wrote in message
news:1181311169.128077.284870@q19g2000prn.googlegroups.com...


In 2025, Seto (or his kids) may still be here to haunt
our grandchildren so we may as well resolve this early
to avoid wasting time.

Reviewing Seto 2005 paper for more than an hour today.
Here's where he made the major false assumptions
that mess up his SR ideas for more than a decade.
After quoting the essential paragraphs of his that
shows his major fallacy (taken from page 16 of
http://www.geocities.com/kn_seto/2005Unification.pdf)
i'll continue my comments of his false assumption.

Seto explained:

"How does light get from point A to point B? The
current assumption is that, locally, light travels
in a straight line towards the target, and that,
in a train of light pulses, the first pulse hits
the target is the first one the source generated.
These assumptions both make sense if the target is
stationary relative to the light pulses, but if
the target moves the second assumption could be
erroneous. Fig 3 describes a thought experiment
that is currently used by physicists to derive the
time dilation equation. A light clock is
constructed of two mirrors parallel to each other
with light pulses bouncing between them. In one
period of the clock, a light pulse travels up to
the top mirror and returns back to the bottom
mirror. The diagram shows that the light pulse is
presumed to travel a slant path when the light
clock is in motion. This is not a realistic
description of the actual event. It raises the
question: How does light know when to follow a
vertical path and when to follow one of the
infinite numbers of slant paths? It is more
realistic to say that light will always follow the
perpendicular path on its way to the upper mirror.
The reason is that the vertical path is the
direction where all the light pulses are directed.
Figure 4 shows this: the first pulse of a train of
pulses follows the original path AB, but the pulse
detected at "E" travels the path CE.

<snip see page 16 of his paper>
(Seto continued)
... When the mirrors are moving at the speed of light,
no light pulse is able to reach the upper mirror
at all. Current physics interprets this situation
as time standing still at the speed of light. The
new interpretation is that time keeps on ticking
at all speeds of the light clock. The amount of
time (duration) passed depends on the length of
the original light path AB divided by the speed of
light `c'. This new interpretation suggests that
absolute time for a moving frame is not slowed or
dilated as currently assumed. The specific amount
of absolute time (duration) required for light to
travel the original light path AB is equal in all
frames. A light clock runs slow when it is in
motion because it is not catching the first light
pulses, but rather some later one. The lower
elapsed time recorded by a moving clock because
the passage of time is not fully detected when the
clock is in a state of motion.

---------------------------------
My comments (Kows):

In our relativistic universe, the light beam would
get up and reflected down in any inertial frame. Now
what Seto is thinking is that since his light travel
in his aether. When the light beam goes up, it
won't hit the celing mirror in the first few pulses
because the aether is fixed and the light clock is
moving and so the light won't hit the mirror, gets?

That's right the first few pulses won't hit the ceiling mirror. If that's
not the case, the leading edge of the light ray (the first photon) will hit
the target. That would mean that you would know the velocity and the
position of the first photon simultaneously.....that is a violation of the
Uncertainty Principle.

Here he notes that the clock in the moving frame
is beating slower because the detector doesn't
get all the light sent because some is lost.

That's right it just mean that a cycle of the moving light clock will take a
larger amount of absolute time to complete.

This
is how he understood the clock of the moving object
to be slower but it is just the light clock slowing
and not the objects in the moving frame.

A moving cycle of the light clock contains a larger amount of absolute time.

He believes
in absolute time and absolution motion (that is
an object moving against the fixed background).

Clock time and absolute time are relatied as follows:
A clock second will contain a different amount of absolute time in different
frames. SR
wrongly assumes that the passage of a clock second in frame A corresponds to
the passage of a clock second in all frames.

So you see, his false assumption is because he
assumes a fixed aether so his reasoning is
connected with it and all the mathematics that
goes with it.

Ah but that is not a false assumption. I have proposed experiments that
detects the existence of this fixed aether. BTW that's more than what SR
offers.

Now if he assumes a relativistic
universe, he would know that there is no aether
and so light clock will have the beam still reaching
the mirror on top.

Except that the light beam will have to know which of the infinite diagonal
paths to follow. Such bogus assumption is beyond logic.
Also relative motion between two object is related to their absolute motions
as follows:
Relative velocity between A and B is the vector different of the vector
component of A's absolute motion and the vector component of B's absolute
motion along the line joining A and B.

And the reason for the time dilation
is because of the finite speed of light and the delay
which is projected to our frame of reference
making the perspective becoming real in that
the time of the moving frame indeed slow down
relative to ours (although of course the objects
in the moving frame wont feel time slowing down).

This assumptiuon of SR is incomplete. In the real universe all objects are
in a state of absolute motion. Therefore the observer's clock can run fast
or slow compared to the observed clock. Why? Because the rate of passage of
clock second in each clock is dependent on the state of absolute motion of
the clock. The higher is the state of absolute motion the slower is the rate
of passage of clock seconds. This mean that a clock second in a faster
moving clock will contain a larger amount of absolute time than a clock
second in a slower moving clock. This is the true reason for the SR concept
of time dilation.

Now if he uses an atomic clock in his thought
experiment 20 years ago he may not have the
problem. His aether explanation is ingenious
though like LET.. ad hoc but modern experiments
have proven him long as time dilation really have
physical effect in that after comparison later,
there is time difference in the physical state of
the objects such as muon living longer, etc.

The correct explanation for muon time dilation is as follows:
The decaying process for a subatomic particle such as a muon is different
from that for a neutron. It was found that a muon at a speed closed to that
of light would have a much longer decay length than that of a muon at the
rest frame of the laboratory. When these decay lengths are converted to
decay times they agree with the SRT time dilation equation. This led
physicists to claim that the muon decaying process is a proof of the time
dilation concept of SRT. The Model Mechanical explanation of the muon decay
process is as follows:
1. The orbit of the muon's S-Particle is unstable and it will decay into a
stable orbit of the electron.
2. In the rest frame of the Lab a muon decays in 2.2 microseconds. However,
a muon moving with respect to the Lab will have a longer decay time of
(2.2*10^-6)(F_aa/F_ab)seconds.
3. Therefore from the Lab point of view the decay length for a traveling
muon is:
v(2.2*10^-6)(F_aa/F_ab) meters
Where v is the relative velocity between the Lab and the traveling muon.
This Model Mechanical prediction for the decay length of a traveling muon
agrees with experimental observations.


Seto. Give reason a chance.

ROTFLOL....you need to get a better understanding of my theory before you
criticize it.
Ken Seto
.
User: "Kowstue"

Title: Re: Seto Light Clock Fallacy & False Assumptions 08 Jun 2007 05:34:14 PM
On Jun 9, 2:18 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message

news:1181311169.128077.284870@q19g2000prn.googlegroups.com...







In 2025, Seto (or his kids) may still be here to haunt
our grandchildren so we may as well resolve this early
to avoid wasting time.


Reviewing Seto 2005 paper for more than an hour today.
Here's where he made the major false assumptions
that mess up his SR ideas for more than a decade.
After quoting the essential paragraphs of his that
shows his major fallacy (taken from page 16 of
http://www.geocities.com/kn_seto/2005Unification.pdf)
i'll continue my comments of his false assumption.


Seto explained:


"How does light get from point A to point B? The
current assumption is that, locally, light travels
in a straight line towards the target, and that,
in a train of light pulses, the first pulse hits
the target is the first one the source generated.
These assumptions both make sense if the target is
stationary relative to the light pulses, but if
the target moves the second assumption could be
erroneous. Fig 3 describes a thought experiment
that is currently used by physicists to derive the
time dilation equation. A light clock is
constructed of two mirrors parallel to each other
with light pulses bouncing between them. In one
period of the clock, a light pulse travels up to
the top mirror and returns back to the bottom
mirror. The diagram shows that the light pulse is
presumed to travel a slant path when the light
clock is in motion. This is not a realistic
description of the actual event. It raises the
question: How does light know when to follow a
vertical path and when to follow one of the
infinite numbers of slant paths? It is more
realistic to say that light will always follow the
perpendicular path on its way to the upper mirror.
The reason is that the vertical path is the
direction where all the light pulses are directed.
Figure 4 shows this: the first pulse of a train of
pulses follows the original path AB, but the pulse
detected at "E" travels the path CE.


<snip see page 16 of his paper>
(Seto continued)
... When the mirrors are moving at the speed of light,
no light pulse is able to reach the upper mirror
at all. Current physics interprets this situation
as time standing still at the speed of light. The
new interpretation is that time keeps on ticking
at all speeds of the light clock. The amount of
time (duration) passed depends on the length of
the original light path AB divided by the speed of
light `c'. This new interpretation suggests that
absolute time for a moving frame is not slowed or
dilated as currently assumed. The specific amount
of absolute time (duration) required for light to
travel the original light path AB is equal in all
frames. A light clock runs slow when it is in
motion because it is not catching the first light
pulses, but rather some later one. The lower
elapsed time recorded by a moving clock because
the passage of time is not fully detected when the
clock is in a state of motion.


---------------------------------
My comments (Kows):


In our relativistic universe, the light beam would
get up and reflected down in any inertial frame. Now
what Seto is thinking is that since his light travel
in his aether. When the light beam goes up, it
won't hit the celing mirror in the first few pulses
because the aether is fixed and the light clock is
moving and so the light won't hit the mirror, gets?


That's right the first few pulses won't hit the ceiling mirror. If that's
not the case, the leading edge of the light ray (the first photon) will hit
the target. That would mean that you would know the velocity and the
position of the first photon simultaneously.....that is a violation of the
Uncertainty Principle.

Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the way.
To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the Uncertainty
Principle
because the photon in an electromagnetic wave doesn't have definite
position but probabilistic. Also if your argument is right that the
aether
is fixed and the light would be left behind. There is possibility
that no pulse would hit the mirror at all because all the
light would be left behind.


Here he notes that the clock in the moving frame
is beating slower because the detector doesn't
get all the light sent because some is lost.


That's right it just mean that a cycle of the moving light clock will take a
larger amount of absolute time to complete.

Yes. After looking at your postulates for like 15 minutes figuring out
how you got all the math. The portions about the light clock made
me realized how you did them.


This
is how he understood the clock of the moving object
to be slower but it is just the light clock slowing
and not the objects in the moving frame.


A moving cycle of the light clock contains a larger amount of absolute time.

He believes
in absolute time and absolution motion (that is
an object moving against the fixed background).


Clock time and absolute time are relatied as follows:
A clock second will contain a different amount of absolute time in different
frames. SR
wrongly assumes that the passage of a clock second in frame A corresponds to
the passage of a clock second in all frames.

So you see, his false assumption is because he
assumes a fixed aether so his reasoning is
connected with it and all the mathematics that
goes with it.


Ah but that is not a false assumption. I have proposed experiments that
detects the existence of this fixed aether. BTW that's more than what SR
offers.

Now if he assumes a relativistic
universe, he would know that there is no aether
and so light clock will have the beam still reaching
the mirror on top.


Except that the light beam will have to know which of the infinite diagonal
paths to follow. Such bogus assumption is beyond logic.
Also relative motion between two object is related to their absolute motions
as follows:
Relative velocity between A and B is the vector different of the vector
component of A's absolute motion and the vector component of B's absolute
motion along the line joining A and B.

Assume the light beam is a laser, since it doesn't need aether to move
and independent of any reference frame, it can go straight. No need
to ask how the light beam will have to know which of the infinite
diagonal paths to follow. You are assuming aether dynamics when
relativistic setup would explain it.


And the reason for the time dilation
is because of the finite speed of light and the delay
which is projected to our frame of reference
making the perspective becoming real in that
the time of the moving frame indeed slow down
relative to ours (although of course the objects
in the moving frame wont feel time slowing down).


This assumptiuon of SR is incomplete. In the real universe all objects are
in a state of absolute motion. Therefore the observer's clock can run fast
or slow compared to the observed clock. Why? Because the rate of passage of
clock second in each clock is dependent on the state of absolute motion of
the clock. The higher is the state of absolute motion the slower is the rate
of passage of clock seconds. This mean that a clock second in a faster
moving clock will contain a larger amount of absolute time than a clock
second in a slower moving clock. This is the true reason for the SR concept
of time dilation.

Because you are assuming its the aether that does them when SR can
give a more elegant explanation but in the end experimental data will
prevail.


Now if he uses an atomic clock in his thought
experiment 20 years ago he may not have the
problem. His aether explanation is ingenious
though like LET.. ad hoc but modern experiments
have proven him long as time dilation really have
physical effect in that after comparison later,
there is time difference in the physical state of
the objects such as muon living longer, etc.


The correct explanation for muon time dilation is as follows:
The decaying process for a subatomic particle such as a muon is different
from that for a neutron. It was found that a muon at a speed closed to that
of light would have a much longer decay length than that of a muon at the
rest frame of the laboratory. When these decay lengths are converted to
decay times they agree with the SRT time dilation equation. This led
physicists to claim that the muon decaying process is a proof of the time
dilation concept of SRT. The Model Mechanical explanation of the muon decay
process is as follows:

How about electrons being swirled in particle accelerators. Their
lifetime is
also increased.


1. The orbit of the muon's S-Particle is unstable and it will decay into a
stable orbit of the electron.

Gee. You are serious about the S-Particle are you. The first few pages
of your paper is the worse. How can the E-Matrix maintain the constant
orbital of the S-Particles around the E-Strings?? Also you talk about
clockwise and counterclockwise helical spin of the S-Particles around
the E-Strings. But how do you tell what is clockwise and
counterclockwise
then there is nothing to compare it too.

2. In the rest frame of the Lab a muon decays in 2.2 microseconds. However,
a muon moving with respect to the Lab will have a longer decay time of
(2.2*10^-6)(F_aa/F_ab)seconds.
3. Therefore from the Lab point of view the decay length for a traveling
muon is:
v(2.2*10^-6)(F_aa/F_ab) meters
Where v is the relative velocity between the Lab and the traveling muon.
This Model Mechanical prediction for the decay length of a traveling muon
agrees with experimental observations.

To Jim Black. The reason I wanted to discuss with Seto is because
somehow I wished he was right. Instantaneous quantum link breaks
the spirit of relativity and what if there are a priveleged frame of
reference. But of course experimental data prevails. Seto is the
most persuasive SR aetherist out there.
Kows




Seto. Give reason a chance.


ROTFLOL....you need to get a better understanding of my theory before you
criticize it.

Ken Seto- Hide quoted text -

- Show quoted text -

.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 09 Jun 2007 09:07:28 AM
"Kowstue" <kowstue@yahoo.com> wrote in message
news:1181342054.843575.89110@x35g2000prf.googlegroups.com...

On Jun 9, 2:18 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message

news:1181311169.128077.284870@q19g2000prn.googlegroups.com...




Reviewing Seto 2005 paper for more than an hour today.
Here's where he made the major false assumptions
that mess up his SR ideas for more than a decade.
After quoting the essential paragraphs of his that
shows his major fallacy (taken from page 16 of
http://www.geocities.com/kn_seto/2005Unification.pdf)
i'll continue my comments of his false assumption.


Seto explained:


"How does light get from point A to point B? The
current assumption is that, locally, light travels
in a straight line towards the target, and that,
in a train of light pulses, the first pulse hits
the target is the first one the source generated.
These assumptions both make sense if the target is
stationary relative to the light pulses, but if
the target moves the second assumption could be
erroneous. Fig 3 describes a thought experiment
that is currently used by physicists to derive the
time dilation equation. A light clock is
constructed of two mirrors parallel to each other
with light pulses bouncing between them. In one
period of the clock, a light pulse travels up to
the top mirror and returns back to the bottom
mirror. The diagram shows that the light pulse is
presumed to travel a slant path when the light
clock is in motion. This is not a realistic
description of the actual event. It raises the
question: How does light know when to follow a
vertical path and when to follow one of the
infinite numbers of slant paths? It is more
realistic to say that light will always follow the
perpendicular path on its way to the upper mirror.
The reason is that the vertical path is the
direction where all the light pulses are directed.
Figure 4 shows this: the first pulse of a train of
pulses follows the original path AB, but the pulse
detected at "E" travels the path CE.


<snip see page 16 of his paper>
(Seto continued)
... When the mirrors are moving at the speed of light,
no light pulse is able to reach the upper mirror
at all. Current physics interprets this situation
as time standing still at the speed of light. The
new interpretation is that time keeps on ticking
at all speeds of the light clock. The amount of
time (duration) passed depends on the length of
the original light path AB divided by the speed of
light `c'. This new interpretation suggests that
absolute time for a moving frame is not slowed or
dilated as currently assumed. The specific amount
of absolute time (duration) required for light to
travel the original light path AB is equal in all
frames. A light clock runs slow when it is in
motion because it is not catching the first light
pulses, but rather some later one. The lower
elapsed time recorded by a moving clock because
the passage of time is not fully detected when the
clock is in a state of motion.


---------------------------------
My comments (Kows):


In our relativistic universe, the light beam would
get up and reflected down in any inertial frame. Now
what Seto is thinking is that since his light travel
in his aether. When the light beam goes up, it
won't hit the celing mirror in the first few pulses
because the aether is fixed and the light clock is
moving and so the light won't hit the mirror, gets?


That's right the first few pulses won't hit the ceiling mirror. If

that's

not the case, the leading edge of the light ray (the first photon) will

hit

the target. That would mean that you would know the velocity and the
position of the first photon simultaneously.....that is a violation of

the

Uncertainty Principle.


Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the way.

To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the Uncertainty
Principle
because the photon in an electromagnetic wave doesn't have definite
position but probabilistic.

No if the first photon hit the mirror it would mean that you will know the
position and velocity of the first photon and that certainly is a violation
of the Uncertainty Principle.

Also if your argument is right that the
aether
is fixed and the light would be left behind. There is possibility
that no pulse would hit the mirror at all because all the
light would be left behind.

No.....the speed of light being transmitted by the E-Matrix is much faster
than the moving light clock. Therefore the photons generated at a later time
will be able to hit the top mirror. If the speed of the light clock is at
the speed of light then no photon will be able to hit the top mirror. SR
interprets this situation as that time stands still at the speed of light.
IRT interprets this situation as that absolute time keep on passing at the
same rate but a clock second for a c moving light clock contains an infinite
amount of absolute time.




Here he notes that the clock in the moving frame
is beating slower because the detector doesn't
get all the light sent because some is lost.


That's right it just mean that a cycle of the moving light clock will

take a

larger amount of absolute time to complete.


Yes. After looking at your postulates for like 15 minutes figuring out
how you got all the math. The portions about the light clock made
me realized how you did them.


This
is how he understood the clock of the moving object
to be slower but it is just the light clock slowing
and not the objects in the moving frame.


A moving cycle of the light clock contains a larger amount of absolute

time.


Now if he assumes a relativistic
universe, he would know that there is no aether
and so light clock will have the beam still reaching
the mirror on top.


Except that the light beam will have to know which of the infinite

diagonal

paths to follow. Such bogus assumption is beyond logic.
Also relative motion between two object is related to their absolute

motions

as follows:
Relative velocity between A and B is the vector different of the vector
component of A's absolute motion and the vector component of B's

absolute

motion along the line joining A and B.


Assume the light beam is a laser, since it doesn't need aether to move
and independent of any reference frame, it can go straight. No need
to ask how the light beam will have to know which of the infinite
diagonal paths to follow. You are assuming aether dynamics when
relativistic setup would explain it.

This is not true....how can it go striaght perpendicular path if it has to
follow a slant path on its way to the top mirror?. If the light beam is a
laser the leading edge of this laser is the first photon. If the first
photon hits your target that would mean that the velocity and the position
of the first photon is known simultaneously. That is a violation of the UP.



And the reason for the time dilation
is because of the finite speed of light and the delay
which is projected to our frame of reference
making the perspective becoming real in that
the time of the moving frame indeed slow down
relative to ours (although of course the objects
in the moving frame wont feel time slowing down).


This assumptiuon of SR is incomplete. In the real universe all objects

are

in a state of absolute motion. Therefore the observer's clock can run

fast

or slow compared to the observed clock. Why? Because the rate of passage

of

clock second in each clock is dependent on the state of absolute motion

of

the clock. The higher is the state of absolute motion the slower is the

rate

of passage of clock seconds. This mean that a clock second in a faster
moving clock will contain a larger amount of absolute time than a clock
second in a slower moving clock. This is the true reason for the SR

concept

of time dilation.


Because you are assuming its the aether that does them when SR can
give a more elegant explanation but in the end experimental data will
prevail.

Fundamentally SR is also an aether theory. Why? Because an SR observer
assumes that he is in a state of rest and all the observed objects are doing
the moving. This SR assumption allows the SR observer to conclude that all
the clocks moving wrt him are running slower than his clock and all the rods
moving wrt him are contracted.
It turns out that this SR assumption is correct if the observed object is in
a higher state of absolute motion than the observer. That's why SR is valid
for use in accelerator design applications. However SR is not valid for
applications where the observed object has a lower state of absolute motion
than the observer. This is proven by the GPS clocks. The GPS clock is
running at a faster rate than the ground clock.




Now if he uses an atomic clock in his thought
experiment 20 years ago he may not have the
problem. His aether explanation is ingenious
though like LET.. ad hoc but modern experiments
have proven him long as time dilation really have
physical effect in that after comparison later,
there is time difference in the physical state of
the objects such as muon living longer, etc.


The correct explanation for muon time dilation is as follows:
The decaying process for a subatomic particle such as a muon is

different

from that for a neutron. It was found that a muon at a speed closed to

that

of light would have a much longer decay length than that of a muon at

the

rest frame of the laboratory. When these decay lengths are converted to
decay times they agree with the SRT time dilation equation. This led
physicists to claim that the muon decaying process is a proof of the

time

dilation concept of SRT. The Model Mechanical explanation of the muon

decay

process is as follows:


How about electrons being swirled in particle accelerators. Their
lifetime is
also increased.

?????? The electron has an infinite life time to begin with. So how can its
life time is increased?



1. The orbit of the muon's S-Particle is unstable and it will decay into

a

stable orbit of the electron.


Gee. You are serious about the S-Particle are you. The first few pages
of your paper is the worse. How can the E-Matrix maintain the constant
orbital of the S-Particles around the E-Strings??

The E-Strings are repulsive to each other and the S-Particles are repulsive
to the surrounding E-Strings. Therefore any orbiting motion of an S-Particle
around an E-String is maintained.

Also you talk about
clockwise and counterclockwise helical spin of the S-Particles around
the E-Strings. But how do you tell what is clockwise and
counterclockwise
then there is nothing to compare it too.

The S-Particle is in a helical orbiting motion around and E-String. Left
handed helical orbiting motion of an S-Patricle is an electron. Right handed
helical orbiting motion of an S-Particle is a positron. I know that you are
going to say that looking from the mirror the electron becomes a positron
and the positron becomes an electron. But that's OK because the relationship
between the electron and positron is maintained.



2. In the rest frame of the Lab a muon decays in 2.2 microseconds.

However,

a muon moving with respect to the Lab will have a longer decay time of
(2.2*10^-6)(F_aa/F_ab)seconds.
3. Therefore from the Lab point of view the decay length for a traveling
muon is:
v(2.2*10^-6)(F_aa/F_ab) meters
Where v is the relative velocity between the Lab and the traveling muon.
This Model Mechanical prediction for the decay length of a traveling

muon

agrees with experimental observations.



To Jim Black. The reason I wanted to discuss with Seto is because
somehow I wished he was right.

I am right. Jim Black is a runt of the SRians.
Ken Seto
.
User: "Kowstue"

Title: Re: Seto Light Clock Fallacy & False Assumptions 10 Jun 2007 08:59:26 AM
On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


---------------------------------
My comments (Kows):


In our relativistic universe, the light beam would
get up and reflected down in any inertial frame. Now
what Seto is thinking is that since his light travel
in his aether. When the light beam goes up, it
won't hit the celing mirror in the first few pulses
because the aether is fixed and the light clock is
moving and so the light won't hit the mirror, gets?


That's right the first few pulses won't hit the ceiling mirror. If

that's

not the case, the leading edge of the light ray (the first photon) will

hit

the target. That would mean that you would know the velocity and the
position of the first photon simultaneously.....that is a violation of

the

Uncertainty Principle.


Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the way.


To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the Uncertainty
Principle
because the photon in an electromagnetic wave doesn't have definite
position but probabilistic.


No if the first photon hit the mirror it would mean that you will know the
position and velocity of the first photon and that certainly is a violation
of the Uncertainty Principle.

After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies. Also
you are assuming photons move like bullet in the
electromagnetic when photons only manifest after
measurements. Also there's a certain range of width
where it can appear in a probabilistic manner.


Also if your argument is right that the
aether
is fixed and the light would be left behind. There is possibility
that no pulse would hit the mirror at all because all the
light would be left behind.


No.....the speed of light being transmitted by the E-Matrix is much faster
than the moving light clock. Therefore the photons generated at a later time
will be able to hit the top mirror. If the speed of the light clock is at
the speed of light then no photon will be able to hit the top mirror. SR
interprets this situation as that time stands still at the speed of light.
IRT interprets this situation as that absolute time keep on passing at the
same rate but a clock second for a c moving light clock contains an infinite
amount of absolute time.

In other words. You believe in Absolute time. However experimental
results prevail above anything. If their lifetime is really increased,
then there is a physical difference. You are assuming that
after the twin returns from near lightspeed travel, only the
clock will differ and not the age of the twins. But experimental
labs can simulate such situations in other ways and they
say the twin indeed age.. something like that.


Except that the light beam will have to know which of the infinite

diagonal

paths to follow. Such bogus assumption is beyond logic.
Also relative motion between two object is related to their absolute

motions

as follows:
Relative velocity between A and B is the vector different of the vector
component of A's absolute motion and the vector component of B's

absolute

motion along the line joining A and B.


Assume the light beam is a laser, since it doesn't need aether to move
and independent of any reference frame, it can go straight. No need
to ask how the light beam will have to know which of the infinite
diagonal paths to follow. You are assuming aether dynamics when
relativistic setup would explain it.


This is not true....how can it go striaght perpendicular path if it has to
follow a slant path on its way to the top mirror?. If the light beam is a
laser the leading edge of this laser is the first photon. If the first
photon hits your target that would mean that the velocity and the position
of the first photon is known simultaneously. That is a violation of the UP.

If it's a laser, it doesn't have to follow slant path. Inside train,
you can toss ball up and it will fall straight because the
source has the same velocity as you. In the case of the
light clock. The source moves the same speed and
remember photons have momentum too.


Because you are assuming its the aether that does them when SR can
give a more elegant explanation but in the end experimental data will
prevail.


Fundamentally SR is also an aether theory. Why? Because an SR observer
assumes that he is in a state of rest and all the observed objects are doing
the moving. This SR assumption allows the SR observer to conclude that all
the clocks moving wrt him are running slower than his clock and all the rods
moving wrt him are contracted.

Actually you can apply SR to two moving frames. It is not an aether
theory because there is no absolute rest frame. Everything is
relative. GR includes accelerated motion.

It turns out that this SR assumption is correct if the observed object is in
a higher state of absolute motion than the observer. That's why SR is valid
for use in accelerator design applications. However SR is not valid for
applications where the observed object has a lower state of absolute motion
than the observer. This is proven by the GPS clocks. The GPS clock is
running at a faster rate than the ground clock.

Because the GPS clock is moving so its real time is slower
compared to ours in real time.
Corresponding with you will make me review so much of
SR and even GR. Hope you can be unbias. I'm only
moved by experimental evidence.
Kows
.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 11 Jun 2007 10:04:46 AM
"Kowstue" <kowstue@yahoo.com> wrote in message
news:1181483966.537451.277390@x35g2000prf.googlegroups.com...

On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:



Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the way.


To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the Uncertainty
Principle
because the photon in an electromagnetic wave doesn't have definite
position but probabilistic.


No if the first photon hit the mirror it would mean that you will know

the

position and velocity of the first photon and that certainly is a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.

HUP doesn't apply when the detector detects a photon. However, HUP will
apply when SR asserts that a specific photon (the first photon of a light
ray) hits the detector. This would mean that the velocity and the position
of the first photon are known simultaneously and that is a violation of the
HUP.

Also
you are assuming photons move like bullet in the
electromagnetic when photons only manifest after
measurements. Also there's a certain range of width
where it can appear in a probabilistic manner.

I didn't assume anything. I just point out that the SR assertion that the
first photon of a light ray will hit the detector is a violation of the HUP.



Also if your argument is right that the
aether
is fixed and the light would be left behind. There is possibility
that no pulse would hit the mirror at all because all the
light would be left behind.


No.....the speed of light being transmitted by the E-Matrix is much

faster

than the moving light clock. Therefore the photons generated at a later

time

will be able to hit the top mirror. If the speed of the light clock is

at

the speed of light then no photon will be able to hit the top mirror. SR
interprets this situation as that time stands still at the speed of

light.

IRT interprets this situation as that absolute time keep on passing at

the

same rate but a clock second for a c moving light clock contains an

infinite

amount of absolute time.


In other words. You believe in Absolute time.

Yes the existence of absolute time is the reason why a clock second will
measure the same speed of light in all frame as follows:
Light path length of ruler (299,792,458 m long physically)/the absolute time
content for a clcok second co-moving with the ruler.

However experimental
results prevail above anything. If their lifetime is really increased,
then there is a physical difference. You are assuming that
after the twin returns from near lightspeed travel, only the
clock will differ and not the age of the twins. But experimental
labs can simulate such situations in other ways and they
say the twin indeed age.. something like that.

Yes in the twin scenario the traveling clock will show less elapsed clock
time. However you can't compare the traveling clock second directly with the
stay at home clock second. In order to make the proper comparison you must
convert the traveling clock seconds into the stay at home clock second using
the conversion factor of gamma. IOW a travel clock second is worth: (gamma*1
stay at home clock second). When this is done both twin will age the same
amount according to the stay at home clock.


Assume the light beam is a laser, since it doesn't need aether to move
and independent of any reference frame, it can go straight. No need
to ask how the light beam will have to know which of the infinite
diagonal paths to follow. You are assuming aether dynamics when
relativistic setup would explain it.


This is not true....how can it go striaght perpendicular path if it has

to

follow a slant path on its way to the top mirror?. If the light beam is

a

laser the leading edge of this laser is the first photon. If the first
photon hits your target that would mean that the velocity and the

position

of the first photon is known simultaneously. That is a violation of the

UP.


If it's a laser, it doesn't have to follow slant path. Inside train,
you can toss ball up and it will fall straight because the
source has the same velocity as you. In the case of the
light clock. The source moves the same speed and
remember photons have momentum too.

Here you are assuming that inside the train is in a state of absolute rest
(not moving wrt light). In real life all objects are in a state of absolute
motion wrt light. Therefore even in the train the target on the roof of the
train will move during the transit of light. This will cause the initial
batch of photons miss the target. That's why a moving clock will take longer
absolute time to complete a cycle.



Because you are assuming its the aether that does them when SR can
give a more elegant explanation but in the end experimental data will
prevail.


Fundamentally SR is also an aether theory. Why? Because an SR observer
assumes that he is in a state of rest and all the observed objects are

doing

the moving. This SR assumption allows the SR observer to conclude that

all

the clocks moving wrt him are running slower than his clock and all the

rods

moving wrt him are contracted.


Actually you can apply SR to two moving frames. It is not an aether
theory because there is no absolute rest frame. Everything is
relative. GR includes accelerated motion.

An SR observer assumes that he is in a state of absolute rest and that all
the objects moving wrt him are doing the moving. That's why an SR observer
asserts that his clock is the fastest running clock in the universe.


It turns out that this SR assumption is correct if the observed object

is in

a higher state of absolute motion than the observer. That's why SR is

valid

for use in accelerator design applications. However SR is not valid for
applications where the observed object has a lower state of absolute

motion

than the observer. This is proven by the GPS clocks. The GPS clock is
running at a faster rate than the ground clock.


Because the GPS clock is moving so its real time is slower
compared to ours in real time.

So what about from the GPS clock point of view? Are you saying that the
ground clock is moving so its real time is slower compared to the GPS real
time? Such assertion would disagree with observation.


Corresponding with you will make me review so much of
SR and even GR. Hope you can be unbias. I'm only
moved by experimental evidence.

The best experimental evidence would be to do the proposed experiments in
the following link. These experiments are capable of refuting IRT.
http://www.geocities.com/kn_seto/2007IRT.pdf
Ken Seto
.
User: "Randy Poe"

Title: Re: Seto Light Clock Fallacy & False Assumptions 11 Jun 2007 11:58:28 AM
On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message

news:1181483966.537451.277390@x35g2000prf.googlegroups.com...



On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the way.


To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the Uncertainty
Principle
because the photon in an electromagnetic wave doesn't have definite
position but probabilistic.


No if the first photon hit the mirror it would mean that you will know

the

position and velocity of the first photon and that certainly is a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However, HUP will
apply when SR asserts that a specific photon (the first photon of a light
ray) hits the detector. This would mean that the velocity and the position
of the first photon are known simultaneously and that is a violation of the
HUP.

Are you still spouting this nonsense? Can you even state
the HUP?
It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.
- Randy
.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 11 Jun 2007 01:31:56 PM
"Randy Poe" <poespam-trap@yahoo.com> wrote in message
news:1181581108.384106.149720@c77g2000hse.googlegroups.com...

On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message

news:1181483966.537451.277390@x35g2000prf.googlegroups.com...



On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the

way.


To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you will

know

the

position and velocity of the first photon and that certainly is a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However, HUP will
apply when SR asserts that a specific photon (the first photon of a

light

ray) hits the detector. This would mean that the velocity and the

position

of the first photon are known simultaneously and that is a violation of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?

It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.

Idiot runt....I suggest that you look up the definition for the HUP.
.
User: "Eric Gisse"

Title: Re: Seto Light Clock Fallacy & False Assumptions 11 Jun 2007 05:07:11 PM
On Jun 11, 10:31 am, "kenseto" <kens...@woh.rr.com> wrote:
[...]


Idiot runt....I suggest that you look up the definition for the HUP.

The HUP isn't a definition, it is derived from the generalized
uncertainty principle between two operators.
Is your understanding of QM limited to what you read in Wikipedia?
.

User: "Randy Poe"

Title: Re: Seto Light Clock Fallacy & False Assumptions 11 Jun 2007 01:37:18 PM
On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181581108.384106.149720@c77g2000hse.googlegroups.com...



On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because instantaneous
link disturbs me as I think I can pull a Greysky stunt. But let's
deal with pure reasons and not let emotional bias comes in the

way.

To your pulses and mirror thing. Well. Even if the photon hits the
ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you will

know

the

position and velocity of the first photon and that certainly is a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However, HUP will
apply when SR asserts that a specific photon (the first photon of a

light

ray) hits the detector. This would mean that the velocity and the

position

of the first photon are known simultaneously and that is a violation of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.


Idiot runt....I suggest that you look up the definition for the HUP.

You mean this?
(delta-x)*(delta-p) >= hbar/2
where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?
There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.
Now, what's your version?
More to the point, you have already been told many times about
devices which make simultaneously single-particle position and
momentum measurements. Those devices according to you
can't exist. Yet they do.
- Randy
.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 12 Jun 2007 09:34:38 AM
"Randy Poe" <poespam-trap@yahoo.com> wrote in message
news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...

On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181581108.384106.149720@c77g2000hse.googlegroups.com...



On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky stunt. But

let's

deal with pure reasons and not let emotional bias comes in the

way.

To your pulses and mirror thing. Well. Even if the photon hits

the

ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you

will

know

the

position and velocity of the first photon and that certainly is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However, HUP

will

apply when SR asserts that a specific photon (the first photon of a

light

ray) hits the detector. This would mean that the velocity and the

position

of the first photon are known simultaneously and that is a violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.


Idiot runt....I suggest that you look up the definition for the HUP.


You mean this?
(delta-x)*(delta-p) >= hbar/2

where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?

Right.....the more accurately you determine the position of a specific
photon the less certain you are able to determine it velocity (momentum)
simultaneously.


There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.

It is a violation of the HUP if you claim that the position and the velocity
of a specific photon can be determine accurately simultaneously.
.
User: "Randy Poe"

Title: Re: Seto Light Clock Fallacy & False Assumptions 12 Jun 2007 09:32:05 AM
On Jun 12, 10:34 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...



On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181581108.384106.149720@c77g2000hse.googlegroups.com...


On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky stunt. But

let's

deal with pure reasons and not let emotional bias comes in the

way.


To your pulses and mirror thing. Well. Even if the photon hits

the

ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you

will

know

the

position and velocity of the first photon and that certainly is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector of
say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However, HUP

will

apply when SR asserts that a specific photon (the first photon of a

light

ray) hits the detector. This would mean that the velocity and the

position

of the first photon are known simultaneously and that is a violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.


Idiot runt....I suggest that you look up the definition for the HUP.


You mean this?
(delta-x)*(delta-p) >= hbar/2


where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?


Right.....the more accurately you determine the position of a specific
photon the less certain you are able to determine it velocity (momentum)
simultaneously.



There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.


It is a violation of the HUP if you claim that the position and the velocity
of a specific photon can be determine accurately simultaneously.

They can be determined with accuracy delta-x and delta-p
which are related according to the HUP. Since hbar/2 is a
very small number, then delta-x and delta-p can be small,
i.e. x and p can be determined accurately simultaneously.
- Randy
.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 13 Jun 2007 08:53:56 AM
"Randy Poe" <poespam-trap@yahoo.com> wrote in message
news:1181658725.965414.213310@i38g2000prf.googlegroups.com...

On Jun 12, 10:34 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...



On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181581108.384106.149720@c77g2000hse.googlegroups.com...


On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky stunt.

But

let's

deal with pure reasons and not let emotional bias comes in

the

way.


To your pulses and mirror thing. Well. Even if the photon

hits

the

ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you

will

know

the

position and velocity of the first photon and that certainly

is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector

of

say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However,

HUP

will

apply when SR asserts that a specific photon (the first photon

of a

light

ray) hits the detector. This would mean that the velocity and

the

position

of the first photon are known simultaneously and that is a

violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.


Idiot runt....I suggest that you look up the definition for the HUP.


You mean this?
(delta-x)*(delta-p) >= hbar/2


where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?


Right.....the more accurately you determine the position of a specific
photon the less certain you are able to determine it velocity (momentum)
simultaneously.



There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.


It is a violation of the HUP if you claim that the position and the

velocity

of a specific photon can be determine accurately simultaneously.


They can be determined with accuracy delta-x and delta-p
which are related according to the HUP. Since hbar/2 is a
very small number, then delta-x and delta-p can be small,
i.e. x and p can be determined accurately simultaneously.

Not for a specific photon identified as *AAA*. For that matter how do you
tag a specific photon identified as *AAA*??? IOW how do the emitter produce
only ONE photon.
.
User: "Randy Poe"

Title: Re: Seto Light Clock Fallacy & False Assumptions 13 Jun 2007 09:09:12 AM
On Jun 13, 9:53 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181658725.965414.213310@i38g2000prf.googlegroups.com...



On Jun 12, 10:34 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...


On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181581108.384106.149720@c77g2000hse.googlegroups.com...


On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky stunt.

But

let's

deal with pure reasons and not let emotional bias comes in

the

way.


To your pulses and mirror thing. Well. Even if the photon

hits

the

ceiling mirror on the first pulse, it won't violate the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that you

will

know

the

position and velocity of the first photon and that certainly

is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the detector

of

say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon. However,

HUP

will

apply when SR asserts that a specific photon (the first photon

of a

light

ray) hits the detector. This would mean that the velocity and

the

position

of the first photon are known simultaneously and that is a

violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure position
and velocity.


Idiot runt....I suggest that you look up the definition for the HUP.


You mean this?
(delta-x)*(delta-p) >= hbar/2


where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?


Right.....the more accurately you determine the position of a specific
photon the less certain you are able to determine it velocity (momentum)
simultaneously.


There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.


It is a violation of the HUP if you claim that the position and the

velocity

of a specific photon can be determine accurately simultaneously.


They can be determined with accuracy delta-x and delta-p
which are related according to the HUP. Since hbar/2 is a
very small number, then delta-x and delta-p can be small,
i.e. x and p can be determined accurately simultaneously.


Not for a specific photon identified as *AAA*.

Yes, for a single photon. The position is determined with
uncertainty delta-x. The momentum is simultaneously
detected with uncertainty delta-p. The HUP requires that
the product of those two numbers be greater than hbar/2,
which is not a very stringent requirement.

For that matter how do you
tag a specific photon identified as *AAA*???

You know when you have a single-photon detection in
your detector. It's done all the time.

IOW how do the emitter produce
only ONE photon.

Depends on the emitter. If it's some sort of particle
interaction, you know how many photons are emitted
and which way they went. If you're talking about a light
source, then you use a very low intensity, spread it
over a wide area, and use short pulses. Usually with that
sort of setup you'll get a combination of single-photon
pulses and pulses with two-or-more, but you can tell
the difference.
Read any paper on single-photon experiments for more
info. The keywords "single photon" should turn up plenty.
For instance:
http://www.iet.ntnu.no/groups/optics/qcr/torbjoern/
http://en.wikipedia.org/wiki/Single_photon_emission_computed_tomography
Toshiba says they have an LED which emits single photons:
http://www.toshiba-europe.com/research/crl/qig/singlephotonled.html
- Randy
.
User: "kenseto"

Title: Re: Seto Light Clock Fallacy & False Assumptions 14 Jun 2007 08:41:24 AM
"Randy Poe" <poespam-trap@yahoo.com> wrote in message
news:1181743752.103240.212820@o11g2000prd.googlegroups.com...

On Jun 13, 9:53 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181658725.965414.213310@i38g2000prf.googlegroups.com...



On Jun 12, 10:34 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...


On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181581108.384106.149720@c77g2000hse.googlegroups.com...


On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky

stunt.

But

let's

deal with pure reasons and not let emotional bias

comes in

the

way.


To your pulses and mirror thing. Well. Even if the

photon

hits

the

ceiling mirror on the first pulse, it won't violate

the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't

have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that

you

will

know

the

position and velocity of the first photon and that

certainly

is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the

detector

of

say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon.

However,

HUP

will

apply when SR asserts that a specific photon (the first

photon

of a

light

ray) hits the detector. This would mean that the velocity

and

the

position

of the first photon are known simultaneously and that is a

violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure

position

and velocity.


Idiot runt....I suggest that you look up the definition for the

HUP.


You mean this?
(delta-x)*(delta-p) >= hbar/2


where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?


Right.....the more accurately you determine the position of a

specific

photon the less certain you are able to determine it velocity

(momentum)

simultaneously.


There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.


It is a violation of the HUP if you claim that the position and the

velocity

of a specific photon can be determine accurately simultaneously.


They can be determined with accuracy delta-x and delta-p
which are related according to the HUP. Since hbar/2 is a
very small number, then delta-x and delta-p can be small,
i.e. x and p can be determined accurately simultaneously.


Not for a specific photon identified as *AAA*.


Yes, for a single photon. The position is determined with
uncertainty delta-x. The momentum is simultaneously
detected with uncertainty delta-p. The HUP requires that
the product of those two numbers be greater than hbar/2,
which is not a very stringent requirement.

The uncertainty increases considerably with increasing distance. If the
detector is close to the source then the uncertainty is negligible. The
reason is that the effect of absolute motion of the detector wrt the photon
is small for a short distance. What you say is true in a lab scale. But what
SR claim is that the first photon of a light ray will be able to hit the
detector at a large distance. Such claim does violate the HUP.


For that matter how do you
tag a specific photon identified as *AAA*???


You know when you have a single-photon detection in
your detector. It's done all the time.

IOW how do the emitter produce
only ONE photon.


Depends on the emitter. If it's some sort of particle
interaction, you know how many photons are emitted
and which way they went. If you're talking about a light
source, then you use a very low intensity, spread it
over a wide area, and use short pulses.

So you are not talking about detecting the position and velocity of any
specfic photon identified as *AAA* and you are talking about detecting a
photon in the confine of the Lab. That's the reason why you claim that you
can detect the position and momentum (velocity) of a photon simultaneously.
I can agree to that.
.
User: "Randy Poe"

Title: Re: Seto Light Clock Fallacy & False Assumptions 14 Jun 2007 09:11:33 AM
On Jun 14, 9:41 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message

news:1181743752.103240.212820@o11g2000prd.googlegroups.com...



On Jun 13, 9:53 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181658725.965414.213310@i38g2000prf.googlegroups.com...


On Jun 12, 10:34 am, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181587038.321761.81690@n4g2000hsb.googlegroups.com...


On Jun 11, 2:31 pm, "kenseto" <kens...@woh.rr.com> wrote:

"Randy Poe" <poespam-t...@yahoo.com> wrote in message


news:1181581108.384106.149720@c77g2000hse.googlegroups.com...


On Jun 11, 11:04 am, "kenseto" <kens...@woh.rr.com> wrote:

"Kowstue" <kows...@yahoo.com> wrote in message


news:1181483966.537451.277390@x35g2000prf.googlegroups.com...


On Jun 9, 10:07 pm, "kenseto" <kens...@woh.rr.com> wrote:


Deep within I hoped you were somehow right because

instantaneous

link disturbs me as I think I can pull a Greysky

stunt.

But

let's

deal with pure reasons and not let emotional bias

comes in

the

way.


To your pulses and mirror thing. Well. Even if the

photon

hits

the

ceiling mirror on the first pulse, it won't violate

the

Uncertainty

Principle
because the photon in an electromagnetic wave doesn't

have

definite

position but probabilistic.


No if the first photon hit the mirror it would mean that

you

will

know

the

position and velocity of the first photon and that

certainly

is

a

violation

of the Uncertainty Principle.


After detection like when after there is a hit in the

detector

of

say the double slit experiment. HUP no longer applies.


HUP doesn't apply when the detector detects a photon.

However,

HUP

will

apply when SR asserts that a specific photon (the first

photon

of a

light

ray) hits the detector. This would mean that the velocity

and

the

position

of the first photon are known simultaneously and that is a

violation

of

the

HUP.


Are you still spouting this nonsense? Can you even state
the HUP?


It does not prevent simultaneous measurement of position
and velocity. You have been told this, and have been shown
pretty pictures of devices which simultaneously measure

position

and velocity.


Idiot runt....I suggest that you look up the definition for the

HUP.

You mean this?
(delta-x)*(delta-p) >= hbar/2


where delta-x and delta-p are the uncertainties on simultaneous
measurements of position and momentum?


Right.....the more accurately you determine the position of a

specific

photon the less certain you are able to determine it velocity

(momentum)

simultaneously.


There is a numerical relation between these simultaneous
measurements, not a statement that the measurements can't
be made simultaneously.


It is a violation of the HUP if you claim that the position and the

velocity

of a specific photon can be determine accurately simultaneously.


They can be determined with accuracy delta-x and delta-p
which are related according to the HUP. Since hbar/2 is a
very small number, then delta-x and delta-p can be small,
i.e. x and p can be determined accurately simultaneously.


Not for a specific photon identified as *AAA*.


Yes, for a single photon. The position is determined with
uncertainty delta-x. The momentum is simultaneously
detected with uncertainty delta-p. The HUP requires that
the product of those two numbers be greater than hbar/2,
which is not a very stringent requirement.


The uncertainty increases considerably with increasing distance. If the
detector is close to the source then the uncertainty is negligible. The
reason is that the effect of absolute motion of the detector wrt the photon
is small for a short distance. What you say is true in a lab scale. But what
SR claim is that the first photon of a light ray will be able to hit the
detector at a large distance. Such claim does violate the HUP.



For that matter how do you
tag a specific photon identified as *AAA*???


You know when you have a single-photon detection in
your detector. It's done all the time.


IOW how do the emitter produce
only ONE photon.


Depends on the emitter. If it's some sort of particle
interaction, you know how many photons are emitted
and which way they went. If you're talking about a light
source, then you use a very low intensity, spread it
over a wide area, and use short pulses.


So you are not talking about detecting the position and velocity of any
specfic photon identified as *AAA* and you are talking about detecting a
photon in the confine of the Lab.

The specific photon is identified as "the one that hits".
If I point a detector at the moon (such as is done in laser
ranging experiments) then the photon is not "in the confines
of the lab" and when the photon impacts my detector, I
know its position and its momentum, within bounds.

That's the reason why you claim that you
can detect the position and momentum (velocity) of a photon simultaneously.
I can agree to that.

How about photons from the moon?
- Randy
.