Is HUP inapplicable to photons? Emit the photon and
detect it, the photon only travels at c so the straight
line from the emitter -=-

-=- to the detection indicates its momentum, and the
detection indicates its position.

Since you asked about three dozen questions and presented
about two dozen half-baked ideas, I'll address one to start.

Yes, the HUP applies to photons. Note the HUP doesn't restrict
whether a measurement can be made at all, but the inherent
*precision* of the measurement (governed by physics and not by
instrumentation).

Thus you can measure the momentum and position of a photon but
not both with arbitrarily high precision.

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PD

I'm just happy I got somebody rational to reply.

About that, it seems that because light speed is strictly c, that if
the observers at emitter and collector both know the synchronized time
of the photon emission, that its position and momentum is readily
determined, because, it's the only particle that could have done that,
reached the collector, and, it did.

Indeed, the procedure for synchronizing clocks is classical and works
only in the realm where quantum effects are small. We know that
already. This, however, does not mean that spacetime and manifest
covariance of physical laws does not pertain to quantum mechanics.

PD

Hi,

I don't really understand that.

You're basically saying that although E and D synchronize their
watches, to establish a "point" reference frame, and then move
symmetrically from that point, i.e. each in equal and opposite
distances, in deep space as necessary, that they do not then share a
reference frame.

What do you think about the reasoning that the Heisenberg Uncertainty
Principle is not applying to these photons, massless particles, and
others are describing massy lepton confinement over time?

I guess I'm asking if you could further explain what you mean by that.

Thanks,

I guess the photon is supposed to be taking all possible paths, i.e.
its path is Feynman's path integral.

Yet, the shortest distance from point to point is a straight line. In
time t, at its maximum and constant velocity c as measured by all
observers in the reference frame, the unimpeded photon travels exactly
t * c meters.

So the detector, if the photon travels all paths until its wave
function collapses on detection, will not see a point photon but
starting at time t the photon in the shortest line and also the same
photon that travelled a fractal space-filling path that would take it
years to cross thirty meters, so the detector is stuck in time forever?
That doesn't seem very plausible.

For the travel distance to be some average of the paths, or the path
integral, then the photon on the actual straight line would be going
both forward and variously backward in time. Now, as it goes backwards
in time, it follows its same track, so to be not advanced, at some
point it would go back in time faster than it went forward, yet back
faster again, to not violate c it violates causality.

It just seems that some classical explanations do override the quantum
in simple experiments.

Then as a layman I'm trying to figure out some intuitive reasons to
explain in the particle-wave duality such things as the dual slit
experiment, or four or eight or all of them leading to the path
integral. The explanations are not so counterintuitive within their
framework, but via exhaustion there just seem too many implausible
implications that can never be verified.

That's probably just a regular skeptic talking, QED, Quantum
Electrodynamics or the explanation of quantum mechanics, is said to be
very successful and that it verifies all its experiments. That is very
key and I respect that, but by the same token it still involves
renormalization, and quantization is denormalization.

Also, there is this consideration of discussion that HUP doesn't apply
to photons, or more broadly HUP doesn't apply in general, and that
changes a lot of the assumptions behind the theory.

Ross