structure constants depend on the basis chosen?



 Science > Physics > structure constants depend on the basis chosen?

LINK TO THIS PAGE  


rating :  0   |  0


  Page 1 of 1

1

 
Topic: Science > Physics
User: "Barrow"
Date: 21 Mar 2007 08:03:58 AM
Object: structure constants depend on the basis chosen?
Dear all,
The structure constant of a Lie group should be independent of
representations.
But in the book "Lie algebras in particles physics", it says: "The
structure constants depend on what basis we choose in the vector space
of the generators"
There seems to be some conflict?
A representation means that we realize the multiplication table of an
abstract group on a certain vector space. So, an abstract group
element becomes the transformation(or operator) on vectors in the
vector space. Thus, if the structure constants are independent of the
representations, it should be independent of the basis we choose in
the vector space of the generators, right?
Is my concept wrong? Thanks for any help, I'm really confused with the
problem. thanks!
Sincerely Barrow
.

User: "galathaea"

Title: Re: structure constants depend on the basis chosen? 21 Mar 2007 10:12:37 AM
On Mar 21, 6:03 am, "Barrow" <GRsemi...@gmail.com> wrote:

Dear all,
The structure constant of a Lie group should be independent of
representations.

But in the book "Lie algebras in particles physics", it says: "The
structure constants depend on what basis we choose in the vector space
of the generators"

There seems to be some conflict?

A representation means that we realize the multiplication table of an
abstract group on a certain vector space. So, an abstract group
element becomes the transformation(or operator) on vectors in the
vector space. Thus, if the structure constants are independent of the
representations, it should be independent of the basis we choose in
the vector space of the generators, right?

but they are not independent
the quote you give
states clearly there is a dependence
you have a lot of options in choosing a basis
any particular choice
will give a new set of structure constants
because the basis vectors will be different
that doesn't mean the multiplication will give new results
it simply means that the elements will have new representations
there is
however
an almost canonical basis
for finite dimensional semisimple lie algebras
the "cartan-weyl" basis
( modulo some normalisation and an arbitrary choice )
which gives a canonical set of structure constants
such work does not apply to solvable algebras
for instance
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
galathaea: prankster, fablist, magician, liar
.


  Page 1 of 1

1

 


Related Articles
Variable Constants?
C1 & C2 radiation constants.
Avogrado constants and others
Quantum Gravity 209.0: How Phase Constants Generalize Dirac DeltaFunctions, Kronecker deltas, Levi-Civita (tensor) symbols, etc.
Permittivity and Permeability Constants of Vacuum
Alternate Fundamental Constants
The three fundamental Variables and two fundamental Constants of mechanics
Time and the constant (was Re: Constants)
LeSagian Gravitational Field Momentum Flux linked to EM/QM constants
Independent/Dependent Phases 7: Dyt vs Dtt Make Most "Universal Constants" Implausible
Fine Structure Constants(plural)
Re: fundamental physical constants
Re: Setting constants like hbar to unity
Quantum Gravity Via Expansion-Contraction 4.0: Genus, Eigenvalues, and Other Piecewise Constants Satisfy Riccati Differential equation
Where are the constants?
 

NEWER

pg.1612     pg.1232     pg.940     pg.716     pg.544     pg.412     pg.311     pg.234     pg.175     pg.130     pg.96     pg.70     pg.50     pg.35     pg.24     pg.16     pg.10     pg.6     pg.3     pg.1

OLDER