Science > Physics > The Complete Disproof of Relativity and current Quantum Mechanics
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Science > Physics |
| User: |
"Jeff" |
| Date: |
27 Jan 2005 03:14:18 PM |
| Object: |
The Complete Disproof of Relativity and current Quantum Mechanics |
www.realityphysics.com <
All comments and opinions welcome.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Dr. Photon" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
28 Jan 2005 03:30:15 AM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message news:<1106860458.866965.50380@c13g2000cwb.googlegroups.com>...
All comments and opinions welcome.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
What's the point starting another thread when you only just started the last one?
Maybe you don't welcome the "comments and opinions" on the other one???
I notice you didn't reply to my one, so I'll post it again.
On your web site you have:
"We begin by dividing the known energy of the [N1] orbit of the Bohr
Hydrogen atom: 13.6ev by ..."
and
"we divide the known energy of the [N2] orbit: 3.4ev by ..."
In other words, you plug experimentally measured values into your model,
and find that the difference gives you the experimentally measured difference.
The steps inbetween are irrelevant.
BR.
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
28 Jan 2005 03:03:07 PM |
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Dr. Photon wrote:
"Jeff" <JLeeCforRP@aol.com> wrote in message
news:<1106860458.866965.50380@c13g2000cwb.googlegroups.com>...
All comments and opinions welcome.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
What's the point starting another thread when you only just started
the last one?
Maybe you don't welcome the "comments and opinions" on the other
one???
I notice you didn't reply to my one, so I'll post it again.
On your web site you have:
"We begin by dividing the known energy of the [N1] orbit of the Bohr
Hydrogen atom: 13.6ev by ..."
and
"we divide the known energy of the [N2] orbit: 3.4ev by ..."
In other words, you plug experimentally measured values into your
model,
and find that the difference gives you the experimentally measured
difference.
The steps inbetween are irrelevant.
BR.
Because the "mass DECREASE" of Reality Physics, NOT the "mass INCREASE"
of Relativity, is what allows you to do this and to reveal the
CORRECTED de Broglie Equation where: wavelength(B)= h / (mass
decrease[of Reality Physics]) x "Photon Spin Velocity within electron"
[also Reality Physics - not current QM]. So please tell us, Dr Photon,
How do you calculate the observed wavelengths of the Atom using the de
Broglie Equation as currently described by Quantum Mechanics?
What this shows is that, for the first time in the history of Quantum
Mechanics we are now able to calculate the CORRECT value for the
wavelengths of the Atom, something QM has been trying to do for over
seventy or eighty years now.
This also further proves that Realtiy Physics completely agrees with
observed physical reality, whereas current Theoretical Physics
(Relativity and QM) do not!
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Franz Heymann" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
01 Feb 2005 12:46:13 AM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message
news:1106946187.921109.197470@f14g2000cwb.googlegroups.com...
[snip]
What this shows is that, for the first time in the history of
Quantum
Mechanics we are now able to calculate the CORRECT value for the
wavelengths of the Atom, something QM has been trying to do for over
seventy or eighty years now.
That's good going.
What is the energy difference between the 2S1/2 and the 2P1/2 levels
of the simplest atom. namely atomic Hydrogen?
Don't give the whole theory, just give the number.
[snip]
Franz
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
01 Feb 2005 01:44:17 PM |
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Jeff wrote:
Franz,
Thanks for your reply. With the Bohr Hydrogen atom, as described by
Reality Physics, the electron orbit pilot waves are concentric and
exactly spherical until they and are "deformed" by the negative field
as generated by the configuration of the arrangement of the near-by
negatively charged electron pilot waves of the other atoms in close
proximety (which act as small spherically shaped antennas). No
sub-orbitals, or Uncertainty Principle, in Reality Physics. By knowing
the position and the strength of the field of the other atoms you can,
according to Reality Physics, calculate the resulting shape of the
"deformed" spherical orbit and its energy configuration.
Thanks again for your reply and all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Franz Heymann" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
01 Feb 2005 05:12:06 PM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message
news:1107287057.664076.301620@f14g2000cwb.googlegroups.com...
Jeff wrote:
[snip]
I hope you don't mind my deleting the nonsense with which you replied
to my very straightforward question.
Just in case you missed it, I repeat it here
What is the energy difference between the 2S1/2 and the 2P1/2 levels
of the simplest atom. namely atomic Hydrogen?
Don't give the whole theory, just give the number.
Please don't try to duck it again.
The reply would consist of just one number followed by the units in
qhich the number is expressed.
Franz
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
02 Feb 2005 08:44:34 PM |
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Franz,
Sorry, but I don't have the time to go the library and look it up right
now, and according to Reality Physics there are no sub-orbitals anyway.
So if what I'm doing is "nonsence" then how come I can use the
mathematics of Reality Physics to CORRECT the de Broglie Equation so as
to exactly correctly calculate, not only the wavelengths of the
electron pilot waves of the Bohr Atom, but also the exact wavelengths
of any photon emitted by an electron as it "jump" orbits, something
that current Quantum Mechanics cannot do.
Which description of reality would you prefer? One that CAN correctly
calculate the observed wavelengths of the Bohr Hydrogen Atom using the
de Broglie Equation (Reality Physics), or one that has been trying for
about a 3/4 of a century now and cannot (current Quantum Mechanics),
and will never will be able to?
Also, since you seem to be the "expert" on QM in this news group, could
you possibly tell me how it is that a photon can instantly travel at
the speed of light, as it is emitted from an electron that is orbiting
the atom's nucleus at a velocity over a hundred times less than the
speed of light?
Thanks in advance (I've always wanted to know the answer to that
question).
Oh, by the way, I think I'll just take a wild guess at the question you
proposed..
energy = 4.372x10^-6 eV, freq. = 1.057 GHZ, wavelength = 28 cm.
Did I pass?
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Franz Heymann" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
03 Feb 2005 01:22:01 AM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message
news:1107398674.735190.117410@z14g2000cwz.googlegroups.com...
Franz,
Sorry, but I don't have the time to go the library and look it up
right
now,
I asked you for the figure obtained by the use of your model.
and according to Reality Physics there are no sub-orbitals anyway.
Whether your model has or has no "sub-orbitals" is of no interest to
me.
The energy difference between the 2S1/2 and the 2P1/2 levels is the
Lamb shift. Its value is predicted by QED. It has been measured.
The measurement agrees to a phenomenal accuracy with the prediction.
Now tell us what your model predicts for this energy difference.
So if what I'm doing is "nonsence" then how come I can use the
mathematics of Reality Physics to CORRECT the de Broglie Equation so
as
to exactly correctly calculate, not only the wavelengths of the
electron pilot waves of the Bohr Atom,
The Bohr atom, in case you don't know it, has been dead since the late
1920's.
but also the exact wavelengths
of any photon emitted by an electron as it "jump" orbits, something
that current Quantum Mechanics cannot do.
QM has produced a prediction for what you call the
"jump" wavelength between the
2S1/2 and the 2P1/2 levels of the Hydrogen atom.
What is your prediction for this?
Which description of reality would you prefer?
QED.
It has produced predictions for the wavelengths of all the major
spectral lines of all the atoms of astrophysical interest, as well as
their relative intendities as functions of temperature.
You cannot do that.
One that CAN correctly
calculate the observed wavelengths of the Bohr Hydrogen Atom using
the
de Broglie Equation (Reality Physics), or one that has been trying
for
about a 3/4 of a century now and cannot (current Quantum Mechanics),
and will never will be able to?
You are totally out of date.
Also, since you seem to be the "expert" on QM in this news group,
I am not, and I have never claimed that.
I just know much more about QM than you appear to do.
could
you possibly tell me how it is that a photon can instantly travel at
the speed of light, as it is emitted from an electron that is
orbiting
the atom's nucleus at a velocity over a hundred times less than the
speed of light?
QM says that a photon always travels with the speed of light because
it has no mass
Thanks in advance (I've always wanted to know the answer to that
question).
Oh, by the way, I think I'll just take a wild guess at the question
you
proposed..
energy = 4.372x10^-6 eV, freq. = 1.057 GHZ, wavelength = 28 cm.
Did I pass?
No. That was not a wild guess. I asked for the result of a
calculation using your model. You looked it up in an encyclopaedia.
You yourself said that your model does not recognise the existence of
this level shift.
You are not a very successful bluffer.
Franz
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
03 Feb 2005 08:41:58 PM |
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Franz wrote:
"You are totally out of date"
Jeff, reply:
FACT: I can, using Reality Physics (as I show on my website) calculate
the exact wavelengths of the Bohr Hydrogen atom using the de Broglie
Equation. Now, since you are so "up to date", let's see you do it with
the de Broglie Equation as it is presently understood current QM.
You say the Bohr Hydrogen Atom is "out of date" as understood by
current QM. Of course it is, since QM can't find a way to use the de
Broglie Equation to describe it, they scapped it. Well, I just brought
it back, and in doing so, completely killed QM. But forget the Bohr
atom. How do you explain the fact (as also shown on my website) that I
can also exactly calculate the wavelength of a photon emitted from an
electron as it jumps orbits using the de Broglie Equation of Reality
Physics. The frequency and wavelength of these photons eminating from
the atom can be measured very precisely by observational experiment,
and have nothing at all to do with the Bohr atom. So Bohr atom, or not,
I have corrected the de Broglie Equation to exactly calculate the
values of these photons as observed from experiment, and it works for
every electron jump in the atom. You can try it yourself if you don't
believe me and you will see I am right.
Now to the question as to: Why a photon, eminating from an orbiting
electron traveling at a velocity more than a hunderd times less than
the speed of light, can instantly travel at the speed of light?
The answer: "that the photon has no mass" is correct for your level of
thinking, and for the rest of those now involved in current QM.
However, using Reality Physics I will now give you the REAL reason: The
photon leaves the atom at "c" because the electron it was emitted from
is composed of "spinning light" to begin with, i.e., "the angular
momentum of photon spin". As the electron jumps energy levels it
"throws off" part of its photon spin as a photon, exactly equal to the
difference in energy levels. Since you are still "stuck" in current QM,
I really don't expect you to accept this, but it is easy to prove using
Reality Physics. (I don't have time to do it now but it is in my book.)
***** because I correctly answered you question?
But you are right about one thing, I am not a very successful bluffer.
As a matter of fact, I am not a "bluffer" at all. I am a "Reality
Physicist" with the CORRECT answers.
I find that you, however, since you made the statement that you know
more about QM than I, are possibly one of the best "bluffers" I have
ever seen.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Franz Heymann" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
04 Feb 2005 06:04:34 AM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message
news:1107484918.953011.182340@f14g2000cwb.googlegroups.com...
[snip
You bore me to tears.
Good bye
Franz
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
04 Feb 2005 09:04:20 PM |
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Franz,
Don't feel so bad, a lot of people cry when they lose.
all the best,
Jeff Lee CENTER for REALITY PHYSICS
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
02 Feb 2005 10:25:45 PM |
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energy = 4.372x10^-6 eV, freq. = 1.057 GHz, wavelength = 28 cm.
Did I pass?
Now I've got one for you.
How can a photon instantly travel at the speed of light as it is
emitted from an electron which is orbiting within the atom at a
velocity more than a hundred times slower than the speed of light?
Thanks in advance (I always wanted to know the answer to that
question).
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
(NOTE: This is a duplicate post, as I don't know if the other one got
through (power problems due to weather. If it did, then just disregard
this one. Thanks.
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| User: "Franz Heymann" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
03 Feb 2005 01:27:24 AM |
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"Jeff" <JLeeCforRP@aol.com> wrote in message
news:1107404745.190382.144200@o13g2000cwo.googlegroups.com...
energy = 4.372x10^-6 eV, freq. = 1.057 GHz, wavelength = 28 cm.
Did I pass?
No. I answered more fully, pointing out that you cheated, in your
earliet note.
Now I've got one for you.
How can a photon instantly travel at the speed of light as it is
emitted from an electron which is orbiting within the atom at a
velocity more than a hundred times slower than the speed of light?
I answered that in your previous post
Thanks in advance (I always wanted to know the answer to that
question).
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
(NOTE: This is a duplicate post, as I don't know if the other one
got
through (power problems due to weather. If it did, then just
disregard
this one. Thanks.
No, I won't disregard this one, because I don't trust you not to claim
later that I did not rebuff your nonsense.
Franz
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
03 Feb 2005 08:47:41 PM |
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Jeff wrote:
Franz,
Pardon me, was that: "rebuff", or "rebluff"?
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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| User: "Uncle Al" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
27 Jan 2005 04:05:38 PM |
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Jeff wrote:
www.realityphysics.com <
All comments and opinions welcome.
http://www.mazepath.com/uncleal/sunshine.jpg
<http://www.albinoblacksheep.com/flash/youare.swf>
http://www.apa.org/journals/psp/psp7761121.html
http://insti.physics.sunysb.edu/~siegel/quack.html
<http://www.firehead.org/~jessh/film/kubrick/Kubrick-Psycho.html>
<http://www.naturalchild.com/elliott_barker/prisons.html>
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf
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| User: "Bjoern Feuerbacher" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
28 Jan 2005 03:47:10 AM |
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Jeff wrote:
www.realityphysics.com <
All comments and opinions welcome.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
That's the *third* time you posted this. When will you
finally begin considering the comments and opinions you
already got?
Bye,
Bjoern
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
28 Jan 2005 03:05:15 PM |
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Bjoern Feuerbacher wrote:
Jeff wrote:
www.realityphysics.com <
All comments and opinions welcome.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
That's the *third* time you posted this. When will you
finally begin considering the comments and opinions you
already got?
Bye,
Bjoern
As a matter of fact, I have considered all of them - but yours.
all the best,
Jeff Lee CENTER FOR REALITY PHYSICS
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