Science > Physics > The Complete Disproof of Relativity and current Quantum Mechanics
| Topic: |
Science > Physics |
| User: |
"Dr. Photon" |
| Date: |
31 Jan 2005 02:30:22 PM |
| Object: |
The Complete Disproof of Relativity and current Quantum Mechanics |
Jeff wrote:
...So please tell us, Dr Photon,
How do you calculate the observed wavelengths of the Atom using the
de
Broglie Equation as currently described by Quantum Mechanics?
lambda=hc/(E2-E1)
You accept that h, c, E1 and E2 are known values, as you quote them
all without derivation.
For the transitions, E1 and E2 are the energies of the levels, for the
"primary" levels, choose E2=0 (free space reference level).
I notice in your calculation that not only do you not derive the
energy levels, but to make it work you even have to quote (without
derivation)
"Vo[N1], which we know is: 2,188,500 meters per second"
Come on, how many parameters do you need???
...for the first time in the history of Quantum
Mechanics we are now able to calculate the CORRECT value for the
wavelengths of the Atom, something QM has been trying to do for over
seventy or eighty years now.
Rubbish. The hydrogen atom was one of the very first things solved by
QM. See for example:
http://www.vub.ac.be/CLEA/IQSA/history.html
"In the fall of 1925 he <Pauli> derived for the first time the
complete Balmer formula for the hydrogyn atom" which he published in
Zeitschr. Phys., 36, 336, (1926).
"And so Schrodinger indeed manages to present a wave model of the atom
and to also derive the complete Balmer formula" which he published in
Ann. der Phys., 79361, (1926).
Your model is totally useless. Not only do you need h, c and m from
measurement, you also need E and V. QM can derive the energy levels
and kinetic energy of the electrons quite happily (since 1926 for
goodness sake), whereas you cannot.
Maybe you didn't read my other posts on orbitals. Take a look at some
measurements of orbitals:
"Direct observation of d-orbital holes and Cu-Cu bonding in Cu2O",
http://www.nature.com/cgi-taf/DynaPage.taf?file=/nature/journal/v401/n6748/abs/401049a0_fs.html
main figure at
http://cbed.mse.uiuc.edu/images/cu2o.gif
"Tomographic imaging of molecular orbitals"
http://www.nature.com/cgi-taf/DynaPage.taf?file=/nature/journal/v432/n7019/abs/nature03183_fs.html
These all agree perfectly with QM. So QM not only got the energy
levels and the wavelengths of the transitions correct, it also
predicted the orbital shapes and got them correct too. What does your
model say of orbital shapes???
BR
.
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| User: "Jeff" |
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| Title: Re: The Complete Disproof of Relativity and current Quantum Mechanics |
01 Feb 2005 11:15:38 AM |
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Jeff wrote:
BR,
The Schrodinger equation uses the inverse values of the energy levels,
NOT MASS and VELOCITY. For decades Quantum Physics have been trying to
find a way to use the de Broglie Equation (electron's mass and orbital
velocity) to describe the wavelengths of the pilot orbit waves of the
atom.
However, they found it could not be done and "scrapped" the Bohr
Hydrogen Atom. The reason they could not do this is because Theoretical
Physicists today still make the misassumption that subatomic particles
are "static" entities. That is why they incorrectly try to use
electron's mass and pilot wave orbital velocity in the de Broglie
Equation with no success.
With Reality Physics subatomic particles are "ACTIVE" entities composed
of "the angular momentum of photon spin" (this has recently been proved
by experiment, as they have already made electron-position pairs,
exactly as predicted by Reality Physics more than two decades ago)
Using this CORRECT description of the electron as provided by Reality
Physics we find that when we multiply the mass "DECREASE" due to
velocity, taken from the original mass of the free electron, (AS
OPPOSED to the Mass Increase of Relativity - which is completely
wrong), and the "Photo Spin Velocity" reduction within the electron
(Reality Physics, NOT current QM which is also completely wrong) we do
obtain, not only the correct values of the wavelengths of the atom, but
we can also calculate the correct wavelength of a photon emitted by an
electron as it jumps orbits. So with Reality Physics, using MASS
DECREASE and reduced "PHOTON SPIN VELOCITY" we can get these CORRECT
answers.
So my challenge to you is: How do you use the de Broglie Equation (here
it is: wavelength = h / MASS x VELOCITY) to calculate the correct
wavelength values of the atom using current QM and the Mass Increase of
Relativity?
....and please, no more blathering BS. Thanks.
Also, the values I used can be found at a website called: "Wave Nature
of Electron". You should visit it, you might learn something!
All the best,
Jeff Lee CENTER FOR REALITY PHYSICS
www.realityphysics.com <
By the way, my orbits are exactly spherical is shape, no Uncertainty
Principle in Reality Physics since everything is certain, exact and
CORRECT, like Reality itself.
.
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