| Topic: |
Science > Physics |
| User: |
"Phil Gardner" |
| Date: |
16 Jul 2003 08:18:14 PM |
| Object: |
The kinetic energy of two interacting particles |
Any collision of a photon of sufficient energy with a fermion can
result in the creation of a new electron-positron pair. While the
cross-section for this process may be very small the only energy
constraint that must be satisfied is that the total kinetic energy (in
the centre of mass frame) of the photon-fermion pair before the
collision is not less than 1.02 Mev. If the Coulomb potential energy
equation, U = k.q1.q2/r, continues to hold right down to r = 0, as is
assumed in classical electrodynamics and in all existing quantum
mechanics models, and if also the fermion is a lepton (a point
particle), we have to accept that in the creation transition the
kinetic energy of the system jumps from a value of about 1 Mev to an
infinite value.
The questions that then arise are: (1) Is this the only alternative
compatible with the existing experimental evidence? (2) If it isn't
how low could the r = 0 limit on kinetic energy go without actual
conflict with this evidence?
Phil Gardner
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| User: "Steve Harris" |
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| Title: Re: The kinetic energy of two interacting particles |
16 Jul 2003 08:59:24 PM |
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"Phil Gardner" <pej_dg@dodo.com.au> wrote in message
news:ea961a86.0307161718.368be950@posting.google.com...
Any collision of a photon of sufficient energy with a
fermion can
result in the creation of a new electron-positron pair.
While the
cross-section for this process may be very small the only
energy
constraint that must be satisfied is that the total
kinetic energy (in
the centre of mass frame) of the photon-fermion pair
before the
collision is not less than 1.02 Mev. If the Coulomb
potential energy
equation, U = k.q1.q2/r, continues to hold right down to r
= 0, as is
assumed in classical electrodynamics and in all existing
quantum
mechanics models, and if also the fermion is a lepton (a
point
particle), we have to accept that in the creation
transition the
kinetic energy of the system jumps from a value of about 1
Mev to an
infinite value.
Nope. QED is an "existing quantum model". In QED the forces
between positron and electron never become infinite, because
when they close to distances closer than approximately the
"classical electron radius" the electric fields become
strong enough that virtual positron/electron pairs pop out
of the vacuum and screen the charges from each other. Thus,
all infinities of this type due to having "Coulomb fields"
around "point particles," are avoided. In QED they are no
longer Coulomb fields, and your Coulomb-type equation for U
is (strictly speaking) wrong.
Okay?
SBH
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| User: "S. Enterprize Company" |
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| Title: Re: The kinetic energy of two interacting particles |
17 Jul 2003 12:46:39 AM |
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Any collision of a photon of sufficient energy with a fermion can
result in the creation of a new electron-positron pair. While the
cross-section for this process may be very small the only energy
constraint that must be satisfied is that the total kinetic energy (in
the centre of mass frame) of the photon-fermion pair before the
collision is not less than 1.02 Mev. If the Coulomb potential energy
equation, U = k.q1.q2/r, continues to hold right down to r = 0, as is
assumed in classical electrodynamics and in all existing quantum
mechanics models, and if also the fermion is a lepton (a point
particle), we have to accept that in the creation transition the
kinetic energy of the system jumps from a value of about 1 Mev to an
infinite value.
r can't go to 0 which also proves QM and The Standard Model is wrong about
point particles with no size.
The questions that then arise are: (1) Is this the only alternative
compatible with the existing experimental evidence? (2) If it isn't
No, The Smart Model shows the correct principle. Like for example:
http://members.aol.com/link14738/SmartScattering.htm
how low could the r = 0 limit on kinetic energy go without actual
conflict with this evidence?
It does conflict with actual evidense but modern day physicists still claim
an electron has no size r = 0.
Phil Gardner
Smart's First Will And Testament Song
http://smart1234.s-enterprize.com/BeefmeatBlues.MP3
S. Enterprize (Science Journal)
http://smart1234.s-enterprize.com/
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| User: "Old Man" |
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| Title: Re: The kinetic energy of two interacting particles |
17 Jul 2003 10:23:01 PM |
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Phil Gardner <pej_dg@dodo.com.au> wrote in message
news:ea961a86.0307161718.368be950@posting.google.com...
Any collision of a photon of sufficient energy with a fermion can
result in the creation of a new electron-positron pair. While the
cross-section for this process may be very small the only energy
constraint that must be satisfied is that the total kinetic energy (in
the centre of mass frame) of the photon-fermion pair before the
collision is not less than 1.02 Mev. If the Coulomb potential energy
equation, U = k.q1.q2/r, continues to hold right down to r = 0, as is
assumed in classical electrodynamics and in all existing quantum
mechanics models, and if also the fermion is a lepton (a point
particle), we have to accept that in the creation transition the
kinetic energy of the system jumps from a value of about 1 Mev to an
infinite value.
The questions that then arise are: (1) Is this the only alternative
compatible with the existing experimental evidence? (2) If it isn't
how low could the r = 0 limit on kinetic energy go without actual
conflict with this evidence?
You have no evidence. Your education is far from complete.
Come back when you can speak intelligently about QED.
[Old Man]
Phil Gardner
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| User: "S. Enterprize Company" |
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| Title: Re: The kinetic energy of two interacting particles |
18 Jul 2003 01:59:23 AM |
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Phil Gardner <pej_dg@dodo.com.au> wrote in message
news:ea961a86.0307161718.368be950@posting.google.com...
Any collision of a photon of sufficient energy with a fermion can
result in the creation of a new electron-positron pair. While the
cross-section for this process may be very small the only energy
constraint that must be satisfied is that the total kinetic energy (in
the centre of mass frame) of the photon-fermion pair before the
collision is not less than 1.02 Mev. If the Coulomb potential energy
equation, U = k.q1.q2/r, continues to hold right down to r = 0, as is
assumed in classical electrodynamics and in all existing quantum
mechanics models, and if also the fermion is a lepton (a point
particle), we have to accept that in the creation transition the
kinetic energy of the system jumps from a value of about 1 Mev to an
infinite value.
The questions that then arise are: (1) Is this the only alternative
compatible with the existing experimental evidence? (2) If it isn't
how low could the r = 0 limit on kinetic energy go without actual
conflict with this evidence?
You have no evidence. Your education is far from complete.
Come back when you can speak intelligently about QED.
[Old Man]
An electron does have size it isn't equal to zero, r =/= 0. I believe the
relative mass size of an electron is it's Compton Wavelength for an electron,
where the electron mass is located ( theoretically).
I think the size of an electron is regard to it's own mass resonance state
is in the 10^-11m range.
I appears the more mass a particle has the smaller it's Compton wavelength
is. In a way this makes sense because the smaller the helix spiral core, more
pressure is applied to the spiral filed mass location. So even thought an
electron is smaller than a proton in size, it's mass resonance state is
actually larger.
Phil Gardner
Smart's First Will And Testament Song
http://smart1234.s-enterprize.com/BeefmeatBlues.MP3
S. Enterprize (Science Journal)
http://smart1234.s-enterprize.com/
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