Science > Physics > The ring gear and planetary gear having fun running around
| Topic: |
Science > Physics |
| User: |
"Spaceman" |
| Date: |
10 Mar 2006 03:04:55 PM |
| Object: |
The ring gear and planetary gear having fun running around |
Three part question so think before you answer.
A ring gear with a circumference of 1 meter is spinning at
1 revolution per second wrt an observer (A) standing to the north
1 inch away from the gear.
There is a white line (D) that (A) is counting going by and it is matching
the
tick on his watch that counts in seconds.
We stop the ring gear and we check on another gear on it.
On this ring gear there is a planetary gear (K) being driven to drive
around the gear in the same direction of motion the ring gear would be
rotating in, and this smaller gear and is passing by observer (A) at
10 times per second when the ring gear is not spinning.
Question 1:
If the ring gear spins at 1 meter per second (1 rev per second)
with this planetary gear still moving at the 10 ring gear circumferences
per second, what would observer (A) read for the planetary gears
revs wrt his position?
Question 2:
Is 11 revs per second for the planetary gear wrt (A) wrong in any way?
Question 3:
Would you ever want to use a velocity addition algebra
instead of simple algebra addition in this case and where would such be
used if it should at all?
--
James M Driscoll Jr
Spaceman
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| User: "PD" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 05:41:24 AM |
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Spaceman wrote:
Three part question so think before you answer.
A ring gear with a circumference of 1 meter is spinning at
1 revolution per second wrt an observer (A) standing to the north
1 inch away from the gear.
There is a white line (D) that (A) is counting going by and it is matching
the
tick on his watch that counts in seconds.
We stop the ring gear and we check on another gear on it.
On this ring gear there is a planetary gear (K) being driven to drive
around the gear in the same direction of motion the ring gear would be
rotating in, and this smaller gear and is passing by observer (A) at
10 times per second when the ring gear is not spinning.
Question 1:
If the ring gear spins at 1 meter per second (1 rev per second)
with this planetary gear still moving at the 10 ring gear circumferences
per second, what would observer (A) read for the planetary gears
revs wrt his position?
Question 2:
Is 11 revs per second for the planetary gear wrt (A) wrong in any way?
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Question 3:
Would you ever want to use a velocity addition algebra
Why yes, of course you would want to use velocity addition algebra.
You're adding velocities after all.
instead of simple algebra addition in this case and where would such be
used if it should at all?
--
James M Driscoll Jr
Spaceman
.
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| User: "Hexenmeister" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 06:41:29 AM |
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"PD" <TheDraperFamily@gmail.com> wrote in message
news:1142077284.937476.245260@i39g2000cwa.googlegroups.com...
Spaceman wrote:
Three part question so think before you answer.
A ring gear with a circumference of 1 meter is spinning at
1 revolution per second wrt an observer (A) standing to the north
1 inch away from the gear.
There is a white line (D) that (A) is counting going by and it is
matching
the
tick on his watch that counts in seconds.
We stop the ring gear and we check on another gear on it.
On this ring gear there is a planetary gear (K) being driven to drive
around the gear in the same direction of motion the ring gear would be
rotating in, and this smaller gear and is passing by observer (A) at
10 times per second when the ring gear is not spinning.
Question 1:
If the ring gear spins at 1 meter per second (1 rev per second)
with this planetary gear still moving at the 10 ring gear circumferences
per second, what would observer (A) read for the planetary gears
revs wrt his position?
Question 2:
Is 11 revs per second for the planetary gear wrt (A) wrong in any way?
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Ok, the men in the white coats will be along shortly.
Is 11 revs per alignment of the white line for the planetary gear
wrt (A) wrong in any way?
Were these synchromesh gears, BTW?
If so Bielawski has a question about your answer.
Androcles
Question 3:
Would you ever want to use a velocity addition algebra
Why yes, of course you would want to use velocity addition algebra.
You're adding velocities after all.
instead of simple algebra addition in this case and where would such be
used if it should at all?
--
James M Driscoll Jr
Spaceman
.
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| User: "Spaceman" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 10:27:16 AM |
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"Hexenmeister" <vanquish@broom.Mickey> wrote in message
news:ZzzQf.111364$Q22.56252@fe1.news.blueyonder.co.uk...
"PD" <TheDraperFamily@gmail.com> wrote in message
news:1142077284.937476.245260@i39g2000cwa.googlegroups.com...
Spaceman wrote:
Three part question so think before you answer.
A ring gear with a circumference of 1 meter is spinning at
1 revolution per second wrt an observer (A) standing to the north
1 inch away from the gear.
There is a white line (D) that (A) is counting going by and it is
matching
the
tick on his watch that counts in seconds.
We stop the ring gear and we check on another gear on it.
On this ring gear there is a planetary gear (K) being driven to drive
around the gear in the same direction of motion the ring gear would be
rotating in, and this smaller gear and is passing by observer (A) at
10 times per second when the ring gear is not spinning.
Question 1:
If the ring gear spins at 1 meter per second (1 rev per second)
with this planetary gear still moving at the 10 ring gear circumferences
per second, what would observer (A) read for the planetary gears
revs wrt his position?
Question 2:
Is 11 revs per second for the planetary gear wrt (A) wrong in any way?
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Ok, the men in the white coats will be along shortly.
Is 11 revs per alignment of the white line for the planetary gear
wrt (A) wrong in any way?
Were these synchromesh gears, BTW?
If so Bielawski has a question about your answer.
Yes PD's velocity adding gears would break after a while.
but good thing the gears don't use such velocity addition *****
in reality.. and they actually proved PD wrong after 1 million
revs without breaking and they are proving PD wrong
billions of revs later also.
:)
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| User: "Spaceman" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 10:23:55 AM |
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"PD" <TheDraperFamily@gmail.com> wrote in message
news:1142077284.937476.245260@i39g2000cwa.googlegroups.com...
Spaceman wrote:
Three part question so think before you answer.
A ring gear with a circumference of 1 meter is spinning at
1 revolution per second wrt an observer (A) standing to the north
1 inch away from the gear.
There is a white line (D) that (A) is counting going by and it is
matching
the
tick on his watch that counts in seconds.
We stop the ring gear and we check on another gear on it.
On this ring gear there is a planetary gear (K) being driven to drive
around the gear in the same direction of motion the ring gear would be
rotating in, and this smaller gear and is passing by observer (A) at
10 times per second when the ring gear is not spinning.
Question 1:
If the ring gear spins at 1 meter per second (1 rev per second)
with this planetary gear still moving at the 10 ring gear circumferences
per second, what would observer (A) read for the planetary gears
revs wrt his position?
Question 2:
Is 11 revs per second for the planetary gear wrt (A) wrong in any way?
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Well,
after a long time, this would be a probem.
You don't get that huh?
You get a C- for a grade.
And we will not allow you to design gearing mechanisms.
:)
Question 3:
Would you ever want to use a velocity addition algebra
Why yes, of course you would want to use velocity addition algebra.
You're adding velocities after all.
Again, your gearing grade is only a C-.
You have bad gearing..
:)
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| User: "T Wake" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 10:43:02 AM |
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"Spaceman" <Realspace@comcast.not> wrote in message
news:QpmdnVHkJecHZI_ZRVn-qg@comcast.com...
"PD" <TheDraperFamily@gmail.com> wrote in message
news:1142077284.937476.245260@i39g2000cwa.googlegroups.com...
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Well,
after a long time, this would be a probem.
Do you know how long?
You don't get that huh?
You get a C- for a grade.
And we will not allow you to design gearing mechanisms.
.
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| User: "Spaceman" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 11:04:03 AM |
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"T Wake" <taswakeAt@hotmail.com> wrote in message
news:-_ednUDUTrCHY4_ZRVnyiw@pipex.net...
"Spaceman" <Realspace@comcast.not> wrote in message
news:QpmdnVHkJecHZI_ZRVn-qg@comcast.com...
"PD" <TheDraperFamily@gmail.com> wrote in message
news:1142077284.937476.245260@i39g2000cwa.googlegroups.com...
Well, yes, it's wrong, but not by much.
I assume that the inner cirumference of the ring gear is such that 1
rev/sec corresponds to a tangential speed of 1m/s as you say.
The right tangential speed of the planetary gear is
(1+10)/(1 + (1)(10)/c^2) = 10.9999999999999988 m/s or
10.9999999999999988 rev/s.
It would be hard, however, to tell the difference between this and 11
rev/s unless you were extremely careful to drive the gears at constant
speed and waited a large number of revolutions to detect the difference
between the right answer and 11 rev/s. Not at all impossible to
measure, though, and an excellent experiment to try to see which one is
correct.
Well,
after a long time, this would be a probem.
Do you know how long?
Yup
1 second and he already has the problem.
(even less time would show he has a problem)
and the more it runs if he was correct
the more of a problem it would have.
but of course, in reality it has no such problem
and the correct reality of the gears is the 11 revs per second.
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| User: "T Wake" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 11:21:46 AM |
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"Spaceman" <Realspace@comcast.not> wrote in message
news:LMWdnWTMiYufno7ZRVn-tw@comcast.com...
"T Wake" <taswakeAt@hotmail.com> wrote in message
news:-_ednUDUTrCHY4_ZRVnyiw@pipex.net...
Well,
after a long time, this would be a probem.
Do you know how long?
Yup
1 second and he already has the problem.
(even less time would show he has a problem)
and the more it runs if he was correct
the more of a problem it would have.
but of course, in reality it has no such problem
and the correct reality of the gears is the 11 revs per second.
Nope. It would take longer than 1 second for the problem in alignment to
become apparent to the gears.
.
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| User: "Spaceman" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 11:46:15 AM |
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"T Wake" <taswakeAt@hotmail.com> wrote in message
news:EMWdnfCBO-Gymo7ZnZ2dnUVZ8qGdnZ2d@pipex.net...
"Spaceman" <Realspace@comcast.not> wrote in message
news:LMWdnWTMiYufno7ZRVn-tw@comcast.com...
"T Wake" <taswakeAt@hotmail.com> wrote in message
news:-_ednUDUTrCHY4_ZRVnyiw@pipex.net...
Well,
after a long time, this would be a probem.
Do you know how long?
Yup
1 second and he already has the problem.
(even less time would show he has a problem)
and the more it runs if he was correct
the more of a problem it would have.
but of course, in reality it has no such problem
and the correct reality of the gears is the 11 revs per second.
Nope. It would take longer than 1 second for the problem in alignment to
become apparent to the gears.
But the math PD used shows a problem occuring already.
the answer was not 11 according to this "supposed problem".
That shows a problem occuring that will only increase with each rev
per second.
It seems you don't know how gears work huh?
LOL
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| User: "T Wake" |
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| Title: Re: The ring gear... |
11 Mar 2006 02:43:55 PM |
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On Saturday 11 March 2006 17:46, Spaceman decided it was time and wrote in
sci.physics (<69CdnTBB4pd7kY7ZnZ2dnUVZ_vudnZ2d@comcast.com>):
It seems you don't know how gears work huh?
LOL
Whatever.
--
T Wake
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| User: "" |
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| Title: Re: The ring gear and planetary gear having fun running around |
11 Mar 2006 05:43:47 AM |
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What if I've had a lifetime such problems and just want to get the barn
painted????????
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