| Topic: |
Science > Physics |
| User: |
"jrivanov" |
| Date: |
03 Mar 2005 11:34:26 PM |
| Object: |
Trajectory problem pls help |
:?:
I've worked on this problem for hours.
An object travels from ground level up at an angle of 53.1 degrees and
lands 134 meters away what is the vectors velocity? Don't consider air
resistance. Thanks in advance......
John
P.S. I thought system of equations using constant acceleration
formulas trying to figure horizontal velocity. then I thought time
in the air starting from the vertex and doubling time for total time.
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| User: "Gregory L. Hansen" |
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| Title: Re: Trajectory problem pls help |
04 Mar 2005 08:35:17 AM |
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In article <4227f362$3_2@127.0.0.1>,
jrivanov <ilonajohn@netzero-dot-com.no-spam.invalid> wrote:
:?:
I've worked on this problem for hours.
An object travels from ground level up at an angle of 53.1 degrees and
lands 134 meters away what is the vectors velocity? Don't consider air
resistance. Thanks in advance......
John
P.S. I thought system of equations using constant acceleration
formulas trying to figure horizontal velocity. then I thought time
in the air starting from the vertex and doubling time for total time.
Draw a diagram showing the trajectory in x versus y, the launching and
impact points, and the initial velocity with angle from the horizontal.
I assume you know from your textbook that the equations of motion can be
written
x(t) = x0 + v_x t
y(t) = y0 + v_y t + 1/2 a_y t^2
And furthermore, that a velocity can be decomposed into components,
v_x = v cos(theta)
v_y = v sin(theta)
Substitute v_x and v_y, and you're left with two equations with two
unknowns. Eliminate t by substitution, solve for v, and insert known or
assumed quantities for x(0), y(0), x(t_impact), y(t_impact), and a_y.
--
"In any case, don't stress too much--cortisol inhibits muscular
hypertrophy. " -- Eric Dodd
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| User: "Steven Gray" |
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| Title: Re: Trajectory problem pls help |
07 Mar 2005 09:41:04 PM |
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ilonajohn@netzero-dot-com.no-spam.invalid (jrivanov) wrote in news:4227f362
$3_2@127.0.0.1:
P.S. I thought system of equations using constant acceleration
formulas trying to figure horizontal velocity. then I thought time
in the air starting from the vertex and doubling time for total time.
You're on the right track. Go with that doubling time idea and get time as
a function of the initial vertical component of velocity. Then also
express time to go the given horizontal distance in terms of the horizontal
component of velocity. I'm sure you'll see where to go from there.
--
Steve Gray
sgray2@cfl.rr.com
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