1) Consider rotating particle mass m, spin h . (spin is aligned with
the L=moment of coordinate system) in the center of rotating
coordinate system;
Direction of rotation of system and speed is defined by moment L of
rotating coordinate system.

2) Consider an event when at time t= 0 in a distance l new particle
mass m and OPPOSITE spin h emerges somewhere far away - e.g. from
splitting of atom ; let us assume initial speed v=0 towards our
original mass m in the center.

After time t= l/c^2 after event the first particle in the rotating
system will start to "feel " that new particle by its mass and will
start attracting it. the trajectories will probably lie on a straight
line; However, after time t=l/c the law of moment conservation will
kick in nad masses will start to rotate around common mass center as
straight trajectory at t=l/c will become unstable: but which direction
the rotation about mass center will have?

That will be decided by the need to conserve total momentum L +h-h so
it remains constant; which means rotation will be chosen in same
direction as L;

Attraction continues, so arriving particle move via spiral towards
center; Howeevr, it can not g et closer as R kerr m+m because the need
to conserve moment will not allow it.

Finally, both particles will move on a circular orbit with average R
between Rk+, Rk-.
But THEY WILL be oscillating; between internal orbits Rk-, Rk+ where v-

v +

Oscillating force is anhrmonic, so solution is not simple; Only thing
one can say that for this 2 particle system


as delta R= R kerr + - R kerr - = h^2/m3*G, delta V = v- - v+ = h/m
delta R

If we multiply insert Delta R from first Equation into second,

Delta V* Delta R= h/m or Delta V*m*Delta R= h

which is Heisenberg uncertainty principle.

Another result of this is that speed of gravitational interaction is

g=c^2 = m^2/s^2 = 9 * 10^16 m^2/c^2


Because the particles ar in rotating coordinate system, they CAN
oscillate without violating any laws.

1) Consider rotating particle mass m, spin h . (spin is aligned with
the L=moment of coordinate system) in the center of rotating
coordinate system;
Direction of rotation of system and speed is defined by moment L of
rotating coordinate system.

2) Consider an event when at time t= 0 in a distance l new particle
mass m and OPPOSITE spin h emerges somewhere far away - e.g. from
splitting of atom ; let us assume initial speed v=0 towards our
original mass m in the center.

After time t= l/c^2 after event the first particle in the rotating
system will start to "feel " that new particle by its mass and will
start attracting it. the trajectories will probably lie on a straight
line; However, after time t=l/c the law of moment conservation will
kick in nad masses will start to rotate around common mass center as
straight trajectory at t=l/c will become unstable: but which direction
the rotation about mass center will have?

That will be decided by the need to conserve total momentum L +h-h so
it remains constant; which means rotation will be chosen in same
direction as L;

Attraction continues, so arriving particle move via spiral towards
center; Howeevr, it can not g et closer as R kerr m+m because the need
to conserve moment will not allow it.

Finally, both particles will move on a circular orbit with average R
between Rk+, Rk-.
But THEY WILL be oscillating; between internal orbits Rk-, Rk+ where v-

v +

Oscillating force is anhrmonic, so solution is not simple; Only thing
one can say that for this 2 particle system


as delta R= R kerr + - R kerr - = h^2/m3*G, delta V = v- - v+ = h/m
delta R

If we multiply insert Delta R from first Equation into second,

Delta V* Delta R= h/m or Delta V*m*Delta R= h

which is Heisenberg uncertainty principle.

Another result of this is that speed of gravitational interaction is

g=c^2 = m^2/s^2 = 9 * 10^16 m^2/c^2


Because the particles ar in rotating coordinate system, they CAN
oscillate without violating any laws.