Science > Physics > Visualizing curved space-time objectively & locally
| Topic: |
Science > Physics |
| User: |
"Jack Sarfatti" |
| Date: |
16 Oct 2005 01:44:05 AM |
| Object: |
Visualizing curved space-time objectively & locally |
How to visualize curved space-time intrinsically free of local
coordinate transformations?
Intrinsic pictures of 4D metrics
How do we plot on a computer, the local frame invariant
g(x) = ds^2(x) = guv(x)dx^udx^v
SSS example
r > 2rs
g(r,@) = (1-2rs/r)(cdt)^2 - (1-2rs/r)^-1dr^2 - r^2(d@^2 + sin^2@d&^2)
g(r',@') = (1-2rs/r')(cdt)^2 - (1-2rs/r')^-1dr^2 - r'^2(d@^2 + sin^2@'d&^2)
The infinitesimals
cdt, dr, rd@ & rd& << rs/r^3
These are 4 parameters to keep fixed in the computer simulation. They
correspond to a kind of lattice spacing and maybe we can do something
analogous to a renormalization group flow to a fixed point?
This metric is static - no t-dependence. We only have 2 effective
variables, r & @ so we can plot g(r,@) with the infinitesimals as
parameters.
Note that the EEP tetrad decomposition is
g(x) = (1 + B(x)^I)nIJ(1 + B(x)^J)
= (1^0 + B^0)^2 - (1^1 + B^1)^2 - (1^2 + B^2)^2 - (1^3 + B^3)^2
(1^0 + B^0)^2 = 1^0^2 + 21^0B^0 + B^0^2 = (1 + 2B^00 + B^00^2)(cdt)^2
Therefore
2B^00 + B^00^2 = -2rs/r
B^00 = (hG/c^3)^1/2(1/c)dTheta/dt this must be dimensionless
Theta = Goldstone phase of the vacuum coherence.
Similarly,
(1^1 + B^1)^2 = 1^1^2 + 21^1B^1 + B^12 = (1 + 2B^11 + B^11^2)(dr)^2
1 + 2B^11 + B^11^2 = (1 - 2rs/r)^-1 = 1 + 2rs/r + (2rs/r)^2 + ...
B1^1 = (hG/c^3)^1/2dTheta/dr
Note that the relation between the gradients of the vacuum phase and the
set of global "coordinates" is highly nonlinear especially in space.
To be continued.
.
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| User: "hanson" |
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| Title: Re: Visualizing curved space-time objectively & locally |
17 Oct 2005 12:40:43 AM |
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"Jack Sarfatti" <sarfatti@pacbell.net> wrote
How to visualize curved space-time intrinsically free of local coordinate
transformations?
[hanson]
Ok, ok, Jack, or for that matter any other rela-fan:
Do present a verba/visualsation that and how space-time curves,
in a situation where/that gravity is not a force but a curving of space
induced by the masses present.
Describe a step by step scenario without invoking forces of what
happens when you step out of the window on the 5th floor and
how space curves on the way down... and in particular of what kink
happens to the curvature when you arrive in the local neighborhood
of the CaAl-silicate electrons on/in the pavement.... ahahaha....
Seriously: to present a intuitively acceptable picture sequence of this
journey down, in Newtonian <=> Einsteinian lingotrans, would go a
long way to convince and quiet the doubters and retractors of relativity...
Get at it, dude/tte/s... ahahaha... ahahahanson
"Jack Sarfatti" <sarfatti@pacbell.net> wrote in message
news:VEm4f.1278$q%.827@newssvr12.news.prodigy.com...
Intrinsic pictures of 4D metrics
How do we plot on a computer, the local frame invariant
g(x) = ds^2(x) = guv(x)dx^udx^v
SSS example
r > 2rs
g(r,@) = (1-2rs/r)(cdt)^2 - (1-2rs/r)^-1dr^2 - r^2(d@^2 + sin^2@d&^2)
g(r',@') = (1-2rs/r')(cdt)^2 - (1-2rs/r')^-1dr^2 - r'^2(d@^2 + sin^2@'d&^2)
The infinitesimals
cdt, dr, rd@ & rd& << rs/r^3
These are 4 parameters to keep fixed in the computer simulation. They
correspond to a kind of lattice spacing and maybe we can do something
analogous to a renormalization group flow to a fixed point?
This metric is static - no t-dependence. We only have 2 effective variables, r
& @ so we can plot g(r,@) with the infinitesimals as parameters.
Note that the EEP tetrad decomposition is
g(x) = (1 + B(x)^I)nIJ(1 + B(x)^J)
= (1^0 + B^0)^2 - (1^1 + B^1)^2 - (1^2 + B^2)^2 - (1^3 + B^3)^2
(1^0 + B^0)^2 = 1^0^2 + 21^0B^0 + B^0^2 = (1 + 2B^00 + B^00^2)(cdt)^2
Therefore
2B^00 + B^00^2 = -2rs/r
B^00 = (hG/c^3)^1/2(1/c)dTheta/dt this must be dimensionless
Theta = Goldstone phase of the vacuum coherence.
Similarly,
(1^1 + B^1)^2 = 1^1^2 + 21^1B^1 + B^12 = (1 + 2B^11 + B^11^2)(dr)^2
1 + 2B^11 + B^11^2 = (1 - 2rs/r)^-1 = 1 + 2rs/r + (2rs/r)^2 + ...
B1^1 = (hG/c^3)^1/2dTheta/dr
Note that the relation between the gradients of the vacuum phase and the set
of global "coordinates" is highly nonlinear especially in space.
To be continued.
[hanson]
Now, Jack, tell me what you have experienced here so far
in/by/thru' a few Newtonian sententes...
Do it now, before you hit the concrete!
ahahaha... ahahanson
.
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