| Topic: |
Science > Physics |
| User: |
"NILS BÖRJESSON" |
| Date: |
27 Feb 2006 12:43:56 PM |
| Object: |
WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE? |
WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE?
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S=1/2.e^3.E0^-2.C^-3.ME^-2
e = ELEMENTEARY CHARGE
E0 = THE PERMITTIVITY OF VACUUM
C = THE SPEED OF LIGHT
ME = THE MASS OF THE ELECTRON
S IS THE TEDENSTIGBÖRJESSONS CONSTANT
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| User: "Sam Wormley" |
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| Title: Re: WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE? |
27 Feb 2006 12:57:28 PM |
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NILS BÖRJESSON wrote:
WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE?
::::::::::::::::::::::::::::::::::::::::::::::::
S=1/2.e^3.E0^-2.C^-3.ME^-2
e = ELEMENTEARY CHARGE
E0 = THE PERMITTIVITY OF VACUUM
C = THE SPEED OF LIGHT
ME = THE MASS OF THE ELECTRON
Flush! *Plonk*
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| User: "QCD Apprentice" |
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| Title: Re: WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE? |
27 Feb 2006 12:49:38 PM |
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NILS BÖRJESSON wrote:
WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE?
::::::::::::::::::::::::::::::::::::::::::::::::
S=1/2.e^3.E0^-2.C^-3.ME^-2
e = ELEMENTEARY CHARGE
E0 = THE PERMITTIVITY OF VACUUM
C = THE SPEED OF LIGHT
ME = THE MASS OF THE ELECTRON
S IS THE TEDENSTIGBÖRJESSONS CONSTANT
Numerology has little meaning.
If you have four numbers, it's not hard to find products of
powers of these numbers to fit just about anything you want.
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| User: "FrediFizzx" |
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| Title: Re: WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE? |
27 Feb 2006 02:25:46 PM |
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"QCD Apprentice" <qcd.apprentice@gmail.com> wrote in message
news:dtvhk2$27a$1@news.doit.wisc.edu...
| NILS BÖRJESSON wrote:
| > WHY IS THIS CONSTANT IN MKSA SO CLOSE TO ONE?
| > ::::::::::::::::::::::::::::::::::::::::::::::::
| >
| > S=1/2.e^3.E0^-2.C^-3.ME^-2
| >
| > e = ELEMENTEARY CHARGE
| > E0 = THE PERMITTIVITY OF VACUUM
| > C = THE SPEED OF LIGHT
| > ME = THE MASS OF THE ELECTRON
| >
| > S IS THE TEDENSTIGBÖRJESSONS CONSTANT
| >
| Numerology has little meaning.
| If you have four numbers, it's not hard to find products of
| powers of these numbers to fit just about anything you want.
Besides that, it is not even close to a dimensionless constant of one.
;-)
FrediFizzx
http://www.vacuum-physics.com
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