"Magcialking" <magic_king@163.com> schrieb im Newsbeitrag
news:1156908269.372396.60840@p79g2000cwp.googlegroups.com...

for example,in the function "int a(int[] b)", I wanna every element
of
array b to be dealt with, but b's length remains unkown, so what can
I
do?

In C you would pass the number of elements in a 2nd argument. You can
also define a "last item" value. Or you can simply guess ;)

void Func_BehindTheCurtains(int *p,size_t len) {}

, and then invoke it using the following:

template<size_t len>
void Func(int (&arr)[len])
{
return Func_BehindTheCurtains(arr,len);
}

Magcialking posted:

for example,in the function "int a(int[] b)", I wanna every element
of array b to be dealt with, but b's length remains unkown, so what
can I do?

The following two functions are exactly equivalent:

void Func(int arr[]) {}

void Func(int *arr) {}

You cannot pass an array by value to a function. If you write a
function signature with a parameter such as arr[], you're really just
taking a pointer by value.

If you want your function to be able to take an array (and to know its
length), then start off with a function such as the following:


void Func_BehindTheCurtains(int *p,size_t len) {}

, and then invoke it using the following:

template<size_t len>
void Func(int (&arr)[len])
{
return Func_BehindTheCurtains(arr,len);
}

Now you can invoke it as follows:

int main()
{
int arr[43];

Func(arr);
}

On 29 Aug 2006 20:24:29 -0700 in comp.lang.c++, "Magcialking"
<magic_king@163.com> wrote,

for example,in the function "int a(int[] b)", I wanna every element of
array b to be dealt with, but b's length remains unkown, so what can I
do?

Write it in C++ instead of C.
Avoid bare naked arrays.
You might end up with something like:
int a(std::vector<int> & b)

Otherwise, you have to pass the number of elements as an additional
argument, or something.