| Topic: |
DEVELOP > c-Plus-Plus |
| User: |
"Henryk" |
| Date: |
12 Sep 2006 03:45:22 AM |
| Object: |
Memory layout of a class with only static members? |
I have something like
class Params {
public:
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
};
This is just a wrapper for globally used parameters in an embedded
system.
Now, I need to do a binary copy of this data to and from some Flash.
So, what I need is the start address and the size of the data.
Unfortunatelly, sizeof(Params) gives 1.
I added dummy variables at the beginning and the end that can be used
to retreive the information.
class Params {
public:
const static char nBegin = 0;
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
// new parameters can be added before nEnd
const static char nEnd = 0;
};
I thought that the begin is &Params::nBegin and the size of all data is
&Params::nEnd - &Params::nBegin + sizeof(Params::nEnd).
It works for this little test class above. But my real class contains
much more data and a test program in VS sorts them in memory
differently. In my case nBegin and nEnd are put together. I think for
memory alignment reasons.
Then I put the class in some special section and everything seems to
work.
My questions:
Does it now work only by accident or is this guarantied?
Are there any better ways to solve the problem without changing the
general layout of the class. In my real application the parameters are
referenced already 100s of times.
Thank you for your comments.
.
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| User: "" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 05:57:52 AM |
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Henryk wrote:
I have something like
class Params {
public:
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
};
This is just a wrapper for globally used parameters in an embedded
system.
Now, I need to do a binary copy of this data to and from some Flash.
So, what I need is the start address and the size of the data.
Incorrect assumption. You assume 1 (one) start address and a contiguous
block of memory after that. There is no reason for that. In fact, for
alignment
purposes, it often is better to store the chars together, the ints
together,
etctera. The order nTwo, nOne, nThree often is the most compact.
HTH,
Michiel Salters
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| User: "F.J.K." |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 07:53:14 AM |
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Henryk wrote:
class Params {
public:
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
};
Now, I need to do a binary copy of this data to and from some Flash.
So, what I need is the start address and the size of the data.
Unfortunatelly, sizeof(Params) gives 1.
I might be dense, but if you have data that needs to be changed on a
regular base ("copy of this data ... from some Flash."), choosing const
attributes seems to be the wrong thing to do in the first place. Sure,
you could try to const_cast<> away the const. But after all, what stops
the compiler from inserting known const values directly into the code,
without any object memory reference? What stops it, from not generating
an object in memory at all?
I think I can deduce why you went this direction in the first place.
You probably want to have a property API that can be queried without
initialisation and/or construction of an object like:
int v = a::property1
It seems though, that you really DO need an object, if you need write
access to it. This is a flaw in your original design.
I think rereading the first chapters of KR would be a good idea, to get
your head free for the Non-OO obfuscated basic language features to
use:
--- file a.h
struct A {
int property1;
int property2;
int property3;
};
extern A a;
--- file a.cpp
#include "a.h"
A a={5,4,3};
--- file main.cpp
#include <iostream>
#include "a.h"
int main () {
std::cout << "Property 1: " << a.property1 << "\n";
std::cout << "Property 2: " << a.property2 << "\n";
std::cout << "Property 3: " << a.property3 << "\n";
}
Can't get any more basic than that, can it ? ;-)
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| User: "Goran" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 05:00:16 AM |
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I don't know about the inner workings of the compiler regarding the
layout of static members, however...
Now, I need to do a binary copy of this data to and from some Flash.
You already have at least two instances of Params: in flash and, I
guess, in your program's memory. Using static, you only get one
instance of the thing, but it seems you have more.
You may try like this:
struct Params
{
int p1;
int p2;
// ...
};
static Params& FlashParams =
*reinterpret_cast<Params*>(0xYOUR_PARAMS_IN_FLASH_ADDRESS_HERE);
void Test()
{
int copy1 = FlashParams.p1;
int copy2 = FlashParams.p2;
Params RamParams = FlashParams;
// etc...
}
Hey, typing-wise, it's even shorter than Params::p1!
Of course, you need to take care not to call Test() before the
initialization of FlashParams (highly unusual situation in my line of
work, don't know about yours).
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| User: "Henryk" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 05:44:19 AM |
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Goran schrieb:
I don't know about the inner workings of the compiler regarding the
layout of static members, however...
Now, I need to do a binary copy of this data to and from some Flash.
You already have at least two instances of Params: in flash and, I
guess, in your program's memory. Using static, you only get one
instance of the thing, but it seems you have more.
I declared the members as static because the program must not change
them.
Actually I have only 1 instance in my program memory. These are the
default parameters. But now we need some kind of parameter update
mechanism. In Flash there is just binary data that shall be copied to
the memory location where the static parameters reside. It's not
another parameter instance but plain binary data (of course in the
right format).
You may try like this:
struct Params
{
int p1;
int p2;
// ...
};
static Params& FlashParams =
*reinterpret_cast<Params*>(0xYOUR_PARAMS_IN_FLASH_ADDRESS_HERE);
void Test()
{
int copy1 = FlashParams.p1;
int copy2 = FlashParams.p2;
Params RamParams = FlashParams;
// etc...
}
That was my other solution but then I have to change all the code where
parameters are referenced. Before I do this I want to be sure that
there are no easier solutions. And, of course I would like to know what
the standard says about this issue.
Hey, typing-wise, it's even shorter than Params::p1!
Long time ago I decided to use the "class with static members" approach
because it saves the global object (static Params ...). It looks like
this was somehow the wrong decision... :o)
Greetings
Henryk
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| User: "David Harmon" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 06:28:46 AM |
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On 12 Sep 2006 01:45:22 -0700 in comp.lang.c++, "Henryk"
<henryk.mueller@gmx.de> wrote,
class Params {
public:
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
};
Now, I need to do a binary copy of this data to and from some Flash.
So, what I need is the start address and the size of the data.
What data? You have three constants. There is actually no
guarantee they are going to occupy memory at all, unless you take
the address of each of them somewhere. There is no guarantee they
are going to be located anywhere near each other by any kind of
reckoning. In many cases a good compiler will just substitute the
const values into the generated code where needed.
.
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| User: "Henryk" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 07:28:05 AM |
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David Harmon schrieb:
On 12 Sep 2006 01:45:22 -0700 in comp.lang.c++, "Henryk"
<henryk.mueller@gmx.de> wrote,
class Params {
public:
const static char nOne = 1;
const static int nTwo = 2;
const static char nThree = 3;
};
Now, I need to do a binary copy of this data to and from some Flash.
So, what I need is the start address and the size of the data.
What data? You have three constants. There is actually no
guarantee they are going to occupy memory at all, unless you take
the address of each of them somewhere. There is no guarantee they
are going to be located anywhere near each other by any kind of
reckoning. In many cases a good compiler will just substitute the
const values into the generated code where needed.
Const variables are ROMable and as far as I know the compiler *should*
not replace the references by the actual values. That was one of the
the reason we used this approach. We can change the value on one memory
location. I checked the executable file before and this compiler (GCC
for PowerPC) does not optimize away my const parameters.
Back to problem, we now use a separate memory section for the parameter
data with a known address and and a known size. So I can copy this part
forth and back without considering any alignment issues inside this
section.
Henryk
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| User: "Noah Roberts" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 10:53:28 AM |
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Henryk wrote:
Const variables are ROMable and as far as I know the compiler *should*
not replace the references by the actual values.
Not portable, not even with the same compiler. Since a const object
will *never* change (that is what the keyword means and the fact that
you "can" is taken care of by the standard by saying if you do then
your program is ill-formed and illicits undefined behavior) then the
compiler is free to use the "as-if" (if there is no other explicit rule
in the standard to govern this) and optimize away the actual variable.
Since the variable never changes then optimizing it away and passing
the value into places expecting it works "as-if" the variable existed.
It can't do this if the address of the variable is used for any reason
though it still can in other places (in other words you could be using
different objects depending on how this data is used). The compiler is
free to assume a const object will not change because if it does it is
free to do anything at all, including not functioning at all as
expected.
That was one of the
the reason we used this approach.
The reasoning is flawed. You'll want to stop doing it. You are
relying on implementation defined behavior and it might not be what you
are thinking.
We can change the value on one memory
location. I checked the executable file before and this compiler (GCC
for PowerPC) does not optimize away my const parameters.
const parameters or const variables? There is a big difference.
Back to problem, we now use a separate memory section for the parameter
data with a known address and and a known size. So I can copy this part
forth and back without considering any alignment issues inside this
section.
There are no alignment issues beyond the fact that these variables are
quite likely not aligned at all. They have no set memory layout except
for each individual variable's given layout (ie sizeof(float) bytes in
contiguous memory to store a float). The variables are not part of any
instance of your class and are not necissarily anywhere near each other
in memory (unlike if they WHERE part of your class). Your class
actually has no size at all, but it gets one byte because it is
necissary to be able to store variables of that type. Consider static
variables as globals only accessable by, or through, your class...this
link is by name only and for the compiler, it doesn't reflect compiled
program layout.
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| User: "F.J.K." |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 08:28:56 AM |
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Henryk wrote:
Const variables are ROMable and as far as I know the compiler *should*
not replace the references by the actual values. That was one of the
the reason we used this approach. We can change the value on one memory
location. I checked the executable file before and this compiler (GCC
for PowerPC) does not optimize away my const parameters.
Back to problem, we now use a separate memory section for the parameter
data with a known address and and a known size. So I can copy this part
forth and back without considering any alignment issues inside this
section.
Henryk
Do you want your data unchangable (const) or do you want to "copy back
and forth" (non nonst)? The time for a decision is now ;-) . Anyway, if
you really want const, see the code in my posting below and change A
a={5,6,7}; to const A a={5,6,7}. You'll probably use some extra flash
routine to write to this const data and know better than I about it ;-)
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| User: "Henryk" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 10:38:18 AM |
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F.J.K. schrieb:
Henryk wrote:
Const variables are ROMable and as far as I know the compiler *should*
not replace the references by the actual values. That was one of the
the reason we used this approach. We can change the value on one memory
location. I checked the executable file before and this compiler (GCC
for PowerPC) does not optimize away my const parameters.
Back to problem, we now use a separate memory section for the parameter
data with a known address and and a known size. So I can copy this part
forth and back without considering any alignment issues inside this
section.
Henryk
Do you want your data unchangable (const) or do you want to "copy back
and forth" (non nonst)? The time for a decision is now ;-) . Anyway, if
you really want const, see the code in my posting below and change A
a={5,6,7}; to const A a={5,6,7}. You'll probably use some extra flash
routine to write to this const data and know better than I about it ;-)
I know this is not consistent at some point: The parameters are const
for SW. The const prefix saves me from changing some parameters
accidently in my code. There is only 1 situation where the parameters
is changed:
Right after startup the flash is checked for valid parameter set and if
one was found it is loaded into the memory section where the SW
parameters reside.
My "copy back and forth" was related to some tests I did. This is not
operational.
Now, based on the new requirements, I think that your and Goran's
proposal is cleaner and the switch from the static members to a static
object is not that big deal.
Greets
Henryk
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| User: "F.J.K." |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 11:19:51 AM |
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Henryk wrote:
Now, based on the new requirements, I think that your and Goran's
proposal is cleaner and the switch from the static members to a static
object is not that big deal.
Just out of interest. What _exactly_ do you think, the static attribute
is doing to help you? I think the only thing it does is stopping you to
see the trivial solution, id est having a global variable with the
preference data. ;-)
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| User: "David Harmon" |
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| Title: Re: Memory layout of a class with only static members? |
12 Sep 2006 02:10:37 PM |
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On 12 Sep 2006 05:28:05 -0700 in comp.lang.c++, "Henryk"
<henryk.mueller@gmx.de> wrote,
Const variables are ROMable and as far as I know the compiler *should*
not replace the references by the actual values. That was one of the
the reason we used this approach. We can change the value on one memory
location. I checked the executable file before and this compiler (GCC
for PowerPC) does not optimize away my const parameters.
But you asked "Does it now work only by accident or is this
guarantied?" The answer as far as the c++ standard is concerned is,
not only is it not guaranteed, but much less is guaranteed that you
seem to be supposing. Anything about const variables being ROMable
is outside those guarantees.
If you are looking for a solution that has some basis in guarantees
made by the language, then I would be proposing something along the
lines of:
1. Abandon static members. They offer just about nothing in the way
of guarantees about layout in memory.
2. Create your variables as members (not static members) of a POD
struct. That's just about the only thing that comes close to any
guarantee about layout in memory.
3. Use a const instance of the struct for initialization. Something
of the form below should *I hope* be ROMable:
static const Params initial_params = { 1, 2, 3 };
4. Use a non-const instance for the copy in RAM. Then you are
indeed guaranteed that it has the same POD layout as the ROM and can
be copied right over.
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