| Topic: |
DEVELOP > c-Plus-Plus |
| User: |
"Milk" |
| Date: |
13 Apr 2004 08:31:02 AM |
| Object: |
Question again? |
HI,
i try to read my HEX file, but i dunno why i just can read the first one in
my file ?
anyone can help me?
My code:
char c[5000000];
char d[5000000];
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
if (ifs)
{
ifs >> c;
if
{
cout<< c <<endl;
}
else
{
cout <<"no file"<<endl;
}
~ Let us linux ~
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.
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| User: "John Harrison" |
|
| Title: Re: Question again? |
13 Apr 2004 10:56:33 AM |
|
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"Milk" <milkmilk776@hotmail.com> wrote in message
news:407cbe86@lungfunggdn.org...
HI,
i try to read my HEX file, but i dunno why i just can read the first one
in
my file ?
anyone can help me?
My code:
char c[5000000];
char d[5000000];
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
We had this question fairly recently, try this
ifs.open("opcode.txt",ios::binary|ios::input);
If that fixes it then its a bug in your implementation of the standard
library.
john
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| User: "John Harrison" |
|
| Title: Re: Question again? |
13 Apr 2004 11:10:41 AM |
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ifs.open("opcode.txt",ios::binary|ios::input);
Sorry,
ifs.open("opcode.txt",ios::binary|ios::in);
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| User: "Christopher Benson-Manica" |
|
| Title: Re: Question again? |
13 Apr 2004 09:23:24 AM |
|
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Milk <milkmilk776@hotmail.com> spoke thus:
i try to read my HEX file, but i dunno why i just can read the first one in
my file ?
anyone can help me?
Possibly, if you phrased your question better... I'll add to what was
already posted, however.
char c[5000000];
char d[5000000];
1) What if your implementation doesn't like two 5 megabyte stack
buffers? Many implementations don't.
2) You want unsigned char; unadorned chars may or may not be signed,
and signed chars may not get along with binary data.
--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.
.
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| User: "Karl Heinz Buchegger" |
|
| Title: Re: Question again? |
13 Apr 2004 01:02:56 PM |
|
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Milk wrote:
HI,
i try to read my HEX file, but i dunno why i just can read the first one in
my file ?
anyone can help me?
My code:
char c[5000000];
char d[5000000];
That's not a good idea if you are dealing with truely binary data.
unsigned char is the way to go.
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
if (ifs)
{
ifs >> c;
Since you are trying to read binary data, operator >> is not what
you want to use. Use the streams read function as in:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
string FileName;
unsigned char c;
cout << "Enter filename: ";
cin >> FileName;
ifstream InFile( FileName.c_str(), ios::binary );
if( InFile ) {
while( InFile.read( (char*)&c, 1 ) )
cout << hex << (unsigned int)c << ' ';
}
return 0;
}
Good luck to your project.
--
Karl Heinz Buchegger
kbuchegg@gascad.at
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| User: "Bill Seurer" |
|
| Title: Re: Question again? |
13 Apr 2004 08:41:39 AM |
|
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Milk wrote:
HI,
i try to read my HEX file, but i dunno why i just can read the first one in
my file ?
Read the first one what?
char c[5000000];
char d[5000000];
What happens if your file is 5 million characters long? You shouldn't
code things like this as constants. You don't use "d" in your code below.
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
if (ifs)
{
ifs >> c;
if
What is this "if" supposed to do?
{
cout<< c <<endl;
Does your file actually contain displayable characters? If not, what do
you think this will do?
}
else
{
cout <<"no file"<<endl;
}
Count your { and }. The numbers should match. Your main says it
returns an "int" so where's your return statement?
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| User: "Milk" |
|
| Title: Re: Question again? |
13 Apr 2004 11:49:27 AM |
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i would like to make my program know the HEX in my input file, for example
(0x27a50004(in hex) = addu $s1, $s2, $s3)
then my program read it know 0x27a50004 after that the program will add it
for me and i need to store the s1 value register in my other array.
therefore later i can call it back and add s1 +s2 something like that~
i just dunno why if i don't have char d[5000000]; this array i just can read
the first line ~
if i have char d[5000000]; i can read second line, so did any one can teach
me??
thanks a lot
My code::
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
char c[5000000];
char d[5000000];
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
if (ifs)
{
ifs >> c;
ifs >> d;
ifs.close();
}
else
{
cout <<"no file"<<endl;
}
cout << c << endl;
cout << d << endl;
return 0;
}
"Milk" <milkmilk776@hotmail.com> ¼¶¼g©ó¶l¥ó·s»D:407cbe86@lungfunggdn.org...
HI,
i try to read my HEX file, but i dunno why i just can read the first one
in
my file ?
anyone can help me?
My code:
char c[5000000];
char d[5000000];
int main()
{
ifstream ifs;
ifs.open("opcode.txt",ios::binary);
if (ifs)
{
ifs >> c;
if
{
cout<< c <<endl;
}
else
{
cout <<"no file"<<endl;
}
~ Let us linux ~
~ Let us linux ~
-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----
.
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| User: "John Harrison" |
|
| Title: Re: Question again? |
14 Apr 2004 05:22:01 AM |
|
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"Milk" <milkmilk776@hotmail.com> wrote in message
news:407ced07@lungfunggdn.org...
i would like to make my program know the HEX in my input file, for
example
(0x27a50004(in hex) = addu $s1, $s2, $s3)
You need to use read not >>.
long opcode;
ifs.read((char*)&opcode, sizeof opcode);
is for text only, not hex.
john
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