Thanks, worked great!

On 23 Nov 2003 06:54:37 GMT, Gianni Mariani wrote:

Hakan wrote:

I have an API call I need to pass a void* to to be filled by the API call --
since I want to return a std::string from the function I wrapped around the
API call I was hoping I could pass the std::string, one way or another, to
the API call. Well, neither operator[], nor, of course, data() are useable
for this. Perusing the documentation in Josutti's excellent book I find no
candidate function or operator -- is that correct or have I missed something?

If none exist I have to work around it by getting the length of the buffer
area needed, allocate a character array of that size, read the data,
construct a std::string from the buffer area and finally deallocate the
character array...

You give us little to go on.

Here is one idea.


#include <string>
#include <cassert>

void BustedApi( void *, int * length );

int const MAXIMUM_SIZE = 1024;

void MyWrapper( std::string & fill_me_in )
{

fill_me_in.resize( MAXIMUM_SIZE );

int length;

BustedApi( static_cast<void *>( &(fill_me_in[0]) ), & length );

assert( length <= MAXIMUM_SIZE );

fill_me_in.resize( length );

}