| Topic: |
DEVELOP > c-Plus-Plus |
| User: |
"" |
| Date: |
04 Jan 2008 05:46:53 AM |
| Object: |
upcasting in vector |
Hello, I have the following code.
#include <vector>
#include <iostream>
class Foo {
public:
Foo(){}
virtual void print() const { std::cout << "foo" << std::endl;}
};
class Boo:public Foo {
public:
Boo():Foo(){}
virtual void print() const { std::cout << "boo" << std::endl;}
};
int main(void) {
std::vector< Foo > vec;
Foo ff;
Boo bb;
vec.push_back(ff);
vec.push_back(bb);
std::vector< Foo >::iterator Ivec = vec.begin();
while(Ivec != vec.end()){
(*Ivec++).print();
}
std::cout << "===========" << std::endl;
std::vector< Foo* > vec2;
vec2.push_back(&ff);
vec2.push_back(&bb);
std::vector< Foo* >::iterator Ivec2 = vec2.begin();
while(Ivec2 != vec2.end()){
(*Ivec2++)->print();
}
return 0;
};
the output is:
foo
foo
===========
foo
boo
so when I create a vector of pointers to Foo, the upcasting of print()
works fine, but it does not for a vector of Foo.
Could you, please, tell me what am I missing here?
Thank you very much for help and your time
m
.
|
|
| User: "Jim Langston" |
|
| Title: Re: upcasting in vector |
04 Jan 2008 06:15:45 AM |
|
|
wrote:
Hello, I have the following code.
#include <vector>
#include <iostream>
class Foo {
public:
Foo(){}
virtual void print() const { std::cout << "foo" << std::endl;}
};
class Boo:public Foo {
public:
Boo():Foo(){}
virtual void print() const { std::cout << "boo" << std::endl;}
};
int main(void) {
std::vector< Foo > vec;
Foo ff;
Boo bb;
vec.push_back(ff);
vec.push_back(bb);
std::vector< Foo >::iterator Ivec = vec.begin();
while(Ivec != vec.end()){
(*Ivec++).print();
}
std::cout << "===========" << std::endl;
std::vector< Foo* > vec2;
vec2.push_back(&ff);
vec2.push_back(&bb);
std::vector< Foo* >::iterator Ivec2 = vec2.begin();
while(Ivec2 != vec2.end()){
(*Ivec2++)->print();
}
return 0;
};
the output is:
foo
foo
===========
foo
boo
so when I create a vector of pointers to Foo, the upcasting of print()
works fine, but it does not for a vector of Foo.
Could you, please, tell me what am I missing here?
Thank you very much for help and your time
Slicing. In your vec you are storing Foo. When you push_back it is dony by
copy, so your Boo is copied to a Foo. Only the Foo part of Boo is taken.
So your vec contains instances of Foo with none of the Bar part.
Polymorphism is done by pointers. In your vec2 you are pushing pointers,
the pointer values are copied, the isntances of Foo and Boo are left alone,
they never get copied or changed.
--
Jim Langston
tazmaster@rocketmail.com
.
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|
| User: "" |
|
| Title: Re: upcasting in vector |
04 Jan 2008 06:22:19 AM |
|
|
ok, thank you for explanation
m
.
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|
| User: "Ron Natalie" |
|
| Title: Re: upcasting in vector |
04 Jan 2008 07:02:19 AM |
|
|
wrote:
so when I create a vector of pointers to Foo, the upcasting of print()
works fine, but it does not for a vector of Foo.
Let me make it simpler, without vectors.
Boo b;
Foo f;
f = b;
f is of type "Foo" not "Boo", the Foo part of the Boo b has
been "sliced" and assigned into f.
f is and will remain of type foo regardless of whether it is
initialized or assigned from a Boo object.
vector<Foo> is the same way. You are copying Foo parts of the
Boo object to Foo objects when you insert them into this vector.
Vector does all of it's insertion (and internal maintenance) with
combinations of the copy-assignment operator and copy constructor
(a requirement of any object you wish to store within is that these
functions can faithfully copy the object).
.
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| User: "" |
|
| Title: Re: upcasting in vector |
04 Jan 2008 06:15:23 AM |
|
|
vec.push_back(bb);
This makes a copy of the Foo subobject in bb. Polymorphic behaviour is
obtained through pointers or references to base objects.
.
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